How to get electric field from electric potential

[@yuanxiang1979]

Thank you so much! My professor have never taught us about gradient and expected us to just know what it means out of thin air. This is a life saver!

[@yoprofmatt]

Ahhh yes, the professor's expecting you to know everything. I've probably made that mistake a few times. Glad to be of help. Cheers, Dr. A

[@yuval260990]

There are so many "professors" out there that don't deserve to called one

[@cjterhark251]

Clear and concise. I like that you clarified what the gradient is and what it does. Helped me a lot. Thanks!

[@yoprofmatt]

You are very welcome. Keep up with the physics. Cheers, Dr. A

[@danijelumicevic3213]

You just made my day, now I can go to sleep because I found a guy with decent explenation

[@yoprofmatt]

Thanks. That's definitely one of my goals: to help people fall asleep. Cheers, Dr. A

[@stephanm.tjaden3887]

This was very, very helpful. I have been struggling to no end on this because the book poorly explains it. This explanation is perfect and very clear cut, and easy to understand.

[@zachgreenwood2]

For those of you looking for bare bones answer to this question. Just take the negative gradient of your electrical potential equation, that is take the derivative of the equation with respect to x, then y of the original, and then z of the original and assign x hat, y hat, and z hat respectively.

[@JustinDBKidrauhl]

You sir are an angel fallen from above. Crazy how I love physics when I'm being taught by KZbin professors :)

[@yoprofmatt]

Falling, yes. Angel, not so much. But I appreciate the high praise. Cheers, Dr. A

[@jamesbedortha11]

good video, help me understand what's going on in my physics class

[@MikeHawk-s2g]

Thank you so much! I was really scared of those partial derivatives until now!

[@jessicaquemado1527]

I got stuck in studying this in my book, I did not know how this equation was derived: E = -dV/dr until I decided to search the internet and found your video hahahahaha thank you so much Dr.

[@ashewood3918]

kinda random but the way he wipes the markers off when they're not dry yet is frqn mesmerizing

[@yoprofmatt]

Mesmerizing is good. I'll take it. Cheers, Dr. A

[@kosmos2065]

Thank you so much sir , tommorow is my physics test , your videos helped me a lot.

[@ronnieli8990]

Saify 2807 good luck!

[@Daniela-iz7ec]

Sir thank you so much !!!! You just made my life so much easier and happier !!! Thank you !!!!

[@yoprofmatt]

Happier as well? Bonus. Cheers, Dr. A

[@ownalicous1]

how does he write backwards so smooth

[@yoprofmatt]

He doesn't. Secrets here: www.learning.glass Cheers, Dr. A

[@apk2626]

@@yoprofmatt i used to think you were left handed until TODAY LOL

[@ethioupdatedinfo.]

Thank you very much professor Anderson 🙏you are really help me a lot.

[@RustinKabiri]

Love your vids, appreciate them

[@jahansaid6382]

Thank you very much, It was so much helpful, you opened my mind :)

[@Ahtohallanldra]

Very helpful, thank you sir

[@omansmamdoh8861]

Thank you very much 💕💕 from Egypt

[@yoprofmatt]

Hello Egypt! Great to hear from you. Never been there but it's definitely on the bucket list. Cheers, Dr. A

[@muteebitwaliha9862]

You are a good teacher

[@s.7ps]

From Abdullah Yousef

[@wandererv3557]

Thank you. Very nice teaching 👌.

[@yoprofmatt]

Cuts & Music, You're very welcome. Glad you're enjoying the videos. You might also like my new site: www.universityphysics.education Cheers, Dr. A

[@surendrakverma555]

Excellent lecture.

[@yoprofmatt]

Surendra kumar verma, Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A

[@kabandajamir9844]

So nice thanks sir

[@yoprofmatt]

Most welcome Cheers, Dr. A

[@yasir.3486]

Hello prof, hope hale and hearty during this quarantine Cheers, Yasir

[@yoprofmatt]

Yasir., Thanks, we're doing okay out here in California. A bit of cabin fever, but reaching out to my Fandersons sure helps. You might also like my new website: www.universityphysics.education Cheers, Dr. A

[@lancepit8161]

Thank you so much! 🙂

[@davemcintosh3359]

Thanks. Slightly confused by why the absolute value of the potential due to the charged sheet is proportional to z. Wouldn't it reduce with greater displacement from the sheet? i.e. wouldn't it be proportional to 1/z, in the same way as potential due to a point charge is proportional to 1/r?

