How to subtract two binomials

[@carllouisecapute9749]

got my assignments answered quickly. thanks

[@brianmclogan]

awesome! you are very welcome!

[@brianmclogan]

Great! Let me know how else I can help

[@sufma6505]

Watching this 5 minutes before my test

[@TheAdamkenneyfriedla]

Thanks to the third power, sir.

[@brianmclogan]

you are very welcome! happy to be able to assist you

[@Toodl]

I got my 7th grade staar (main test to determine if you pass) coming up and this helped me a lot , to be understand the concept

[@lucidgen11]

would the signs change for let's say: (2a-2b)-(5a-7b), would the negatives become positives and the positives become negatives?

[@touyert9140]

Man I'm in Pre-Calc and I forgot how to even do this haha, thank you! I really appreciated this because it helped me a lot and then watching this reminded me how to solve everything again. High school T_T.

[@brianmclogan]

I am here for you, teaching pre-calc this year so keep watch out for more videos

[@magnicifentvi9554]

+Free Math Videos Cool, thank you

[@joshua5374]

Touyer T lol same here forgot our lesson last year lol

[@marcjoshualatonero934]

Good morning Sir✌😂 I am one of your subscriber in your youtube content which is all about math. Regarding to your one videos "How to subtract two binomials" you said that we can subtract binomials if it is same base like (5a + 9b ) - ( 2a + 4b) I learned this example you've talked about in your video, So I just want to ask what if the equation is like this ( a³-3a) - ( 1- a -2a²) what method that you can apply to this equation? It is subracting binomials with a trinomials may I right? Thank you Sir! I hope that you notice this message.😂😊

[@JashanNarwal]

no one ever helped bro💀

[@zacharyadkins762]

Thanks

[@brianmclogan]

Zachary Adkins you are very welcome!

[@zacharyadkins762]

Is there any videos for multiplying and dividing binomials?

[@brianmclogan]

yes plenty, I can't send you a link on a comment but if you search my channel I have a couple of examples

[@zacharyadkins762]

Thanks! You are a life saver!

[@djestrada02]

Thank You Sir ^_^ now I know how :)

[@touyert9140]

I apologize for posting here, because I don't know where to post but I have a problem I need assistance with if I can. The rules state to find the Greatest Common Factor such that the remaining factors have only integer coefficients. The problem is: 1/2x^3 + 2x^2 - 5. I thought about what I could do but I don't understand what numbers are the Remaining Factor and I tried 10 as the greatest common factor. I would really love if there were a lesson about this. Thank you!

[@touyert9140]

Oops, the -5 has an x at the end, so instead of -5, it's -5x.

[@brianmclogan]

GCF will be x, if you need to factor out a GCF for integer coeffiencts then factor out 1/2 your new expression will look like this 1/2x(x^2+4x-10)

[@touyert9140]

+Free Math Videos Thank you!

[@Adonisbrown21]

Thank you for the help

[@brianmclogan]

Odaine Brown you are very welcome! happy to be able to help

[@Adonisbrown21]

Mr. McLogan's Math Channel of course. You are cute too

[@SonISoni-wu3of]

(14b-16c) square 2

[@jeniferflores7620]

How would you express your answer as a trinomial

[@brianmclogan]

why do you need to do that, the answer is a binomial

[@SonISoni-wu3of]

(2a+4b) squire2

[@iTreyyHD]

so it doesnt matter that the other binomial is still in parentheses?

[@themilkman1188]

What if they're both perfect squares?

[@brianmclogan]

The Milkman then you would apply the same process. just take the square root of both terms to identify a and b

[@themilkman1188]

Thanks

[@Bankrolls33]

Jason kid is that you ?

[@daniellayne8336]

I'm so confused, (-5x^3+4) - (-8x^3) How is the answer not -3x^3 + 4?

[@brianmclogan]

Danny Layne -5-(-8) can be written as an addition problem -5+8 which is 3

[@daniellayne8336]

Mr. McLogan's Math Channel Yeah I looked more into it and understood how I got it wrong. Thanks man.

[@brianmclogan]

no worries, happy to help

[@maggierudzavice1244]

Thanks you I got a F

[@mayisarahman2152]

I mean it is from 9yrs ago...

[@D1MPL3S_]

Thank you sir!