Increment and Decrement Operators in C (Part 2)

C Programming & Data Structures: Increment & Decrement Operators in C (Part 2)
Topics discussed:
1. Solving expressions like a+++b.
2. Lexical analyzer.
3. Tokens.
4. Token generation.
5. Homework problem.
C Programming Lectures: goo.gl/7Eh2SS
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#CProgrammingByNeso #CProgramming #IncrementOperator #DecrementOperator

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True

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8 ans

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[@Sazzad_Sabbir]

For the last question:- 1)If you set the code like this in the complier: #include int main() { int a=4, b=3; printf ( "%d", a++ + ++b); return 0; } Then the output is :- 8 2) But , if you set the code in the compiler like this: #include int main() { int a=4, b=3; printf ( "%d", a+++++b); return 0; } Then , there will be an error! Thank you guys

[@jonathanooi6817]

How is -8 tho? Can explain for me?Thanks

[@Dilip077]

It's 8

[@jonathanooi6817]

@@Dilip077 he wrote :- 8

[@manu-mp5bt]

First program is correct, it will not raise any error. And the last value is 8. Explanation: a=4,b=3; are the values we have , a+++++b means the lexemes are |a++| |+| |++b| . So 'a' is used and incremented to 5, and b is incremented to 4 and then used in expression. So the final answer will be 8. Second program will generate error because immediate after an increment or decrement we should have a variable

[@jsmphompho8052]

@@manu-mp5bt but the question doesn't have spaces and "error" is one of the answers so I believe 8 would only be right if spaces you showing were part of the written program. please do correct me if I'm wrong. otherwise d is the right answer for me

[@proggenius2024]

You rock guys. Keep it up 👍 And yeah the answer to the homework question is d)error. Had it been written with a space as a+++ ++b, the answer would have been 8. But as it is, i.e., a+++++b, it is evaluated as |a| |++| |++| |+| |b| or (a++)++ + b which causes an error because an an increment operator doesn't take an rvalue or a++ as its operand. As discussed more clearly by neso, both increment and decrement operators work only on lvalue(left value).

[@mz5821]

There's an error in your statement. The answer would have been 8 if written as a++ + ++b not a+++ ++b

[@monikak1421]

8

[@youssefharby1153]

error: lvalue required as increment operand You are right i have tried it

[@vortex370]

@@monikak1421 he is right that will give you error .if you have watched the lecture properly then only you can get why,. It's a concept of spacing

[@vortex370]

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[@kunaldhyani]

Answer to the question is ERROR. As a+++++b is tokenize as - a ++ ++ + b = (a++)++ + b So, as increment operator can take only lvalue so, compiler generates error.

[@sabbirahul664]

8

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[@thawedmind]

some people don't like the accent. I'm following through the whole course and its really helpful because of the backgroudn knowledge which I just don't get anywhere else, other people are just looking for quick answers and wouldn't appreciate the diversion into tokens. Just to clarify I think this guys amazing I feel as if I'm getting a complete understanding for the subject. =D

[@ajaysharan8130]

@Nadeem Afzal yes 100% correct

[@anjaliawasthi4623]

Awesome haven't learn these operator in such a way

[@aishwarya2205]

Same here

[@compangit1524]

Comments for myself: lexical analyzer scans the code and tries to find meaningful sequences which it converts to tokens to translate. Usually, meeting a blankspace will stop the current token generation. Post-increment happens after the current value of the variable is used in the function. My answer for the assignment is d) error We first need to get the sequences of tokens to get an overview of what's about to happen. The sequence of tokens is [a] [++] [++] [+] [b]. This might seem to work, but if we try to go thru it one by one. a++ is fine, but a++++ is not. a++++ may seem valid but ++ operator requires to be accompanied by an lvalue. a++ is an rvalue hence, an error will be thrown at that point.

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Guy I never knew I could understand the topic of token generation and compiler design and how it interprets. I am really grateful to be in this century where everything is in the internet. Thank you

[@VamsiKrishna-ym3cr]

Error.. a++ means a=a+1 a++++ means( a+1)=(a+1)+1 But ,lvalue is required to use increment operator..

[@swagatikasahoo1531]

Thank you for the explanation 👐

[@pineapplee101]

Cant that be a++ + ++b ?

[@ojaskumar2355]

@@pineapplee101 yess i thought the same process🙌

[@VamsiKrishna-ym3cr]

@@pineapplee101 lexical analyser scans longest and valid Tokens ..there we are given a+++++b and if we generate tokens we get 'a' ,'++' ,'++', '+' , 'b'...

[@hetaeramancer]

@@pineapplee101 i think this can work, and it will be equal to 8 a++ and then + and then ++b

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[@its_SR07]

error is the ans

[@prabhatsingh6124]

@Anonymous OP nope error will be the answer

[@desuchan3313]

@@prabhatsingh6124 is it because the fact that u cannot increment operators am I right?

