How many pairs of integers x,y exist such that the product of x,y and HCF(x,y)= 1080 | gdce exam |

[@mangeshyadav9640]

Very helpful 👍

[@harishsingh2652]

Can you please solve 3rd problem HCF(x,y)=240 problem and share the steps.

[@DityaClasses]

Ok

[@DityaClasses]

240 = 2×2×2×2×3×5 Possible HCF = 1 and 2 HCF 1 = (1,240),(3,80),(5,48),(15,16) HCF 2 = (2,60),(4,30),(6,20),(10,12)

[@shortsofficial7903]

4:19 how did u predict it bro?