Fresnels Equations at an Angle

[@meetoptics]

Congratulations for being able of introducing this technology to society through these videos. This platform let us spread all we know about the field and from MEETOPTICS we are proud to be part of the photonics community and to help engineers and researchers in their search for optical lenses through our site. We celebrate every step forward.

[@eastofthegreenline3324]

This series is great and I often return to it to refresh my memory. One thing I didn't notice first time was at 10:36 you refer to the plane of the blackboard as the "plane of incidence." Hecht (Optics) likewise. It is the plane in which we see the angle of incidence but I am wondering if the term originally referred to the plane to which k is normal? After all the light is incident along k...At any rate your video clarified this. Tks!

[@ankusingh1954]

What a great explanation. Thank you so much sir 🙏🙏😍😍

[@alihussein1005]

Wonderful Explanation! Thx a lot

[@adiazdu]

Awsome! Your videos are so helful for me :) thanks.

[@meetoptics]

They are for sure!

[@matheshvaithiyanathan3372]

It's short and sweet.

[@meetoptics]

So good. Completely agreed 🚀

[@adiazdu]

I have a question. What happens if the interface that I am interested to study has some charge density (so changing the boundary conditions)... can I (for some reason) still apply the Fresnel’s equations derived here? Regarding that my boundary conditions are going to be different.

[@JordanEdmundsEECS]

No, you will have to include the charge density term in the derivation of Fresnel’s equations, so they would be different. You can definitely do it though, it’s just r and t will be different.

[@adiazdu]

Thanks

[@adiazdu]

Actually, when looking at this problem, I just realised that my boundary conditions are going to change for the electric field normal to the surface, and when deriving the Fresnel’s equations we only use the tangential electric field, so, taking it into account, the Fresnel’s equations are going to be the same, is that right?

[@meetoptics]

@@adiazdu it is great, true! Thanks again

[@vegardnybakeri8148]

Wow this is great!

[@meetoptics]

It is amazing, sure!

[@yimmakofa7020]

How do we derive an expression for reflectance as a function of angle of incidence for thin film coating? Thanks

[@mytrusmars]

Great 👍

[@varkush399]

proof of me paid attention in your video; you write '2' bottoms up