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[@every_things_is_here]

#include int main() { int a=4, b=3; printf("%d", a+++++b); return 0; } output : 8 solving: a++ + ++b hear a++ is post, or ++b is per and + is use of addition

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[@rahulreticent5034]

Output = 8 a, ++, +, ++, b will be tokens generated by lexical phase As ++ is a unirary operator so after first ++ is generated second ++ won't find any variable near it so it backtrack to + only and then ++ will be generated next token bcz it will find b as nearest variable.

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yes got the same answer

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wrong answer answer will be error

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[@prateekraghuvanshi1291]

a++ means a= (a+1) a++ ++means (a+1)=(a+1)+1 which is not allowed so it will produce error

[@thawedmind]

gotta try it to be sure, gonna do that in a min, but I think that the token analyser will token it like this [a++][+][++b].

[@thawedmind]

you were right, It sees it as a r value.

[@sadirirfan9008]

@@thawedmind but it can analyse like this way also [a++][++][+][b] because [++] is a valid lexeme.

[@YoYo-nt7yf]

No it read from the left so it will be a++ which is 5 Then a++ (here a is 5) ie. 6 a is 6 and b is 3 So 6+3 which is 9

[@sambitmishra129]

@@thawedmind u are wrong bro, compiler start reading character from left to right until it finds meaning full token.

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[@HM_Shah_Paran]

a ++ ++ + b. Value 'a' assigns 4 in the equation first, then increments. So, 4++ +3 is the completion of equation. Since 4 is a constant and a constant can't handle increment operator, this is an error.

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[@aminhoney3644]

Input: a+++++b Output: Lvalue error

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[@pritamkrdas8696]

It will show an error ,, but if we. Put the line. Like a++ + ++b then it will give the output 8 .. so after putting space at a &b we will get the output

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[@mohithkumar3522]

error: lvalue required as increment operand printf("The value of %d+++++%d %d is:",a,b,a+++++b);

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[@selvalakshmis.v4232]

d)Error Reson: lvalue required as increment operand Thank you, Sir

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[@ramyakrishna9558]

the answer is 8. because if we proper tokens between them like |a++| |+| |++b|. In que a=4 and b=3, |a++|=4 and |++b|=4 depending upon the given terms explaing in vedio on pre and post increment. so the answer is 4+4=8.

[@abdulkareemqasem7183]

first of all you ar really great teacher ,I like the method you use to explain .regardless of it is my first time keeping following a lecturers online put I truly got a huge benefit out of your lecturers ,the answer is 8 because after token generation |a| |++| |+| |++| |b| so post increment we will use the value first the increment but in pre increment we must first increment the value .It goes like this a=4 b=3 so 4+4=8

[@slobodantajisic2762]

Those are not the longest sequences of meaningful characters. What about |a| |++| |++| |+| |b| ? These are the longest sequences of meaningful characters, so we get an error "lvalue required as increment operand", because a++ ie a = a + 1 is not lvalue.

[@ayushisrivastava7535]

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[@hymasubramanyan]

answer is 8 ,when we put proper spacing between the operators, ie, a++ + ++b;

[@duartemonteiro9459]

But there is no proper spacing here

[@manalkhazraj]

Why not 9. If a++ is 5 Then + ++b is 4 5+4=9 I don't understand

[@duartemonteiro9459]

@@manalkhazraj It is just error.

[@vishalray4230]

@@manalkhazraj a++ is post increment operator,hence increment will be after the evaluation.

[@ayushrana3429]

No you are wrong answer is error

[@swathik3491]

a++ ++ + b as a++ is replaced with 4 but for ++ no operand availabe it produce error

[@subhrajitbiswas5829]

a++ + ++b=8

[@cs04abhinavasthana36]

@@subhrajitbiswas5829 no wrong

[@cs04abhinavasthana36]

@@subhrajitbiswas5829 sequence se token mein convert hoga n

[@cs04abhinavasthana36]

Ryt

[@subhrajitbiswas5829]

Ohh yes

[@Foodfind217]

Answer of the last question is 8 Because (a++) + (++b) =4 + 4 = 8 And a contains 5 and b contains 4

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[@nileshtadagonda6647]

Q3> It will show Error , if we put space before and after of middle + then answer will be 2)8.

[@UNKNOWN-tq4lq]

the main data entry is planked so it will be only 8 when the data type been planked. this will be the correct explanation for this answer

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[@niranchana_kv69]

Output : error: lvalue required as increment operand

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[@purushothamchembeti8606]

ans:error because a+++++b can be generated as token as |a| |++| |++| |+| |b| now as it is the post increment first the equation will be evaluated then operand will be incremented, so a+b=7, and a=4 , two ++, ++ operators will be there, as increment acts on single operand another ++ can't be evaluated.so it gives error.

