Lec 07 Important Question Discussion on Symmetrical Fault Part III

[@parthchavda7549]

Sir ..... Maine Kal se aapki power system ki series suru ki hai....bahot hi Maja aa Raha hai....sir... Aisa lagta hai ki aapne power system k chhakke chhuda diye ho...... awesome sir

[@subodhsingh4878]

sir , in the last question since we have transformers in between of motor and generator which will step down the base voltage for motor hence the p.u impedance of motor will be multiplied by factor of MVA ratio only giving ans 1.44 pu.

[@pavankumargujjala]

thankyou so much for this beautiful series,learned many new things.

[@9873502528]

sir in last question, if we convert resistance in actual value then shift using transforming ratio toward generator from load, and then convert in per-unit. i must get answer as you found, but i didn't (my answer is 1.44). i know my method is lengthy but still both answer must be same even i follow different steps. i checked myself twice please sir correct me.

[@someshthakur4084]

Right. P.u values are not affected by transformer voltage. Only mva affects it

[@surendrakverma555]

Excellent. Thanks Sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@rupambhattacharyya780]

Sir in lecture 7 to calculate subtransient current we have to calculate subtransient emf not steady state emf

[@deepakchauhan6215]

Thank you sir for the concept of MVA method.

[@aishwaryabhagat1333]

Very beautiful series.Thanku sir

[@ayushranjan7840]

Sir made Easy me btaya gya ki subtransient fault calculation ke lie prefault subtransient induced emf calculate krna h.. Aur transient fault ke lie pre fault transient induced emf nikalna h.. Aur sustained fault ke lie pre fault xd leke emf find krna h

[@krantiveersingh12]

but bhai pefault condition me subtransient reactance hota hai kya?

[@rupambhattacharyya780]

Yes you r right

[@prabhatsrivastav9862]

Sir 2001 wale question me man lijiye Subtransient ka chakar nhi hota to kya 1 ohm wale resistance ko per unit me change nhi krege... Isko bhi to per unit me change krna pdega.. 🙏

[@amankumaaryadava1627]

Ye confution mera bhi h.

[@rishikesh7671]

Sir you wrong you put resistance value in ohm why it should be used in p.u

[@boombeachnoob3642]

Sir........in that problem where thevenin is not applicable you said, You took resistance of load as 1 ohm and calculated fault current value but you should take it in PU, 1 ohm * 500mva / 20 kv = 1.5 PU isnt it sir ? I=V/R I=20K/1 ohm = 20Kamps I pu= I actual* root 3 * 20kv /MVA........... I pu = 1.384 so, if we calculate PU current it will be 1.384 pu of load current and add it with generator current 5 pu both will give 6.384, CLOSER TO ACTUAL 6.4....... YOUR METHOD IS CURRECT BUT HOW Im GETTING RIGHT ANSWER SIR............PLEASE EXPLAIN ME SIR......

[@amankumaaryadava1627]

Thevenin ko valid krne ke liye age hm dono reactance same lenge to us concept ka kya hoga jisse hm kahte h ki steady state reactance is always greater than sub transient .

[@gayatrirajak9008]

Sir aapne gate 2001 wale ques me fault current 6.4 pu nikale hain but correct ans given by iit is 5.05pu Ans 6.4pu is not in ans

[@VijayPatel-fe3gr]

Sir resistance ko ohm me liya gaya hai instead of pu

[@manisawhney1882]

Sir, 1st question mein aap jab Eg calculate kar rhe the prior to fault, tab aap load ki p.u. resistance value , 5/4 pu consider karna reh gye

[@techspecialinformation7746]

at 21:58 you made the mistake. you take j0.2 in pu and value of resistance 1ohm , take both impedance in pu thevenin will be applicable here ..... Please comment I'm right or wrong

[@sonubishwas5300]

Yes bro. m sure please check it out

[@hrithiksamala1729]

In first problem, while calculating Eg you have considered the fault. Then, instead of taking Xd'' why you took Xd ?

[@someshthakur4084]

Pre-fault condition is steady state condition so obviously you'll consider steady state reactance Xd. When fault occurs, the initial reactance is subtransient reactance so that one is considered. If the question had said that it is a sustained fault then we would have taken Xd not Xd" to calculate short circuit current.

[@electrical_shekhi3242]

Good work

[@KuldeepRana13]

Sir ans given is 5.05 p.u please check the first method at 5:12

[@mohdaqib784]

Can you explain how?

[@KuldeepRana13]

@@mohdaqib784 according to gate book solution if we are dealing with initial value of current then we need to take sub transient voltage

[@GeniqueEducationTeam]

whatever i explained is correct...ok

[@KuldeepRana13]

@@GeniqueEducationTeam thank you sir

[@souvikbera5845]

it may happen that the author of the book you are referring also did by the second method and did not consider the condition of superposition and printed the result as calculated by this method.

[@UEEBchaitanyasaipriya]

MVA method❤

[@balkrishnasharma5076]

Sir in gate 2001 Option given is (a) 7.22 (b) 5.02 (c) 3.22 (d) 2.25 But our ans is coming 6.4pu of initial rms current So how we mark the right tick@ Genique education

[@GeniqueEducationTeam]

in different book ..option is different..so consider what i said..

