How to Sketch Acceleration Time Graph From Velocity Time Graph

[@syedfazlihanan9759]

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[@MathematicsTutor]

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My textbook didnt explain this very well, so I went to youtube, watched 5 videos about this, and this one if definitely the best.

[@MathematicsTutor]

Thanks a lot for appreciation. It inspires me to do the needful for the students like you. Share and Subscribe, if you like. Thanks and All the Best!

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[@kwispee5169]

This was so helpful. These graphs are pretty hard to grasp the concept of, especially since we are so used to our graphs being continuous or remotely continuous, and then these acceleration graphs come out of nowhere.

[@MathematicsTutor]

Thanks

[@lilohandaru5552]

yes, discontinuous graph is unintuitive

[@sublimekyle]

AP Physics student here. Had no idea what I was doing. Thank you so much

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[@MathematicsTutor]

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[@MathematicsTutor]

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[@MathematicsTutor]

Thanks for appreciation. Feel free to post question. Thanks

[@prajwalhn311]

Best video ever made for graphs! Awesome explanation.. Keep up the good work!

[@MathematicsTutor]

Thanks a lot for appreciation

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[@MathematicsTutor]

Thanks

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Thank u so Mach is this topic is very difficult for me and I am facing problem to understand this topic clearly but now I understand this topic clearly😊

[@MathematicsTutor]

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Thanks sir very very much.. it helped me a lot. Presently I'm in class 11 and studying kinematics..

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[@MathematicsTutor]

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Great video. Helps a lot for my exam tomorrow. Thanks!

[@MathematicsTutor]

Thanks for appreciation. All the Best!

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Your voice just wants u to keep watching even though I hate physics

[@jupiterdrops7752]

Thank you so much!!! I’m taking AP physics 1 (I want to major in physics) I was so confused lol

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Thanks alot for this video man, really helped me out in my physics course

[@MathematicsTutor]

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God bless u for making this video!.

[@MathematicsTutor]

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[@jabsba]

Thank you very helpful! But at the beginning on the acceleration graph shouldn't you start at 0 and then go to 2?

[@MathematicsTutor]

Acceleration is constant and eqaul to 2 m/s^2 in the first leg.from 0 s to 5 s. Horizontal line as shown in the graph correctly shows it. Hope it is clear. Thanks

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Pov: you took honors chem last yr and decided AP Physics was the way to go and now u dont know wtf is going on and u have a test tmr 😍💯💯

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Thank you sir this help me very much ..... Thank you soooo much......🙏🙏🙏🙏

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Superb teaching....👍

[@oyamamanjani9888]

THANK YOU SO MUCH

[@aerdis3814]

I have a question. when velocity goes from 0 to -20 so in the negative direction the acceleration will be negative too. isn't it

[@bemneth.tefera7682]

Yes, Because its decelerating or the speed is decreasing which only happens when the position is negative. The acceleration is negative too.

[@aerdis3814]

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Sir I actually have a question, is it a way I can reach out to you?

[@MathematicsTutor]

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My savior. Thank you.

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Good one. I like the way you explain. Thank you.

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omg u saved me i wasn't able to understand this until i saw ur vid 😄

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Your vid is very good... keep up the good work 👍👍

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Thank you so much for this video!!! you explained it really well.

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I agree, this is going to be super helpful considering the fact that my test is on Friday. Wish me luck!!!

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[@shafkatalam7373]

Don't we have to join the lines in Acceleration vs. Time graph?

[@killerman6336]

This Clear my doubts

[@lonevoyager6026]

but why don't you look at like the point like at 1,2,3,4 or 6,7,8,9/? ik these dont have accurate numbers on the y but on a test I did, i could find one for each x number but idk why u have to use only the 5,10,15,and 20 plz epxlain

[@jdrukman]

they're not needed. you only need two points to create a line, and acceleration is just the slope of each line.

[@agilitea9852]

Thanks for the explanation, it helps a lot.

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[@yousufali4567]

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[@SadiqunhnabiChoudhury]

Why didnt you add the seperate lines in the acceleration time graph together???

[@MathematicsTutor]

Good question. Transition at an instance is not really defined. Example at 5 we are not sure if the value is 2 or 4. Corners result into undefined rate of change. Hope that is clear. Thanks

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Thank youu so muchh for thiss explainationn :)

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Can anyone tell me from which book this question has been taken?

[@charmainetee3636]

ahh this video was so helpful! thank you :)

[@Babsmeme]

Does that mean that if velocity was a curve, then acceleration would be a straight but diagonal line?

[@bijoyetribhowmik9905]

Absolutely

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Thanks sir 1:23

[@dianaf8507]

Thank you for helping me!

[@swetasweta9540]

Why is deceleration always taken as negative ?

[@shashiranjan8596]

Thnq sir

[@sivakumarsg1153]

👌🙏 Good explanation

[@joseguevara9143]

Thanks so much!

[@mthulisi]

So u don't connect the points just leave the dashes

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what pen are you using ?

[@MathematicsTutor]

This is the most popular question. Here is the solution: kzbin.info/www/bejne/mZyQfohuhdKqsNU Thanks

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Thank you

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Best out the best

[@ess8915]

thanks

[@lazycatt287]

So acceleration is just tangent lines and irs not connected

[@MathematicsTutor]

There is jump discontinuity at t = 5, 10, 15, in between we have constant acceleration as shown by the horizontal line.

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Really good vid

[@MathematicsTutor]

Thanks for appreciation. All the Best!

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Btw nice explanation

[@rvs263]

Can I join the lines of a-t graph

[@rvs263]

Any of the reader of my doubt can reply

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[@MathematicsTutor]

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[@MathematicsTutor]

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