Heat Transfer (05): Heat diffusion examples, 1D conduction in a plane wall

[@throttlejunky2211]

If only there was a camera guy who could pay attention. otherwise great video

[@nournoman9191]

in the min 16:00 Eg dot = q dot * Area * L , q dot and Area and L are given, plug in the values to get 1000*10*1 = Eg dot, hence the equation is : Est dot= Ein dot + Eg dot - E out dot Est dot = 120 kW+(1000*10*1) - 160 kW Est dot = -30 kW = -30000 W Hope this helps :)

[@abisheikvisagan4630]

Thank you

[@marioleon4102]

I hope that camera operators career goals don't involve operating a camera, because my god man, FOCUS.

[@ramonhppacheco]

@14:40 you shouldn't rule Eg dot out of the equaation. It represents the term q dot *Volume. Having that and Ein dot as q (x=0) and Eout dot as q (x=L), you'll get to the correct answer of -30kW fot Est dot.

[@joaquin9198]

i hope the camera guy is not getting paid with tuition money caz wooow

[@theazndonut1]

The camera guy has one job. Come on man.

[@athanasiosmatrapazis4111]

Thank you so much for the courses! At 15:58 in the Heat Diffusion Equation we get Watts/m^3. We need to multiplie to volume (AxL) to get Watts.

[@ryancrumley8616]

Thanks for posting these videos. They really help me understand what's going on and how heat transfer works.

[@CPPMechEngTutorials]

Our pleasure.

[@sanjitpandey552]

Cameraman god dang it

[@부리부리-u5g]

23:55 Isn't C2 supposed to be T1 not T2?

[@wilfredoteran9314]

yes

[@sametarslan2121]

@@wilfredoteran9314 yes :(

[@itzipocalyspe9396]

@14:40, should Egen be q dot * volume = 10000 W (assuming z=1)? If so then the Est equation would equal -30,000 W

[@jackstratif9988]

Yes, and that’s what the textbook has for example 2.3

[@charlesdlamini8126]

Hi Graph is not visible

[@xplosiveactionarchive9092]

18:09 can someone explain why you can solve for Pc_p dT/dt and how that gets you to the Est = -30,000W?

[@theogreen2186]

So you use the entire diffusion equation like he did before as we solved for those values in the previous part. So from the right hand side you divide over density and c_p and solve for dT/dt, since density and c_p are known. Using this result you can then solve for Est =density*c_p*dT/dt. Hope this helps

[@manuboker1]

Thanks ! Wonderful Heat Transfer lectures !

[@muhammadluqman4117]

sir at 15:14 you got the answer for the Est= 30k W thats not correct we get Est= 40000 if Egen= 0

[@amogneworkie3225]

yah got 40.000 also

[@conchscott9910]

Last video we complained that he was moving to much so now he say I ain’t moving no more then😂

[@CPPMechEngTutorials]

Okay... we'll take down all these free videos. :(

[@choubatsu5860]

@@CPPMechEngTutorials No thank you, I'm going back for my master's degree and going back to school for first time in 10 years. thank you so much for the refresher lol

[@ibrahim4951]

@@CPPMechEngTutorials no need to get sensitive. Its that we as viewers at least expect to see whatever you're recording in the class. not just freeze into one single frame and miss every other frame

[@CPPMechEngTutorials]

@@ibrahim4951 Sarcasm is difficult to transmit in a KZbin comment.

[@이해수-i3d]

@@CPPMechEngTutorials Well screw them ungrateful complainers. I'm just glad I can watch a nice lecture on such a hard subject for free. thanks a bunch for uploading them :)

[@moq4463]

at 15:20 why is it -30,000 watts and not -40,000 watts? Where did that -30000 watts come from?

[@antonventura6364]

same question

[@martinhvik2216]

E_gen should be q_dot * volume, so 1000 W/m^3 * 10m^2 * 1m= +10,000 W, and therefore it's -30,000 instead of -40,000.

[@antonventura6364]

@@martinhvik2216 thank you very much!

[@lauragomez3516]

@@martinhvik2216 but he said E_gen is equal cero, so I am lost again

[@theomnipresent1]

@@lauragomez3516 He said it was zero and crossed it out. When he wrote out his givens @ 7:21 E_gen was given, and he forgot.

[@apple-fs3bm]

Any chance you could share a list of the homework assignments? It would be a game-changer for my prep! Thanks a bunch!

[@dinushachathuranga7657]

Buch of thanks for the amazing explanations❤❤❤

[@clarenceroopnarine6180]

Is it safe to assume that the heat flows normal to the wall surface?

[@sanjitpandey552]

If we want to use the equation for part b, how do we get dT/dt?

[@evaristogabriel8208]

I think you don't, because dT/dt is a component of E(storage)

[@حسينبنعلى-م6ص]

link ok pdf for our text book, please

[@chungkifok6077]

in 18:00 , if I use the right bottom equation, then dotE_st=40*(-100)+1000=-3000W. Why am i not able to get -30,000W?

[@abhijithsuresh880]

Est dot =m cp dT/dt m= rho * vol = rho * 10*1 Just multiply ur answer with volume (10)

[@devadathans5506]

I don't understand the whining about the camera here. To those who are doing that, if you bring your cursor over to the video, two thick, vertical bars will appear to the bottom left called the pause button. If you click on it, the video will freeze at that particular frame and you can take notes. Another way to do that is to press the long key called 'spacebar' on your keyboard. It also pauses the video. Imo, Professor Biddle is the most interesting part of this lecture and it is best to keep him focussed except when he is writing on the board. So, props to the camera man.

[@CPPMechEngTutorials]

Tell me more about this... "cursor"... you speak of. We understand the camerawork could have been better though.

[@ibrahim4951]

seems like someone didn't pay attention to the class just like the camera guy. Our beloved camera man does not even show us the board where the problem is being solved smartass

[@hadideyal9377]

sir you are amazing thank's

[@alidogru7188]

which book do you follow I know çengel's book

[@xplosiveactionarchive9092]

The textbook is "Introduction to Heat Transfer" by Bergman et al.

[@raiyanowaiz487]

What is the camera guy doing?

[@CPPMechEngTutorials]

We know we know. :P

[@OZ_viking]

Can anyone explain where is -100x came from??? -300-100x... 12.10 min.

[@deniseclairearimadopillo6177]

The derivative of T(C) = 900-300x-50^x2 is -300-100x since 50 is raised to 2. I hope this helps

[@3000LeftyMagician]

Funny enough my professor is Dr. Bergman the author of the textbook, and Dr. Biddle teaches it way better.

[@itzipocalyspe9396]

Maybe they should get one of those 360 cameras so we can follow the professor ourselves

[@MrSamsam911]

they usually have horrible resolution and distortion. i dont think its a good idea

[@CPPMechEngTutorials]

We will be experimenting with 360 cameras for lab tours this summer!

[@CPPMechEngTutorials]

@@MrSamsam911 You're right. However, the more expensive 360 cameras might work. But we don't want students in the classroom to feel self-conscious about being recorded.

[@user-jt8tr1qh1l]

Chrome Hearts shirt is tough

[@ChristopherFelicitas]

Whoever the camera man in this episode, don't smoke weed when doing shit like this. You affected a lot of people who want to learn.