[@vlogsbyabhinav5598]

Sir if we use j0.2 to calculate Eg" then answer is 5.05 .. can we do so ?

[@ManOrDestinyKRR]

Resistance was not converted in per unit value,why sir 11:47

[@sonubishwas5300]

On converting the resistance value in pu ibgot 6.25 as answer

[@ManOrDestinyKRR]

Ok thanks but sir has taught us these concepts so nicely. The way discuss the solution to the questions taking every angle/point is awesome

[@sonubishwas5300]

Yes no doubt it is outstanding teaching by sohail sir...

[@ManOrDestinyKRR]

Thank you so much Sohail sir

[@mrduryodhan4103]

But in gate 5.05 is actually im made easy booklet

[@DXFact.]

Sir ur lecture ar very helpful

[@aryannishad316]

best sir ji

[@udaymehta8917]

THANK YOU VERY MUCH SIR ...

[@momenulislam8567]

Sir thank you.. I admire you and especially your techniques are just extraordinary.. It would be a great help sir if you please discuss the IIT Bombay 1999 question of symmetrical fault.. please sir.. please....

[@GeniqueEducationTeam]

mail ur question to [e-mail] including your mobile number

[@namratasethia2439]

Me

[@mauryashivom7984]

thanks sir suggest for this type of mistake when reactance is not constant

[@debjyotipalit78]

Sir in question 1 passive load kaise current deliver karega???

[@RaviRaj-fy6bd]

ans is 5.05

[@TheShubhransu]

Sir , while attaching opposite polarity voltage why we are considering sub transient reactance, as it is not the condition after fault???

[@rahularya4705]

Very nice sirji

[@swathikadiyala9681]

Sir .What if there are many busses how can we use thevinins method

[@surajrawat9645]

thanks a lot

[@Happyfacesss]

Sir qno-1 me answer 5.09 Pu hai 6.4PU wrong answer hai.

[@akhileshpatel2322]

Nice sir...

[@mohitsaini4078]

sir first question ka answer galat aa rha hai it is out of options please check options

[@rahulsinghthakur420]

sir why resistance is not converted into pu

[@Elite_Engineer]

sir during thevenin theorem concept if during fault ckt if i take xd as -0.8j tab toh add karni karne par after fault j0.2 aa jayaga is that also wrong.

[@GeniqueEducationTeam]

tell me the time at which you are getting prblm

[@Elite_Engineer]

@@GeniqueEducationTeam sir at 14:54 when u said reactance dono ki across same hota toh koi dikkat nhi thi becoz at transient hume same milta but hum us reactance ki value ko - 0.8 lele taki after fault 0.2 aa jae

[@Elite_Engineer]

Is it possible

[@mrduryodhan4103]

But sir what ever we got through thevinens concept answer that is match with gate 2001 solutions 5.05 not 6.4 in made easy previous year practice book !???? 😭

[@harshdwivedi619]

There is no option of 6.4 in gate 2001 original question.

[@amarreddysurapureddy8614]

Don't use thevenins theorm

[@naziyabano4911]

Thank u sir

[@mubarakhussain7560]

Are you preparing for GATE/ESE??

[@MohammadAsif-zp8px]

Sir I haven't found this question in previous year booklet......can can you kindly provide me the reference of question......

[@AK-2020]

Keep checking properly. I found all the questions.

[@swtghs]

One level up #genique

[@vijetayadav123]

🙏

[@kanthakborkar710]

👍

[@sonubishwas5300]

Sir in thevenine equivalent on converting resistance into pu i got 6.25 pu is this not close to answer because you haven't consider R as pu please.... clear the doubt sir..

[@souvikbera5845]

what is the value of load resistance you got in pu??

[@sonubishwas5300]

0.8

[@souvikbera5845]

@@sonubishwas5300now using this value are you sure your answer is 6.25 pu.Please check!!

[@sasmitapraharaj4565]

Sir r should be converted to pu?

[@GeniqueEducationTeam]

yes u are correct..

[@amarreddysurapureddy8614]

Tell me shortly not in depty. It's too lengthy process

[@Mimi_mehendi]

Sir pls suggest me PS book for theory

[@moumitamondal5188]

🙏🙏🙏🙏

[@Ghumantu_jha]

Sir short circuit fault on transmission line ,(like momentary current ) wala part cover hoga ..?

[@manojrana6782]

please anybody tell me how angle 36.85 is calculated

[@krantiveersingh12]

eg=1angle 0+0.8angle 90 eg=1+j0.8 change this in polar form and you will get the answer

[@divyanshu1210]

🙏🙏🙏🙏🙏❤❤🙏

[@RishiKumar-wf9nh]

In last question it will be 3.6 not 36!

[@TheAlgoTrader17]

Solve again

[@HARSHVARDHAN-ol4ib]

Sir it is a humbly request to you pls upload electrical machine pls sir.... I am waiting for this subject because in this subject alot of problems........ I hope this subject video will come soon ...... Pls sir .....