Germany| A Nice Math Olympiad exponential question| Can you solve for x?

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JJ ONLINE MATHS CLASS

JJ ONLINE MATHS CLASS

29 күн бұрын

This is a math Olympiad exponential question involving algebraic identity and laws of indices #matholympiadproblem #exponentialequations #olympiadmathematics #logarithm

Пікірлер: 26
@jmich7
@jmich7 23 күн бұрын
And your expressions are so funny, SUPER COOL!
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 23 күн бұрын
Thank you
@marcgriselhubert3915
@marcgriselhubert3915 27 күн бұрын
1/3 is evident solution, so we can fctorize: x^3 + x^2 -4/9 = (x - 1/3).(x^2 +(4/3).x +(4/9)) = (x -1/3). (x + 2/3)^2. So the given equation has two solutions: 1/3 (simple solution) and -2/3 (double solution).
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 27 күн бұрын
🤝🤝
@soumayahatchi4168
@soumayahatchi4168 27 күн бұрын
Love you too darling . Thank you for teaching us a smart and easy way of solving math problems
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 27 күн бұрын
U are welcome
@Rich-Man820
@Rich-Man820 7 күн бұрын
Wonderful
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 6 күн бұрын
Thanks
@prime423
@prime423 25 күн бұрын
Look at the original equation!!Its clear 1/3 is a root. Then use synthetic division. Simple,with very little angst. Simple is always better!!
@shahidrasul9580
@shahidrasul9580 27 күн бұрын
your methods are very Smart ❤
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 27 күн бұрын
Thanks so much
@RyanLewis-Johnson-wq6xs
@RyanLewis-Johnson-wq6xs 27 күн бұрын
(0.3/0.9)^3+(0.3/0.9)^2=0.148/0.999=4/27 (-0.6/0.9)^3+(-0.6/0.9)^2=0.148/0.999=4/27 x=0.3 recurring or 1/3 x=-0.6 recurring or -2/3
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 27 күн бұрын
👏👏👏
@pukulu
@pukulu 27 күн бұрын
x = 1/3 by inspection but there are also a couple of other roots.
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 27 күн бұрын
Nice guess
@LifnaCabi
@LifnaCabi 27 күн бұрын
Muito inteligente,mae, fantastica didatica!Guine-Bissau. Traduzir em ingles.​@@JJONLINEMATHSCLASSchannel
@johnstanley5692
@johnstanley5692 25 күн бұрын
given x^2*(x+1) = 4/27 = (2/3)^2 * (1/3) = (2/3)^2 * (1-(2/3)) => (3*x+2)|g(x), where g(x)=x^2 * (x+1) - 4/27 (=0). dividing g(x) / (3*x+2) = (1/27) * (9x + 3 *x - 2) => g(x)=(1/27)*(3*x + 2) * (3*x + 2) * (3*x - 1)=0 => x={ -(2/3), - (2/3), (1/3) }
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 25 күн бұрын
🤝🤝
@elmoussadekelaoufir144
@elmoussadekelaoufir144 27 күн бұрын
Sorry you can solve with more easily you can separate 4 from 1 and 3.....
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 27 күн бұрын
Ok. Please drop the method. Thanks
@fernandoarielgarcia5498
@fernandoarielgarcia5498 27 күн бұрын
You are a super smart girl💖😘😘🥇
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 27 күн бұрын
Thank you
@elmoussadekelaoufir144
@elmoussadekelaoufir144 27 күн бұрын
I solved this equation in 3 minutes
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 27 күн бұрын
🤝🤝
@jeankouassi5897
@jeankouassi5897 23 күн бұрын
I like your smile.
@JJONLINEMATHSCLASSchannel
@JJONLINEMATHSCLASSchannel 23 күн бұрын
Thanks
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