[October SAT] The BEST SAT Math Trick

What’s going on y’all 🤙
This SAT Math trick will show you how to solve sat questions quickly and score higher.
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𝗥 𝗘 𝗦 𝗢 𝗨 𝗥 𝗖 𝗘 𝗦 [𝗙𝗿𝗲𝗲]
🏫 SAT Prep Discord Server:
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🏆 3-Step To 700+ On SAT Math Without Naturally Being Good At Math [Free Masterclass]
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📄 SAT Math Study Plan:
• [October SAT Math] The...
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𝗣 𝗥 𝗢 𝗚 𝗥 𝗔 𝗠 𝗦 [𝗣𝗮𝗶𝗱]
📚 SAT Math Accelerator [6-Week Prep Course]:
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☎️ 30 Minutes With John [Consultation]
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FAQ
Name: John
Where did you study - Emory University
What did you major in - Economics & Psychology
Can you tutor me - Contact me ([e-mail])
How long have you been teaching - Since 2012
Why do you decide to teach - It was tough for me to figure it all out when I was in high school, and my goal is to make it a lot easier for current students
Can you make videos on Reading & Writing - I don’t know those sections well enough to talk about them.
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[@JohnSAT]

Matching Rule : kzbin.info/www/bejne/r4rIenmpl95nqrM

[@andyzhou-ji9vq]

y=8 x=0

[@AltOurCumrade]

Bro the question you have is 9th grade level lmao even in 8th grade people know it. Is sat this simple LMAO?

[@LegesseYihdego]

😂😂I quit got me

[@ValkyRiver]

On the real projective plane, as long as the lines are different, there is always one solution. Two algebraic curves of degrees m and n intersecting on the complex projective plane will always meet in mxn points, up to multiplicities of intersections. (Bézout’s Theorem)

[@Wineblood]

y = -3x + 8 and y = 3x + 8, both straight and not parallel, so one intersection.

[@Night_Hawk_475]

That's how I did it, I prefer methods that are easier to visualize, because they're a lot easier to remember, even if it takes an extra few seconds to do.

[@mariam_ah]

and if you are really strugglign cant u just graph it and count?

[@randono213]

That’s the same way I did it

[@randono213]

@@mariam_ahI guess, but you would still need to simplify to get the “y” by itself

[@julianavillanueva2275]

there’s only one solution since both intersect each other at the point (0,8)

[@aayudh.7749]

Okay but you need to know this. You can't have 2 solutions for linear equations. It's always either zero, one or infinitely many. If the equations are identical, they have infinitely many solutions. If, they have the same slope, they have zero solutions. and if its neither, they have one solutions. Always automatically eliminate option 'two'.

[@lanisessence2875]

you’re literally the only person who explained this with ease 😭

[@synsol5731]

You are so smart

[@mathwithmelissa617]

Great explanation!

[@2121prada]

exactly!

[@Nesyulett]

thx

[@jaydenlin3780]

In the digital SAT, you have Desmos to use as you like. This is one of those questions that you simply plug into desmos and see if the lines are the same, parallel, or cross.

[@zencigaming]

Wdym? Like desmos is in the computer you are doing the digital SAT on?

[@promaster5533]

It’s included

[@zencigaming]

@@promaster5533 Thanks

[@maarijfarrukh2019]

​@@zencigaming Its included in the SAT One person on reddit solved almost all his SAT on desmos and got 790 Its OP

[@zencigaming]

@@maarijfarrukh2019 send me the thread plz and thanks

[@wzpforall]

Identical equation = infinite solutions Same slope = zero solutions Different slope = one solution

[@smaransure2234]

y cant u just solve it normally

[@Quixler]

@@smaransure2234 Well, you have to know how many solutions there are and this is just a trick to keep in mind so it is easier to know how many solutions there are. First, find the two equations for the graph and then use this method. Trust me, it is very helpful.

