Herman Yeung - Calculus - Sandwiches Theorem (迫近定理)

  Рет қаралды 44,100

Herman Yeung

Herman Yeung

Күн бұрын

Calculus 電子書 (手稿e-book) (共261頁)︰ play.google.co...
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適合 DSE 無讀 M1, M2,但上左 U 之後要讀 Calculus 的同學收睇
由最 basic (中三的 level) 教到 pure maths 的 level,
現大致已有以下內容︰
(1) Concept of Differentiation 微分概念
(2) First Principle 基本原理
(3) Rule development 法則證明
(4) Trigonometric skills 三角學技術
(5) Limit 極限
(6) Sandwiches Theorem 迫近定理
(7) Leibniz Theorem 萊布尼茲定理
(8) Logarithmic differentiation 對數求導法
(9) Implicit differentiation 隱函數微分
(10) Differentiation of more than 2 variables 超過2個變數之微分
(11) Differentiation by Calculator 微分計數機功能
(12) Application of Differentiation - curve sketching 微分應用之曲線描繪
(13) Meaning of Integration 積分意義
(14) Rule of Integration 積分法則
(15) Trigonometric rule of Integration 三角積分法則
(16) Exponential, Logarithmic rule of integration 指數、對數積分法則
(17) Integration by Substitution 代換積分法
(18) Integration by Part 分部積分法
(19) Integration Skill : Partial Fraction 積分技術︰部分分式
(20) Integration by Trigonometric Substitution 三角代換積分法
(21) t-formula
(22) Reduction formula 歸約公式
(23) Limit + Summation = Integration 極限 + 連加 = 積分
(24) Application of Integration - Area 積分應用之求面積
(25) Application of Integration - Volume 積分應用之求體積
(26) Application of Integration - Length of curve 積分應用之求曲線長度
(27) Application of Integration - Surface area 積分應用之求表面積
(28) L’ Hospital rule 洛必達定理
(29) Fundamental Theorem of Integral Calculus 微積分基礎原理
(30) Calculus on Physics 微積分於物理上的應用
(31) Calculus on Economics 微積分於經濟上的應用
(32) Calculus on Archeology 微積分於考古學上的應用
之後不斷 updated,大家密切留意
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Calculus 電子書 (手稿e-book) (共261頁)︰ play.google.co...
Calculus 微積分系列︰ • 學店時代正式終結 之 Calculus 微積分
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Пікірлер: 9
@oipower
@oipower 9 жыл бұрын
我是路過的,但已被吸引下來,絕對值得支持,加油啊老師 !!
@mastalp01
@mastalp01 8 жыл бұрын
this chinese lecture makes more sense than my teachers. Thanks
@kongoyu230
@kongoyu230 6 жыл бұрын
really appreciate your effort ,your videos really help me get through my struggles in the beginning of my university life!
@散华-l9m
@散华-l9m 2 жыл бұрын
大学都系要番黎睇herman
@HermanYeung
@HermanYeung 9 жыл бұрын
To Ernest: 因為我地只要做到識 in 就 ok 而留低 x^8k,我地已經識 in 所以就可以做下一步
@ernestfan7632
@ernestfan7632 9 жыл бұрын
點解第三題可以代 x 做 0, 但係 x^8k 照留係度嘅?
@charliefung2008
@charliefung2008 9 жыл бұрын
拍多D類似呢D片!
@spicygamer3637
@spicygamer3637 9 жыл бұрын
THANKS,BTW 一開始上下限唔係應該用大於等如 同小於等如咩?
@HermanYeung
@HermanYeung 9 жыл бұрын
+Potence Omni 無所謂,因為 lim 的情況下,有無等如分別係沒有的。
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