[@bhahubaliashish9853]

Why don't you upload videos for quantum mechanics...😄😄 You are just awesome 😍😍

[@ahmedzekii8883]

thank you for aver i now understand physics

[@karinaballesteros1991]

such a perfect video! thank you!

[@yoprofmatt]

Thank you for the post. Keep up with the physics. Cheers, Dr. A

[@Allfay]

what a great teacher

[@stonerazad3359]

#YouAreLoveProfessor❤ #LoadsOfLoveFromIndia💜

[@yoprofmatt]

Thanks! Feeling the love. Back at ya, Dr. A

[@shalomfadullon8983]

great video, but couldnt pay attention because i was distracted by the fact that HE HAS TO write everything BACKWARDS???? or flip it??? mind blown. he is so good

[@yoprofmatt]

shalom fadullon, Not writing backwards (I'm not that talented). The board is called Learning Glass. You can check it out at www.learning.glass Cheers, Dr. A

[@maloucalda1194]

Is this the same with electric field as potential gradient?

[@seannibecker5500]

are you drawing everying in reverse? cant figure it out

[@shubhamghadai9356]

Sir, why have you considered two equipotential surfaces in the second case?

[@yoprofmatt]

Shubham Ghadai, Leading into the parallel plate capacitor example. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A

[@spaghettigal]

Where could I find some harder examples? Thanks in advance!

[@abdullahal-junaibi3656]

okay this is just brilliant

[@yoprofmatt]

Ag AL-JUNAIBI, Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A

[@dhrubajeetbasumatary6130]

Are you writing the words inversely since it is a glass

[@nucspartan321]

thank you so much

[@dmi3904]

thank you!

[@yoprofmatt]

You're welcome. Cheers, Dr. A

[@Lexyvil]

At 5:04, why do you divide V by "r"?

[@senatunca7778]

then the formula will be equal to E

[@jessicaquemado1527]

He's trying to get it in the form like that of E

[@xenonx4645]

love

[@yoprofmatt]

Thanks. Have a great day. Cheers, Dr. A

[@sonoma5971]

this guy is so chad

[@faisaltanoli3955]

How do you make these Videos? just Curius to know

[@cjterhark251]

Probably behind a glass window, and then flipping the video during the edit process, if you're wondering about the direction of the writing.

[@Aryankumar-hm8qw]

CJTerhark thnx ....i wanted to know abt this too....

[@_akhil_17]

On comments just simply . Wow😳😲😮😮

[@Dr.guy.]

Me, not an intellectual: using this video to fall asleep

[@interhaker]

tzt kay?

[@painsongs2081]

I Indian student

[@Realistic_clips]

Who is INDIAN here ❤🇮🇳

[@olxzender]

Is this Physics or Mathematics, or is it symply an event of voicing formulas that one can simply look in the books? Does anyone wonder how these equations came into being? ..."epsilon nought" "arrhh to the minus two" ""some constant sigma", seriously, is this an explanation, or just dictation? Good Sir, you are not a professor, but a student at an exam. I doubt you yourself understand what you teaching. Reading the zeroes and the ones as values off of a compact disc doesn't generate music in my ears. Kudos to those for whom it does.

[@ktsatyajit]

You cant get an expression for V without knowing how E is related to V !!! Your argument is circular.

[@yoprofmatt]

Satyajit K. T., You're right, you definitely need to know how E and V are related. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A

[@ktsatyajit]

@@yoprofmatt Dear Matt Anderson, thanks a lot. I shall have a look. I will share my views on how to get the electric field from electric potential shortly. In short, I would think the way would be to start with Force, then define the electric field and show that the curl of the electric field is zero for static charge configurations. Then one can introduce the concept of the potential energy of a system of charges. The work done by "me" on the charges would connect force and the stored potential energy. One would then introduce the concept of Potential as the work done per unit charge. Now that makes the relation between Potential and the work done per unit charge which essentially is V = -Integral (F.ds/Q), where V is the potential and F is the force and ds is the infinitesimal displacement, the minus appears due to the fact that the force and the displacement are in the opposite direction. But F/Q = E, therefore you end up getting V = -Integral (E.ds), note that this path integral on the line is possible because of the fact that in electrostatics the curl of E goes to Zero, as the force is conservative. Best wishes.

[@caleb7799]

clear your throat