[@ashton1241]

so what would be the slopes in this equation @@Quixler

[@loganlloyd6930]

@@smaransure2234time

[@chrisusedtobetheman8.079]

Quite helpful!

[@justaiza]

the E got me haha

[@jasonPKT]

😂😂 same

[@elapsefn2788]

you can just put it in desmos and check at how many points the functions intersect

[@johnathanpatrick6118]

E) I quit...wow. 🤭😂🤣🤣

[@loganxavier]

Two different lines that aren’t parallel will always only have one solution

[@gaminghellfire]

That's right, but a line on top of a line segment are not parallel but have more than 1 solution.

[@Tirelesswarrior]

Why does SAT give the "I quit" option?😅😅

[@besson_archer]

or, just put the two equation on the desmos and see how many intersections they have or not..?

[@srini7371]

Bruh just use, • a1/a2 = b1/b2 = c1/c2 then its infinitely many solutions • a1/a2 ≠ b1/b2 then its one solution • a1/a2 = b1/b2 ≠ c1/c2 then its no solution

[@adaaaa6642]

Solved in seconds by this method.

[@autumnsky4220]

How do u find a1 b1 and everything else?

[@adaaaa6642]

@@autumnsky4220 They are coefficients of x1,x2,y1 and y2.

[@autumnsky4220]

@@adaaaa6642 ohhhh thxx Btw, what is the c? Is it the y?

[@adaaaa6642]

@@autumnsky4220 It is the constant.

[@greaterdanemark2397]

I really wish they’d word these questions in a more clear manner. It makes it so easy when someone just tells me what the question is *actually* asking

[@carultch]

How would you reword this question to make it clearer? It seems to be clear enough to me.

[@devyanshyadav193]

Can’t we like do this on Desmos?

[@Jazzyjihyo]

lmao desmos is so over powered I love it (collegeboard dont see this)

[@amoghsv557]

why do you have to complicate it? just try to visualise it in a graph in your head. It's zero if they're parallel, 1 if they're not, and infinite if they're the same line.

[@gregoryharlston0602]

most students are HORRIBLE at visualizing! It's great that you can visualize but most students can't do it! So he isn't complicating it for the majority of students. His method is much better than visualizing!

[@amoghsv557]

@@gregoryharlston0602 I see. If you consistently use desmos, I think you'll get better at it.

[@awvz_1194]

Why tf would you possibly do it this way? Memorizing "rules" like this without emphasizing why is partly why we have so many mathematically illiterate people.. smh

[@ibraxiv-_-6653]

If you draw two lines you get 3 possibilities: they either intersect ones, infinitely, or never They intersect once if the slope (or the amount of tilt) is different. They have infinite solutions if it’s two equations for the same exact line (the values in the simplest form are the exact same) They have no solution if the lines have the same slope but start at different points. To make it easier for yourself learn how to turn the equations into a standard linear equation (y = mx + b (where y is alone on one side of the equation)) if both equations have the same “m” but a different “b” then it has no solution, if “m” and “b” are the same then it has infinite solutions, otherwise it has only one

[@rensvanampting234]

Or just solve the easy system and then look at how many solutions you get

[@j.onnkay]

Yeah but sometimes the question is about the approach not the solution If the question says find it without solving it, if you solve it then you made it in the wrong way This exercise was to show some properties that could or could not be useful is other cases

[@adamgrimsley2900]

This is a poor way of looking at it. It makes no real fundamental sense.

[@Sam_73378]

You are wrong about the first one, the criteria is that the ratio of coefficient of x and ratio of coefficient of y should not matching.

