I would like to introduce to you a really general but very simple proof for all compound angle formulae with any positive angles a and b, which can be a > b or a < b. The starting formula should be cos (a - b). The unit circle is divided into 2 sectors by the two unit vectors having angles a and b. The length of the chord of the minor sector can be found by distance formula when the coordinates of the unit vectors are derived as x = cos a or b, and y = sin a or b. The reason for choosing cos (a - b) is that the angle between the unit radii forming one of the two sectors of unit circle is (a - b) when a > b, and - (a - b) when a < b, whatever the values of a and b. By rotational transformation about origin, the sector with this angle moves to a new position with original unit radius for angle a lying on the x-axis. The original unit radius for angle b will move to have a new angle = (a - b) or - (a - b). Hence a new set of coordinates for ends of the rotated chord can be established. A second distance equation for the chord length equal to that from the first distance equation can be established. With algebraic manipulation, the formula for cos (a - b) can be proved in the most general way. With this formula proven, other compound angle formulae can be derived by substituting (-b) for b, (90 + a) for a into the proven formula and substituting sin/cos for tan. I would like to call this method equal chords of rotated sectors method.