Ideal Gas Law Physics Problems With Boltzmann's Constant

[@TheOrganicChemistryTutor]

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[@newtoninspired]

thanks for the R and k relation! was ALWAYS confused at that.

[@tyrell.m5249]

Phsyics would be so goddamn easier if it didn’t have conversions

[@JoshAwe]

Bruhh u good?

[@dizonjamesmulenga7260]

Welcome to reality 🙂

[@razasyed575]

your the man of the hour holmes

[@jayashreeg8116]

I think if we find n value first and multiply it with Avogadro number, it will directly give number of molecules. I have cross checked the answer value and it's the same. Please let me know what you think.

[@kincaid5749]

thats exactly what I found as well, and it is also how my physics professor taught me how to do it. I think it is correct in this case, and in any other case where you have similar units.

[@senny-]

The Boltzmann constant is the R constant divided by the Avogadro's Number!

[@ethancline9905]

A couple of days ago the Ideal Gas videos were all apart of your physics playlist but now they are gone. Where can I find these videos?

[@sujimayne]

STP according to IUPAC is 273.15 K and 1 bar (100 kPa). NIST uses NTP and that is 293.15 K and 1 atm.

[@carultch]

The IUPAC standard for STP changed in 1982, so it's possible he got his definition of STP from a textbook printed in the '70's, which would use 273.15K and 1 atm, instead of 1 bar.

[@Bbbbbbbbbbhhhhhhh]

I don’t know, today I know my teacher still tells us to use 273.15k

[@draygerard4550]

thank you

[@thisgirlpurpleyou3334]

I don't know if anyone's gonna see this but please if you know, can you answer my question? Why did he use PV=NKT in that last example? Thank you so much!

[@elzika739]

because it asked for number of molecules instead of number of moles, so if you used pv=nRT it wouldn’t of worked because that finds moles. so you simply should remember this equation for finding any question that needs you to find molecules

[@senny-]

You're gonna get moles instead of molecules if you solve for lowercase n. You can convert it to N later though by multiplying it to Avogadro.

[@twinrickel7647]

How can you use Boltzmann equation to find approximate population of an excited state?

[@jpmcfrosty]

I know this is a hella old video and not sure if anyone will even see this but can anyone explain why my Homework portal from my school has the answer in suggesting *answer box to input answer* "10^23" ???? All my answers are coming out to "10^24" I've triple checked my computations and followed those steps in the last problem to the tee. Even online HW resources have their answers in "10^24" but the portal is having "10^23" next to their answer box

[@sidalalujaili3769]

when are we supposed to use R vs. K?

[@carultch]

They both ultimately are the same thing. It's just that R is expressed in terms of moles, and k (usually lowercase k) is expressed in terms of atoms or molecules. One is a macroscopic unit, the other is a microscopic unit. Moles ultimately are just a convenient counting unit called "the chemist's dozen", so it makes it practical to express populations of molecules without scientific notation.

[@RUOTKherkuol]

That's very interesting

[@ICantSolveMath]

k=R/Na wow I graduated from college without knowing this. Haha

[@ProCode1919]

Good

[@sdaless]

10,000 mL is equal to 1 cm^3 not 1 mL

[@kiransteward5387]

Isn't standard temperature 298k?

[@robertowisconetti2732]

nope its 273 K.

[@kiransteward5387]

@@robertowisconetti2732 but isn't that 0 degrees? In the UK our spec says 25 degrees (298k) might be different for you guys though

[@robertowisconetti2732]

​@@kiransteward5387in celsius its 0. converted to k its 273. 25 degrees is the room temperature. u have mixed da facts. if u need any help. i ll help ya

[@neilbergin3835]

Wespuchchi Nasarawo it’s 273.15 K = 0 degrees Celsius.

[@kiransteward5387]

@@neilbergin3835 yeah I know that but in chemistry we take 298k and 100kpa as standard conditions under the topic of enthalpy changes

[@Prince-rl5cv]

k

[@fatimaalfehaid]

👌🏽🏆

[@RaushanKumar-zt3ej]

Hi

[@zacharyfalkowski]

Good