IR Spectroscopy - Practice Problems

[@TheOrganicChemistryTutor]

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[@lubnaabdalla9925]

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[@chamomile3620]

@@b-annm5571 YES I TOTALLY AGREE

[@ahmednaeem2009]

Real organic spectro knowledge in simple way

[@lateratolosa8124]

Thanks

[@peybak]

Thanks for the video. The C=O stretch was a little off on the fourth problem @ 5:46 . I got confused for a moment ;)

[@chamomile3620]

Yuh, same

[@vanessatravieso8775]

me too! i was like looking for which had a triple bond around 2200

[@joshuahering2041]

okay good, im not going crazy, I was looking at my notes for like 3 mins like huh, then I settled for trick question, none of the above. and when he said C=O 1700 I instantly came to the comments lolol

[@peybak]

@@joshuahering2041 on a real test, the professor would have to give you that one haha. You'd have good reason to pick none of the above; I think he just slipped a little when he was drawing that 1700 stretch.

[@Jdoug305]

@@vanessatravieso8775 nerds

[@Iiix78]

I'm a pharmacy student and there is no words express how much thankful l am , I'm really understand IR spectroscopy 😍

[@annawaters3531]

Great content, however at 6:10 the signal is between 2000cm^-1 and 3000 cm^-1, you approximated it as 1700cm^-1.

[@akabuoguchidimma9565]

The same mistake was made at 10:02 Great content! This really broke IR spectra interpretation for me.

[@tr.buuvibrian8162]

That was a big error. It also confused me. This topic is too sensitive to make such blind mistakes

[@fredinaoware1459]

i was confused as well

[@minatedumo2454]

At least I know I’m on the right track for noticing it .

[@bradenwhite4356]

I thought I was going insane

[@saminanoor8094]

No one can teach this better than u... literally no one

[@AdelineMedverd]

Not kidding I was doing my class lectures and text book to try and understand problems like these for 4 hours and was getting no where then I watched your two 10 min videos on IR spectroscopy and understand it. THANK YOU

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Oh gawd allmaitee, I really needed this 18 months ago. You my dude, I trust your videos the most. It sucks that you didn't have the time to prep this before.

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This made the new content we had to learn for Chem A level a lottt more easier! Thanks!!!

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I made a 102% on my 2nd Ochem exam that was majority IR/NMR thanks to you!

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[@joannaenriquez488]

i watched this very carefully and i understand now. thank you for making it easy to follow.

[@sundaywibs99]

really apreciated your video!!! i had a test tomorrow WML!!!~~

[@directioner578]

It is easier to understand with practice problems, thank you!

[@saiamitchaddha5525]

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[@mahdimahmoudi4379]

Very nice❤ I learn it very well, you teach better than our teacher😂 thank u🌼🌸

[@aimonchok6249]

you're the best teacher !

[@bintousoumaoro8907]

For problem #4, can you clarify this. U said the peak was at 1700 however the peak was presented after 2000, roughly 2200. Is this a mistake. This confused me as I see you had the C=O in all the answers but the peak was not presented around 1600

[@frightenedusee5621]

It is a mistake

[@barbiesax7743]

Yeah it's a mistake

[@Noorussama-py7rp]

I was also confused

[@Gymgrl12]

Thank you so much for the phenomenal help you have been for me !! I do want to say though, at 6:10 you mentioned the signal at approx 2200 is a C=O stretch, how could this be so or is it that you were accidentally off on the graph? Pls clarify amazing tutor!

[@MasonHatfieldLogorrhea]

It was a slip up

[@areebtiger]

7:10 you put the carbonyl stretch at the wrong side of 2000.

[@theriverglass]

Thank you for this video! I appreciate the breakdown of how to think about IR spectra!

[@saranmunian6376]

It's very useful.. thanks . Then in the fourth problem there is no peak like carbonyl but u said like 1700 cm^-1.

[@trollfake9578]

You've painted the C=O signal as in it was 2200-2300, not 1700 :(

[@fernandocruz9882]

Wow thanks I really needed this, You are great

[@celiareg3346]

Thank you, this really helped I needed this for my test cause i'm in 6th grade. :D

[@franciscoisidro3622]

In 1:37, the option D is in alkyne terminal end, why is the wavenumber not 3100-3200? He said 2200, that’s for an internal alkyne.

[@محمدالديري-ر5د]

Thank you for this valuable video

[@b-annm5571]

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[@sukumarrakshit1714]

Good morning from India.

[@b-annm5571]

@@sukumarrakshit1714 Good day, do you know where I can find the information above while we wait for TOCT to make those videos ? I would appreciate it a lot. I do see some of the lectures from India but they are not in English.Regards

[@charlesoffiong6963]

Incredible explanation! Well done!

[@trentkirkwood4488]

Number four confused me I initially chose A but then I switched to be because it looked more like something was at 1300 than at 1700. I guess spotting errors helps learn too. Maybe that was his goal.

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[@dolledby_anj2874]

THE BEST OF THE BEST❤️ Thank you 😊

[@ericpham8205]

The ether expansion or concentration could fool the spectroscopy if not calibrate ether before measuring

[@samuelwilberforce8689]

we do appreciate. Thank you

[@yoojinshin9314]

at 6:20, I see the second curve as 2200 rather than 1700 C=O. Could you explain this? Thank you so much!

