Intuition Behind Voltage

[@josippetkovic389]

This channel is SOOOO underrated one of the most underrated ones. Wth

[@DawitAlemayehu-sq6hk]

sir, since the internet is closed in our region by our government and in some places he opened the internet and I am here now and since I don't have enough time I am downloading this video and I am sure I will be flabbergasted by it.thank you for your help!!!

[@RSA_Shock]

Literally the only video on youtube that gives some proper intution behind voltage, thank you for your work

[@melakubitew8953]

This video is so underrated , I remember struggling the concept of electricity when I was in high school. I wish I had the access to this wonderful explanation.

[@sagnikacharjee41]

The last 1.5 min make me love electrostatics...... ❤

[@tejasmallick3716]

best physics teacher in india

[@piyushpathak1186]

broo your old videos are as good as new ones

[@vishujha1669]

You make physics understandable !!!! thank you so much sir , never really understood any of this just ended up mugging up formulas and writing papers ....thanks :)

[@Mahesh_Shenoy]

Hey I am glad I could help ;-)

[@animewatcher400]

​@@Mahesh_Shenoy Sir I didn't knew you were on yt since such a long time, you deserve more than just 5 lack subs

[@blanktd]

quite an old video but just so explanatory and not just concept memorization thanks man

[@brandonscott3012]

11/10 . Really impressive to see you teaching all in one take like that. Normally i see your more edited videos with the animations, they are also amazing. But it really shows how skilled you are as a teacher. I felt just as engaged in any case 👏🥳

[@balachandhiranchandrasekar8132]

Great, thank you so nuch

[@carmcal2871]

such pure fire that i have temporarily lost my vision

[@oliya_b]

Thank you a loooot!!

[@MAHABAKHAT]

I am from India but still I am your great fan

[@georgerussell2947]

thank you for this insight into voltage

[@saulivor2843]

Thank you!!!!!! I really struggled to understand this concept until watching this.

[@kabirguron1697]

You are amazing brother

[@Mahesh_Shenoy]

Thank you so much 😀

[@EveK-North]

This is an excellent video. I have a couple of questions. So, I've heard that voltage can be thought of as "electrical height" - the comparison being the role height plays in gravitational potential energy. E (electrical potential energy) = q x V, but E (gravitational potential energy) = m x g x h. So, what is the "g" equivalent in electrical systems? Do people even care about that? It's probably not an important quantity in circuits. When it shows -2C at the 9:50 mark, I'm trying to understand what this means. Because it's negative C, I'm thinking it represents electrons. And electrons want to go (electrostatic force) from lower electric potential (-3V) to higher electric potential (+5V). So, if you're also applying a force in the direction of the displacement (right to left), then why would it be negative? I understand that if you apply a force in the opposite direction of an object's displacement, that would be negative. Are you actually applying a force from left to right, but it's still moving to the left?

[@Ellen.elles21]

I believe When we move a charge Higher potential energy to the lower potential energy I believe the work done is negative and when we move it from the lower potential energy to the higher potential energy the work done is positive

[@juanmanuelmillansanchez8165]

amazing video i understood it organicly thank u !

[@shubhamhorambe7903]

awesome video as always

[@Mahesh_Shenoy]

Thanks Shubham, Please do share :)

[@shubhamhorambe7903]

sure sir!!!

[@ronitmandal7301]

Thanks sir! It really helped!

[@Mahesh_Shenoy]

I am glad it did :) More videos coming up. Please share it with your friends (whoever would be interested) and subscribe for more :)

[@vishujha1669]

your refraction derivation video was playing in my head during my boards :D

[@Mahesh_Shenoy]

haha :D.. Awesome. Glad it helped someone :D

[@ommjayprakasnath2343]

what happens when we join a conducting wire to a battery? how does the current remains constant? Is this related to transiants?

[@2UK_2UK]

See his video why pd remains same across resistance

[@animewatcher400]

Woah only 34 comments

[@kiranbhat4902]

Mahesh sir what is negative potential for example what does it mean if a point has potential of -5V

[@kauuu4137]

If the potential is negative, then it basically means that the source charge is negative. If the source charge is negative then it attracts the unit +ve test charge. So we have to apply a force that is opposite (pointing away from the source charge) to bring it to a point R from infinity such that the unit +ve test charge doesn't accelerate. We know that WORK is the dot product of F and r. So when F and r are in opposite direction the work is negative and so is the Potential.

[@Xx_Eric_was_Here_xX]

so negatives are allowed when you're talking about a force relative to some initial direction?

[@curiousphysics23]

Sir you work done without acceleration but when an external force is applied force is the cause of acceleration?so what do you mean by without accelerating

[@vachan-maker]

Its an assumption so that all work done is stored as energy,otherwise we cant say the same

[@vishujha1669]

Its interesting :D

[@ExplorerofScience]

There must be more detail in video..

[@jaredsykes1718]

A well-articulated explanation and decent video however I am discouraged and confused by the assignment of "V" for individual points in the electric field. In my understanding, the symbol "V" in electric interactions denotes Electric Potential (and consequently, Voltage/Potential Difference), and Electric Potential is defined not for individual points in the field but for two separate points, between which a test charge moves. I think you referred to those "V" values as electric potential as well. I found this very misleading. If anyone can proffer an interpretation of this, or correct me if I'm wrong, I would appreciate it as I am still struggling with these concepts. A possible explanation may be that there is an unknown charge that has been left out of the drawing, with unknown location and magnitude. And so maybe it is assumed that the audience can infer that "V" represents the Electric Potential between that given point and the unknown charge. But that wasn't so clear... to me at least.

[@vachan-maker]

Electric potential is the work done in moving a unit charge from infinity to a particular point in space in the E field of a charge.So it is defined for everypoint and therefore we can give it a "V value" to random points in space