HWN - Want to interview for NXP Semi? Study this!

  Рет қаралды 12,192

Hardware Ninja

Hardware Ninja

2 жыл бұрын

Hi fellow (and future) engineers!
This week we tackle a real interview question using the foundations we learned on one of our first videos. We're so thankful for our community members that constantly send us feedback and ideas for questions. We couldn't make this happen without you!
Check this video before answering the question: • HWN - Hardware Intervi...
Welcome back to another episode of Hardware Ninja! Ever wondered how to get a job as a Hardware Designer in some of the top tech companies like Microsoft, Google, Tesla, Apple, Facebook, etc?
The interview process employs many application based questions whether you're a recent college grad or an experienced applicant. It doesn't matter if you want to work for Elon Musk, Tim Cook, or the up and coming start-up you heard about. We're here with curated material of real life technical interview questions.
Please consider subscribing to the channel and supporting our movement. Prospective job seekers (including yourself some day) will benefit from this resource.
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Пікірлер: 8
@Laiba12319
@Laiba12319 2 жыл бұрын
I get the same answer applying the superposition principle.
@flinxsl
@flinxsl 2 жыл бұрын
I got to the same answer just by charge conservation, which is more intuitive for me. I just wrote: Q1_p1 = Q1_p2 + Q2_p2 C1*V1 = C1*(Vout - V2) + C2*Vout then it is the same equation as you wrote.
@HardwareNinja
@HardwareNinja 2 жыл бұрын
Hi Greg, Thank you so much for stopping by and contributing to the discussion! You're absolutely right, charge conservation is another great way to think about the problem. However, we opted to go with the approach of the initial condition since it builds on the topic of our very first video! :)
@amitjana8172
@amitjana8172 11 ай бұрын
very nice question! in the second transient event i solve the problem using superposition and got the same answer.
@bhayanakmaut007
@bhayanakmaut007 2 жыл бұрын
is this correct? Intuitively, C1 is flying capacitor, assuming phi1 and phi2 are complementary clocks, when phi1=1, c1 is charged to V1, when phi2=1, C1 should fly to V2 + V1, your Vout should be V1+V2. since no R is mentioned Tau is zero, implies cap charges instantaneously regardless of Capacitance value. your final equation Vout= C1V1 + C1V2/(C1+C2) doesnt seem right if C1=C2, Vout = (V1+V2)/2 ? There is a problem with notation, delta V1 must be delta Vc1 and Delta Vc2 must be = delta Vc1 + V2
@yunusdification
@yunusdification 2 жыл бұрын
the delta V2 and V2 is a bit confusing. Maybe use Va as V1 and Vb as V2
@therandomchannel9226
@therandomchannel9226 2 жыл бұрын
How did u plot Vout out of the equation without explaining
@coolwinder
@coolwinder 2 жыл бұрын
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