Graphing a rational function with a slant asymptote

[@googleuser1937]

One of the best teachers out there on the internet.

[@7elas241]

I don't speak English very well but I understand your explain thank you

[@mussienewaymitiku3792]

its simple and easy ways of explanation and i am satisfy thank you so much!!!

[@TheMissAlira]

Thank you so much for this example I just tried to understand similar, it helped!

[@brianmclogan]

you are very welcome!

[@onethkahandawa1909]

Perfect👍🏻

[@jaia846]

What if you have 1/3x -1/3 as your slant ..do you start at -1/3

[@brianmclogan]

that would be the y-intercept, yes

[@jaia846]

Thanks sooo much 👍🏾

[@brianmclogan]

you are very welcome!

[@segayanmx4442]

Sir, why you don't calculate the derivative of the function to study the overall curve of the function? I've seen many videos of yours ,but in these you avoid to calculate !

[@maricarcruz7556]

I just notice that getting the x intercept is like getting the Vertical asymptote but instead of getting the zero of denominator we will use the numerator🤔🤔 to get x-int?

[@angelmendez-rivera351]

Yes, that is fact what it is. The vertical asymptote of the numerator is the zero of the denominator, and vice versa.

[@tohidalamkhan4081]

Tq sir

[@irwandasaputra9315]

2x+x^-1