How to remove/delete all duplicate files in a folder with a batch file!

Here's how you can use a batch file to quickly find and delete all duplicate files in a folder. This can quickly clean up a folder on your PC if you've accidently copied the same files to it twice, for example.
The script simply looks for all files that end in ' - Copy' or a bracketed number like ' (2)', and deletes all files that do. Make sure that this is what you need before you run the script, as it deletes the files and skips the recycle bin.
You can find the full code in the pinned comment below.
#batch #batchfile

[@Guidoshowtos]

Here's the full code, so you can copy and paste it to make your batch file: @echo off setlocal EnableDelayedExpansion REM This batch file removes duplicates but keeps the original files and itself. REM It identifies duplicates by " - Copy" or " (number)" in the file name. REM Identify and keep original files for %%F in (*.*) do ( set "file=%%F" set "filename=%%~nF" set "ext=%%~xF" REM Use findstr to exclude files that have " - Copy" or " (number)" in their name echo !filename!| findstr /R " - Copy" >nul || echo !filename!| findstr /R " ([0-9])" >nul if !errorlevel! neq 0 ( REM Mark this file as original set "original[!filename!!ext!]=1" ) ) REM Delete duplicates only for %%F in (*.*) do ( set "file=%%F" set "filename=%%~nF" set "ext=%%~xF" REM Reconstruct the original file name by removing " - Copy" or " (number)" set "cleanName=!filename: - Copy=!" for /L %%N in (1, 1, 100) do ( set "cleanName=!cleanName: (%%N)=!" ) REM If this file is not marked as original and it's not the batch file, delete it if defined original[!cleanName!!ext!] if "!file!" neq "!cleanName!!ext!" if "%%F" neq "%~nx0" ( echo Deleting duplicate: !file! del "!file!" ) else ( echo Keeping: !file! ) ) echo Done.