Position or displacement time and velocity time graph relation

[@hirunisiriwardhane4361]

i am in sri lanka and i had many smALL but too much necessary points to know but i never found solutions untill i watch this vedio so absolutly thanks sir anil kumar for delivering succh sort of useful clip

[@ghsjgsjg53chjdkhjydhdkhfmh74]

Thank you! I came for a level mechanics and this is the best one yet explaining motion of displacement time graph😍

[@MathematicsTutor]

Thanks for appreciation. Here is related playlist: kzbin.info/www/bejne/Y4rVZJuBZ5t2sKs

[@am-cb8vn]

@@MathematicsTutor thank you

[@javien-dn9ps]

thank you for your help w my physics homework!!! god bless u

[@MathematicsTutor]

Best Wishes

[@buikhanhlinh1145]

You have made my studying SAT physics easier!!! Thank you!

[@erumfawwad1464]

Excellent demonstration. I always come back whenever I'm going kinematics graphs.

[@MathematicsTutor]

Thanks a lot. All the Best!

[@joytighosh2314]

@@MathematicsTutor thank you

[@zerog1064]

Thank you so so so so soooooo much!

[@Googlegoogle-cr7pu]

voice and video super sir

[@Master-vd4qd]

Outstanding... Sir

[@MuhammadUsman-sk8uz]

Grt Work Sir

[@hitesha699]

Just wowwwwwww wow amazing explanation sir....amazing!°!!!!!!

[@norhanaambel531]

Thank you, sir!

[@ashizafar6553]

Awesome 😇

[@corneliusharris152]

Explained it better than my teacher thanks

[@hafizfakharudin4557]

It was a beautiful lecture...Indeed

[@tanmaysharma3335]

Nice explanation

[@DailyMovieClipsAI]

anil kumar the GOAT

[@jeetendrapratap5050]

Awesome explaination sir

[@Aadi_7779]

Gd

[@hohahehi]

perfect teaching

[@ajibolaekunola]

Very informative

[@abhi.j7780]

Great teaching sir, thank you so much

[@clintn.kildepstein1656]

Thank you so much sir for helping me

[@the_explorer35]

Thankyou sir for making it easier for us.

[@dhruved.]

Can't express my feelings sir... ThaNK You so much i required this urgently!!!! 😭❤️🙏

[@inokarathnamali8251]

Thanks for the video Thank you

[@rahanata7829]

Really helpful sir Thank u May God bless u

[@patricksilvestri2406]

Amazing Video!

[@VK-il9kv]

v useful thanks

[@rapbeats162]

Thank you very much

[@AhmedHassan-vj6hz]

many thanks

[@JeanCloueLBacho]

Thank you so much, I really love the way you explain it, now I understand our lesson, Thank you☺

[@shantot.a7874]

Thankyou

[@ashatv9452]

Superb class understood very well Thank you so much sir❤

[@myousaf634]

Thanks sir u understand 👍

[@magalin1442]

VERY HELPFUL!! THANK YOU SIR

[@harshapasagada8590]

Good sir

[@Rk95122]

Thank you, Sir.

[@SOMESHWARKANDREGULA]

Thank u sir u really cleared our doubts, voice was really apperciable....& pls explain with any numericals...

[@anilkumarpathiyadankesavan6698]

Thank U sir...osm explanation.

[@ritika_bhattacharjee]

thank you! this really helped

[@StephenTech]

Absolutely amazing explanation, was struggling with this in both A-Level Maths & Physics, this video has helped me understand better than any of my teachers (:

[@samarbandodkar12]

Excellent

[@MathematicsTutor]

Thanks for appreciation. All the Best!

[@samarbandodkar12]

Anil Kumar thank you

[@ericadixon9400]

THANK YOU!!!!!!!

[@thiliniwijesinghe7739]

Thank you so much sir!! Very helpful 🙏❤

[@5aleddss]

THANK YOU!

[@Manavkumar-k8h]

Thank you 🙂

[@abigailgiles7451]

Very helpful!!

[@khalidibrahim4232]

🔥🔥

[@larafalls4329]

Super informative. Thanks!

[@damodarpadhy794]

It will better ,if example for each graph were given

[@MathematicsTutor]

Check this playlist: kzbin.info/www/bejne/aXaXgnx8fK2coKc Thanks

[@BIDEN-re7ry]

thanks!

[@vishalsinghjat1916]

Thanks sir

[@_.aintforu_2]

Thank you it helped me a lot

[@kerryloh5285]

sir,so the zero in velocity-time graph is just a turning point and not mean the object stopped when at zero? unless no line is drawn behind the zero in velocity-time graph?

[@milaspalmer8036]

Draw a displacement time graph and velocity time graph of a ball released at height of 8m and bounces on the group 3 times and each rising half the previous height

[@AmanSharma-wn8qh]

Sir veryyyy thank you . I don't know how much I facing problem with that .

[@amyalexander7360]

makes sense sir, thank you!!

[@10perkara]

thank you... it's very fun learning... it also makes me understand more

[@ObeyAmmalol]

11:53

[@MathematicsTutor]

Let me know if all was clear. Thanks

[@ayushagarwal016]

Awesome could have been more amazing if added a t graph in all cases , BTW Awesome.

[@mastan7846]

It is better to explain how slope is positive

[@jayantideshpande8459]

Sir in 2nd graph how the slope is positive?? The slope is going towards the origin.. So how the slope is positive??