[@IsabelHernandez-cm5bd]

Glad i wasn’t the only one at 2200 this would be c triple bond c

[@MrChaluliss]

Our boy dun bunked the drawing up is what happened. THE FOOL.

[@icewind7]

you need a new glasses, that's only explanation.

[@adenoorliza8259]

this really really helps me to understand tings that is not easy to understand just by reading. I am very grateful. do you feel the same way guys?

[@souadtebbal6414]

Very intersting. How can we can compare two spectrum??????

[@JesusLightsYourPath]

Im confused because my IR chart says an OH bond is between 3200 and 3500. Not at 3000

[@camiloacevedo7516]

In my IR chart, we are given three options for OH bonds. When OH is present in an alcohol, phenols (dilute solutions), it is between 3590 and 3650. When OH is present in alcohol, phenols (hydrogen bonded) it is between 3200 and 3550. When OH is present in carboxylic acids (hydrogen bonded), it is between 2500 and 3000.

[@pi2745]

My stupid brain understood this .. thank you soooooo much ❤️❤️

[@sarahakomahmensah1449]

I know right 😂😂😂😂

[@AbdirisaaqFarah-p5c]

7:17 that C=O stretch isnt at 1700 cm-1??

[@chrislong2603]

At 9:35 how does answer choice A have an Alkane stretch? Is it because there's a CH2 bond in between the NH2 and Benzene ring?

[@chrislong2603]

Oh wait, is it because the Alkane stretch is sp3?

[@valentinaparedes6375]

Thanks a lot, you are the best!

[@fusionrage5096]

I would like to thank you for making learning enjoyable for me.

[@annikaj8021]

Shouldn't 4 be an aldehyde?

[@nightshiin78]

You got me through high school, but the real question is can you get me through college?

[@CATB33]

Im always doing that in my notebook thank you you help me

[@abigailbui5753]

thank you!

[@safiyya4238]

Thanks for such a helpful video:)

[@nasrinmeghla7270]

At no. 4, the signal was at >2000 But you said 1700cm^-1

[@lawrencekomane2152]

@6:22 the stretch is of a nitrile functional group not carbonyl

[@ramanbapir2385]

please make a video about budans theorem

[@kantconnect3626]

Hello there! Wonderful class But I do have a question. Please what is the name of that software you are using to write that!...... please

[@kibetkevin107]

Who else is having a CAT tomorrow and therefore to get some content here

[@t7salm3lm56]

What website does he use???

[@karunachourasia6084]

nice explanation sir,tnq

[@tekchandthakur2551]

Really it's very helpful

[@ggroy3157]

In Problem 4, how can the number after 2000 its about 2200 and you say that it's 1700, there is some thing wrong

[@bintousoumaoro8907]

i was going to say that i think thats a mistake on his part

[@aryakrishnab8361]

Nice and informative session..😊 Thank you Sir 🤗💝

[@windadimaramadis5034]

OH or NH ?

[@szxnv]

i owe u my tuition

[@Kimchi_69]

yeah my professor doesnt do multiple choice for the test im about to have so hopefully i remember some of this lol.

[@avamontgomery3750]

Wouldn't problem 5 be A because 2 peaks on the amine mean it is a primary amine? and answer D is a secondary amine.

[@anjalikushwaha8184]

Answer D is primary amine as nitrogen is directly attached to one single carbon and not 2. At first I also thought the same but then after looking at it carefully I realised it just looks so because of the ring it appears as if it's attached to 2 carbon but no just 1. It's been a year though!😂

[@giftsadique1806]

I did watch the "Introduction Video" but I'm failing to understand how do you know that which stretch is represented a certain functional group?

[@elijahdamien7914]

hi sir, what online blackboard do you use?

[@free_learning_for_all]

Great content ❤ Thank you so much

[@019saravanakumark2]

Please full topics of post pericyclic reactions..

[@johnvincebanjao2368]

Hi I was inspired on how you make your lesson clear and presentable but may I ask what software do you use to illustrate your discussion because I will need it to my online class I hope that you reply to comment thank you.

[@sap8nap]

In Q4, the frequency is beyond 2000... should be around 1700

[@ericpham8205]

Time signature of signature spectrum is better

[@lamaiyad9596]

THANK YOU 😍😍😍👏

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Can I know what kind of app you are using so I can use it too? Cause I need it for reporting please reply ༎ຶ‿༎ຶ

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[@briankasia]

From the graph that carbonyl is not at 1700 (question 4).

[@himangimanik490]

Very nice videoss sir

[@NewWesternFront]

but where is the ch2 bend on problem 2??

[@s.sdobledhamaka4319]

Very helpful 🙂

[@tokamostafa5022]

Thanks man

[@songohan393]

thank you very much

[@munazaahmad6063]

IR spectroscopy helps to determine percentage composition how??

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How do you make these videos? Which app do u use?

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May I know what app are you using sir?

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the goat

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[@yasminnabila1417]

Nice

[@rahamanshaik7406]

At 7:21 i think it should be 2200 with C triple bond C so none of them are correct

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[@OrgMedChem2020]

very good

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i can not understand anything. i think i have soo big problem on Organic chemistry. ( i watched IR Spectoscopy- basic introduction )

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