The beauty & essence of statistics and probability distribution in statistical mechanics was described through this video is really awesome. Best teacher ❤️
@Akash_Tyagi_938 жыл бұрын
He is the best teacher I've noticed in this NEPTELhrd series . Thank you very much Sir, FROM IIT Kanpur.
@chanky10007 жыл бұрын
17:55 It's a non trivial trick, and it takes a non trivial person to find it. Poisson found this in 1815. Beautiful!
@arghyamazumder43684 жыл бұрын
Yeah,I am impressed
@maujo200914 жыл бұрын
I have found these lectures EXTREMELY helpful! Thx NPTELHRD! If available, please upload Classical Electrodynamics lectures.
@supern0is3494 жыл бұрын
this is priceless.Seriously.A guy this smart teaching for free?Unbelievable thanks a lot for the video
@sanchayanbanerjee76234 жыл бұрын
just GOD.... !!!!!! CAMERA WORK & sound is also outstanding
@03Kabbotta1112 жыл бұрын
He finally forgot something! After hours and hours of this brilliant man's lectures he finally forgot some little factor in Stirling's Approximation. He is human after all ; )
@Tyns198 жыл бұрын
Michael Chapman where is the error plz!!
@swapnilganeshpure4 жыл бұрын
May be becquse he looks unwell in this lecture.
@elamvaluthis72682 жыл бұрын
Very excellent explanation 😁😁😁.
@kunalverma69404 жыл бұрын
Around 26:00, Dr. Balakrishnan doesn't do a Stirling approximation for n! because it varies from 0 to \infty, but so does the number (N-n)! (from \infty to 0) , so why is the Stirling Approximation valid in that case?
@shambhavimishra8928 Жыл бұрын
Actually, N>>n, so (N-n) doesn't go from infinity to zero.
@abbeselhabib24358 жыл бұрын
very helpful for me and 'الفيلسوف عبد الصمد"
@sagarmalhotra44738 жыл бұрын
I don't really get the reasoning behind taking the integral from negative infinity to plus infinity at 15:58 , whereas in the gamma function the limits are from 0 to infinity.
@TheBobathon8 жыл бұрын
it's a valid approximation because the area under the gaussian for x0, when n is large. You can check this for a given value of n using normal distribution tables if you want to be sure
@meonyoutube29774 жыл бұрын
how is Stirling's approximation justified for (N-n)! when n is variable from 0 to infinity?
@shambhavimishra8928 Жыл бұрын
Actually, N>>n, so (N-n) doesn't go from infinity to zero.
@elamvaluthis72682 жыл бұрын
Very nice thank you.
@ayushpaliwal18804 жыл бұрын
I didn't get the N^(2/3) thing (particles near the wall), how ?
@jdidiieiee4624 жыл бұрын
N proportional to V => N ~ L^3 => N^(1/3) ~ L, also S ~ L^2 => S ~ N^(2/3) irrespective of number of dimensions
@mayanksharma8284 жыл бұрын
I have a dout . I would be grateful if someone can clear it. In 20:51 , How can we assume that particles are moving independent of each other. I understand that there is no explicit interaction between particles ,but due to thermal energy particles will collide . I don't know what can such an event be considered statistically independent.
@kunalverma69404 жыл бұрын
From what I can understand, by "independently moving", Dr. Balakrishnan does not mean that they aren't colliding. Instead, it means that the probability of a particle to be inside the small volume v is "independent" of (or you could say isn't affected by) some other particle being inside that small volume v. A particle sitting inside that volume can't cause another particle to "not be" inside that volume.