Esterification--Making Esters from Carboxylic Acids

[@manavshah328]

Really joe, you saved my life tomorrow's my finals and I was shivering to memorize this shit... Cheers mate

[@jOeCHEM]

Manav, I'm so glad you found the video helpful! Make sure to check out the rest of my channel / my website joechem.io for more videos + worksheets (with solutions) 100% free. But no matter what, make sure to get a good night's sleep, eat a good breakfast, and give that final hell tomorrow.

[@manavshah328]

@@jOeCHEM yes sir!! Gonna take that advice and ace the mf exam...

[@kaushikumarihami1982]

Another amazing explanation with such a short time of a period and this is what I exactly wanted. As always I wish you the best of luck in everything you do in the future. Please don't stop making amazing videos like this.

[@jOeCHEM]

This was such an insanely nice comment--thank you for taking the time to leave it, for watching, and for being a jOeCHEMist. I'm so so happy you've found the videos helpful!

[@AliaShahid-n6w]

Hi Joe, I noticed you reformed h20 as a byproduct. Wouldn't that be hydronium ion since you reprotonated h20 in the last step? Thank you for all your help!

[@user-ky6yr4tu3w]

4:15 Why couldn't an intramolecular step occur where the OH abstracts a proton from the positively charged oxygen? Is it because we're in an acidic environment which makes it more energetically favourable for it to abstract from H30+ instead?

[@WomannequinReviews]

Hey Joe, your videos are truly the best when it comes to anything regarding organic chemistry on the internet. I am just wondering, aren't the reactions in this mechanism reversible? I assume you might not be drawing equilibrium arrows for the reactions since the equilibrium will be heavily skewed to the right with excess alcohol and therefore one does not need to treat the reaction as reversible.

[@jOeCHEM]

Hi @WomannequinReviews ! Thank you so much for watching and for the kind words. And yes, I did forget to use equilibrium arrows in the course of this mechanism. You'll have equilibrium arrows UNTIL the step where you kick water off--that will be the irreversible step that will drive the reaction to the product and form your ester. And on the flip side, when adding water back in, your equilibrium arrows would be necessary up until the step where the ether part of your ester is kicked off, allowing you to recover the carboxylic acid. Sorry for the late reply, I was traveling last week!

[@anonmyous8525]

Please please I have confusion in tetrahedral step when the H bonds with OH(gets protonated)making +OH2 why is there another H bonded with it where it came from 😊

[@OnkarPawar00]

Thanks ❤

[@sanduninirodha849]

❤️

[@abazeralawad2263]

👍