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No it is 7

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Type it in your pc

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Checked in decoder... You are wrong chirontan... It shows error

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@@chirontanbhuyan51 its error sir!!

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[@MahmoudGamal1999]

Lexmer will convert it to -> |a| |++| |++| |+| |b| and it will consider the two double pluses, a++ ++, undefined then it will produce an error!

[@jeevajeevan1346]

error: lvalue required as increment operand

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[@tharunkumarcheripally9712]

By Lexical analysis , which provides meaningful expressions expression : a++ + ++b = 4 + 4 = 8

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It is the crt answer bro

[@santhoshteja1849]

if we use a+++++b ,then u will get error,but if we use a++ + ++b,then u will get value 8.

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Which branch bro

[@aditisharma8482]

Answer is d...it gives an error name Lvalue required .......but when I write the code (a++ + ++b)there is no error

[@matlapudipavaneswarsatyaap2667]

answer is b

[@matlapudipavaneswarsatyaap2667]

sorry guys answer is d it divides the lexemes into a ++ ++ + b .and groups into a++ ++ +b .here lvalue is not there to store the value it gives error. So, answer is d.

[@004_it_ajay_veerabaghut5]

@@matlapudipavaneswarsatyaap2667 Yeah I thought the is B .because lvalue divide like this a++ /+ /++b 🤔

[@pradoshkumarrout519]

They have no spaces. Between them so lexical will find the second (++) right after the first (++) ends.

[@matlapudipavaneswarsatyaap2667]

@@pradoshkumarrout519 no bro

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[@TheFeaturedGuy]

the last question answer is an error because in token generation we get |a| |++| |++| |+| |b| in this case we are getting a++ ++ = (a+1)++ here (a+1) is a rvalue which is not allowed for increment so we will get an error.

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The answer is definitely d. Thank you so much for the great explanations

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[@viveksai8893]

Answer for the given homework problem is 8 and thank you very much sir for helping lot of students to study through this course

[@gnanyadapa9666]

It's error.

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[@noindamster3581]

[a] [++] [++] [+] [b] is error as no operand for 2nd [++] so is it possible for lexems to be like this? [a] [++] [+] [++] [b] because it has a option to either read it like [+] or [++]

[@poornachandra3138]

Hello

[@shreyaskulkarni526]

2:43 it always matches the longest character sequence, so their is no option read it like + or ++, it will read it as ++ and not +

[@rohannayak3827]

SO ANSWER IS SAME 7/ERROR

[@anuj_chaudhary_2430]

@@rohannayak3827 nups may be its 8/ error...still confused

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It's the first way and the answer is error

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The answer was 8 for homework question sir

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it will produce error! thanks for this course, you're really great..

[@addictiveguitarist6811]

Sir, you are great 😍.....i really understand the concepts deeply taught by you 😁. The answer will be for the last quest .|a| |++| |++| |+| |b| This will give error because it is unvalid expression 😁

[@Sweetishyam5]

Error is the last question's answer.thank you neso academy

[@rowdyghatkar]

It runs the program when we use spaces i.e a++ + ++b and outputs 8 ... Otherwise gives errors.

[@ritikshrivastava9442]

Right bro

[@ritikshrivastava9442]

@Poonam Rathore in my opinion it is the compiler error Bcoz when we are adding a+++b compiler simply generating token in that way a++ + b (I don't know how to put the value under the box in typing so I used space for clarification ) So, in given question we can think that the compiler should generate tokens in that way a++ ++ + b But what compiler do a++ but it is unable to add another post increment in it that's why it is showing error I think this might be helpful to you I am not 100% sure if someone clarify more betterly then leave a comment

[@RAVITEJAP-ss9rl]

@Poonam Rathore a+++++b in token is a ++ ++ + b. So it is same as writing [(a+1)++]+b..... And for the post increment operator lvalue is required but here a+1 is not a lvalue. So we get an error.

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[@kancharlajyothi2020]

Last question answer is Error

[@satyamgawade4244]

Q3) L value required error Evaluation (a++)++ + b Once a++ is evaluated then it becomes 4++, since 4 is not a modifiable l value, compiler will throw and l value required error

[@sreemoyeepradhan7707]

Is the correct answer for Q 3 option (b) 8?

[@koinahotahai]

No , error will arise

[@tomidebbie2078]

@@koinahotahai why

[@tomidebbie2078]

@@koinahotahai it will be seperated in tokens as a++ + ++b

[@koinahotahai]

@@tomidebbie2078 error arises

[@sungchulyonseiackr]

@@tomidebbie2078 a | ++ | ++ | + | b = ((a++)++ error at this step since a++ is a rvalue)+b