This is absolutely terrific. I was ready to throw my book out the window when it got to this chapter. Now, it is all beginning to come together. Thank you!
@ayeshashaikh44336 ай бұрын
i love you gang thank you so much, you explained what my professor couldn't
@aga38483 жыл бұрын
I wish my lecturers to be like you...Thank you for the videos!
@ranjusubedi973 жыл бұрын
i just came up to this video, u have explained so well. i wondered ,i just watched your 32 minutes video. Thank u .
@tobiacasadei23633 жыл бұрын
Thanks Joe, clear and useful explanation. Really appreciated how you pointed out where reactants "end up" in the pyridine ring. Keep up with the great work
@bryannavarro40882 жыл бұрын
Your helping me soooo much for Ochem 2 your videos are amazing!!!!
@mohammedhassankorna Жыл бұрын
Amazing teacher and amazing explanation ❤
@jOeCHEM Жыл бұрын
Thank you so much for the kind words and for watching!
@nansupatra43633 жыл бұрын
Thanks a lot. You are a great guy to do it. OMG OMG. It is very hard.
@ricola78643 жыл бұрын
hey Joe, love your work, it helps me a lot! I don't really understand why you protonate your keto-ester in the imine-formation at about 9:20, we are working in a basic environment because of the ammonia, right? it also seems a little unnecessary and complicated as you can write the mechanism without out the protonation just as well.
@jOeCHEM3 жыл бұрын
Hi, Ricola! I had taken this directly from a textbook (Volhardt Organic Chemistry: Structure and Function), but I think you bring up a good point. This is a complex, multistep reaction and in reality protons are being picked up/falling off all the time and very quickly. Of course you can't just introduce acid and base out of thin air, but in this scenario, with so many components, there would be multiple steps where you could introduce acid/introduce the ammonia. If your course differs slightly in how the acid-base steps are executed, please follow what your instructor shows (I'm not your teacher/not giving anyone any grade 🙂). jOeCHEM/this channel will always differ slightly from what an individual student may experience in their class, but if you're carrying out a Hantzsch Pyridine Synthesis the overall approach will be almost the same. Does that make sense?
@shelbysgarage58283 жыл бұрын
If I remember right, when you add your ammonia that closes your block giving you your piperidine/piperdone I think the later. And if you use a different chem(brain not working) your reaction goes right making a completely different out come
@JBry_2 жыл бұрын
Would you not have to partially protonate the -OH even in basic conditions because -OH is a poor leaving group? I'd imagine that's possible at a pH of ~ 8.5. Chem Libre talks about pH ~ 5 for imine formation.
@subainaawan38718 ай бұрын
So helpful thank you so much ❤
@sherdilabdullah9893 жыл бұрын
So the oxidation of dihydropyridine is ideal ( it doesn't have any mechanism)
@omraikar85174 жыл бұрын
Great!! Thank you Sir...would be awesome to have a Hantzsch on pyrrole
@brianmbugua41933 жыл бұрын
If I could I would. ...am back at it again....so I didn't sit 🪑 my exam so I have to do it this time round .....I didn't finish watching the video last cont'd from 18:36.
@mrmrtdy90503 жыл бұрын
Hantazsch for pyrrole please
@zeynepunal15902 жыл бұрын
Okay james franco from 127 hours
@bonbonpony2 жыл бұрын
Didn't know that water can just rip off random hydrogens off of other molecules :q