If the maximum load carried by an elevator is 1400 \(\mathrm{kg}(600 \mathrm{~kg}-\) Passenger \....

If the maximum load carried by an elevator is 1400 \(\mathrm{kg}(600 \mathrm{~kg}-\) Passenger \(+800 \mathrm{~kg}-\) elevator \()\), which is moving up with a uniform speed of \(3 \mathrm{~ms}^{-1}\) and the frictional force acting on it is \(2000 \mathrm{~N}\), then the maximum power used by the motor is  ______\(\mathrm{kW}\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2
ight)\). 📲PW App Link - bit.ly/YTAI_PWAP 🌐PW Website - www.pw.live