[@irfankobber7097]

best explaination by far! Can u do a vid on bouncing ball accelation time graph

[@swarajsarangi3120]

❤️❤️❤️❤️💯

[@Sidd_Imran]

HOW TO FIND SLOPE POSITIVE & NEGATIVE IN NATURE IN CASE OF LINE? pl explain

[@sreyaunni6155]

Excellent class sir...😊👌.Hope more from you...😊

[@sallyko__2807]

May I ask the name of the black pen your using?? Thanks!!

[@ermiasestefanos4195]

I Like it, but isn't it "accelerating" , which is non-uniform/ not constant, if the line graph is Parabola?

[@MathematicsTutor]

at 6:12, The slope of a curve is constant; Curve is Velocity; Slope of this line is the acceleration. y = mx + b, m is a constant. Hope now you can see that the acceleration is constant for the parabola representing displacement. Thanks

[@nkitydv]

What is the difference between uniform and constant velocity please help me

[@Aspirant1210]

@@nkitydv both are same 🙄

[@dyanmofitnessandcalistheni1016]

Thanku sir

[@Gleza519]

What pen was used

[@vodanh652]

well explained. thank you.

[@MathematicsTutor]

Thanks for appreciation and your time. Appreciate your name -- Eager to Learn, a true student!

[@__.nahaan.__2509]

Plz give example for each cases

[@MathematicsTutor]

Sure, will post a video on that soon. Thanks

[@anilkumarsharma8901]

make calculator over it for more easy calculation and direction 😎😎😎😎

[@ajinkyakale3353]

What would be the vt graph if acceleration is non uniform??

[@MathematicsTutor]

Thanks. Will post a video for that. Here is some concept which can help: kzbin.info/www/bejne/fZaXk2uFgpqso7s

[@MathematicsTutor]

Here is an example for non-uniform acceleration: kzbin.info/www/bejne/q5mzY2xpi9SpgLc Let me know if that helps. Thanks

[@hafsa9512]

no curve is formed in any v-t graph?

[@hirunisiriwardhane4361]

why not when the velocity increasement(accelaration) increases with time we could get curves in v-t graphs too

[@xmariacelestex]

is a position and time graph the same as a distance and time graph?

[@Madeeha_]

I might be late but yess

[@maabetikijodi1116]

Sir of this answer2. Draw a plot between displacement v/s time for the retardation motion

[@frankcarey250]

Sir please clear my doubt. To get distance traveled we calculate the area under Velocity Time curve, which we usually do considering curve above X axis. But we could have compute the area under that curve with respect to Y axis. But why don't we do so? Please reply.

[@MathematicsTutor]

We could do either way. Why we don't normally do - x is treated as an independent variable. Time is independent variable by default. Velocity is defined as rate of change of distance with respect to time -- so that explains. Hope it helps.

[@kausarmalik9258]

@@MathematicsTutor sir you ate amazing

[@YL-ii3vy]

hi,i have a question, for the fourth d-t graph,the object returned back to the original position twice(displacement=0m),but in the v-t graph,the velocity of the object is at zero when the d-t graph is in its minimum point(displacement is negative,but not zero),why is that so? And why the v-t graph was not drawn in a way that the the line touches the x-axis twice?(which means that velocity=0m/s)

[@kakaliray4721]

You have not at all understood the video..

[@skumar2664]

Online class hota hai sir

[@MathematicsTutor]

Yes, send e-mail for details

[@Maria-ph6wb]

A special case where a body moving with constant velocity has constant acceleration. Is this true? My teacher said: It is true bcz acceleration=0 is also a constant quantity for acceleration and where a=0 velocity is constant But I don't get it....so plz explain...

[@teresamariconda964]

Maria hi because acceleration is change in velocity so if the body maintains a constant velocity of 0 then acceleration is 0 as there's no change in velocity so that is still constantly 0

[@TaurusWhat]

Great explanation!

[@MathematicsTutor]

Thanks a lot for appreciation! All the Best!

[@roddamapm8401]

Very good explanation

[@zaheenkhan3770]

Sir why the displacement and velocity time graph scatch are different from each other plz sir i have big confusion

[@MathematicsTutor]

Velocity is rate of change of displacement. So they should be different. Hope that helps

[@thethuglife10]

@@MathematicsTutor amount of change in position is called displacement Velocity is rate of change in position

[@anilkumarkumawat1693]

What is meaning of -disp, and - velocity

[@MathematicsTutor]

Thanks, will make a video on this soon. displacement is change in position velocity is rate of change of position.

[@carultch]

Negative displacement means that the object is located in a direction from the starting point, that is opposite what we arbitrarily define as positive. Negative velocity means that the object is moving in a direction, that is opposite what we arbitrarily define as positive.

[@deeptibarmandeka6254]

How many pens u have?😄😄best video 👍👍👍

[@saiprasad5599]

Sir the last vt graph is not correct I think sooo

[@MathematicsTutor]

It is correct. Please check again. Thanks

[@TheMarko7766]

some graphs are WRONG

[@aartisorout2416]

Good sir

[@shabanaanjum6675]

Nice explanation

[@MathematicsTutor]

Thanks

[@JeanCloueLBacho]

Thank you so much, I really love the way you explain it, now I understand our lesson, Thank you☺

[@fawlen_eynjuhl]

thank you sir