Griffiths Electrodynamics Problem 2.21: Electric Potential Inside and Outside Sphere-Uniform Charge

[@adetayoeyelade7924]

Jordan Bell you are incredible with your solutions....I cant get a better solution than what you are giving out. Thanks for building confidence in me.

[@AmmarAbdurrauf]

I could not believe that this video was 8 years ago, yet very clear in explaining.

[@vinfinity8940]

I couldn't find legit solutions to this problem the text doesn't give info about the electric field inside the solid sphere. I was a lot confused with this problem and I tried to compare it with the spherical shell one which would only work for the inside of the sphere. I just felt really dumb for not being able to solve this. Thank you for the video, it's a bit long but it starts right where I want it from. Making mistakes is ok because it makes the viewers aware of not repeating the same errors.

[@cNeverHide]

I think you made a mistake for inside potential. It is the integral of E out from infinity to R (and not from infinity to r) minus integral of E in from R to r, so at the and you have Vin = (q/8pi epsilon R^3) * (3R² - r²). Otherwise, it is a really well explained video thank you :)

[@vennela7430]

you just took the pain out of me, I was not knowing how to calculate the inside E,

[@johnnybatafljeska6368]

For a potential inside..why arent we intergrating from R to 0 ? whats the point in using the limits from R to r?? Shouldnt potential be a constant value inside the sphere?

[@shakeelkhan-bq5yi]

sir problem 2.22 nahe website may

[@SpencerG82]

Papa Bless

[@preethiovn]

Sir pls speak loudly!!

[@physicsboy3108]

Kindly sir Speak loudly

[@rasheedataliep5757]

this man whispering

[@nymeriafrost7687]

30 minutes are you kidding me? This video can be twice as short if you would cut the pauses and get straight to the point