Please allow a minor correction towards the conclusion of the proof of Liouville's Theorem: you say "So RHS of the above inequality becomes arbitrarily large" but what you mean is "So *the denominator* of the RHS of the above inequality becomes arbitrarily large". Very nice lecture. This whole series is fantastic.
@manoranjansahu71612 жыл бұрын
GOOD
@anubhabpahari4 жыл бұрын
In the last of two given exercises, there is an error. Instead of integrating from 0 to π we should integrate from 0 to 2π. This would give us the result 2π instead of π.
@bhaskarpandey85863 жыл бұрын
No the equation is correct as it is.[Hint: Use Liouville's theorem]