[@adhd8202]

exactly

[@r22gamer54]

OR, you could just put it into desmos :)

[@Roxve]

y+3x = 8 (1) multiplying (1) by 2 2(y+3x) = 2y+6x = 2(8) = 16 (2) 2y - 6x = 16 (3) adding (2) and (3) 2y + 6x + 2y - 6x = 16 + 16 = 32 4y = 32 y = 8 replacing y in (1) y + 3x = 8 8 + 3x = 8 x = 0 thats how I would have wrote it in an exam, it's really easy to see in like 3 seconds

[@TheYapperDaily]

how to never get it wrong... use desmos

[@ragavireddy570]

We don't need to solve the equations to get the answer. For ex: The equations are in the form of ax +by =c and a° x + b°y = c°. So we just need to find the values of a/a°, b/b° and c/c°. If 1) a/a°=b/b°=c/c° then the equations have infinite solutions as they are basically the same lines meaning they coincide at every point. 2) a/a° ≠ b/b° then the equations have one solution as they intersect at only one point. 3) a/a°=b/b° ≠c/c° then they have no solutions as they are parallel lines and never intersect each other. So in this question, a/a° = 1/2 b/b° = -1/2 c/c° = 1/2 As a/a° ≠ b/b° , the lines intersect at only one point thus they have only one solution.

[@AgarioGameplays]

Y+3x=8 2y-6x=16 Y = 8-3x So we replace 2(8-3x)-6x=16 Then 16-6x-6x=16 Which gives us 0=12x So x=0/12 so x=0 Then we plug it in to the first equation y+3(0)=8 therefor Y=8 and X=0. So there’s one solution

[@marcosnead]

¿Cero no sirve como solución?

[@Bagel937]

@@marcosnead they only plugged the 0 back into the equation to check to ensure that 0 was a solution. A solution is only the x value, the y value just confirmed that the x value is true (it solves the equation).

[@ritvikdevireddy8614]

u did not need to do all that just multiply top equation by 2, cancel the z’s ur left with 4y = 32 y = 8 so by then u know there’s just one solution so u got ur answer

[@ritvikdevireddy8614]

cancel the x’s*

[@luvlaur3n]

@@ritvikdevireddy8614there’s many different methods to solving equations like this, and some make more sense to others

[@0-to-Hero-hub-hridanshsurana]

x=0,y=8. It's over.

[@KS-ol1gh]

Just put the two equations on desmos and see how much they intersect

[@AnuragMitra-qm3tn]

We get such qs in class 10 bro 😂

[@liammoore1066]

y + 3x = 8 2y - 6x = 16 Easy trick: Since 16 is a multiple of 8 by a factor of 2 just multiply the entire first equation by 2. Set the new equation equal with the original second equation and you get 2y + 6x = 2y - 6x Next subtract 2y from both sides. Now 6x = -6x So just by plugging in a few numbers you should see that zero is the only number that fits.

[@yobamayobama8940]

I did that method too but I think what he did is a lil faster

[@Kawamata123]

Good job. At the -6x = 6x step, you can add 6x to both sides...then 12x = 0. divide both sides by 12 and x = 0.

[@liammoore1066]

@@Kawamata123 Nice way of finishing that!! Couldn’t think of a way to put a proof to the end!!

[@62mainstreetnewarknj58]

what if none are matching

[@Hola-rx1jy]

M=-m implies they are perpendicular meaning one intersection hence solution

[@anon-a-moss8960]

Another thing to know is that you're working with two linear functions, which can only have 0 (parallel or same slope), 1 (for an intersection or different slopes) or infinite solutions (if both are the exact same function). Two solutions is impossible.

[@alexdfries]

Or just plug in the first equation to the second and just getting the point of (0,8)?

[@jaxoncr]

that doesn’t guarantee it is the only solution, there could be infinitely many as well, namely scaler multiples of that solution

[@liamdavid5696]

At my school I did these types of questions in year 10

[@AR-jn6re]

OR JUST USE DESMOS😅

[@anketmohadikar8767]

man is this even a que like everyone who know math can solve thia orally ,,,

[@flashgenious8389]

Dude it’s two lines unless it’s parallel how would there be more or less then one intersection it doesn’t have exponents

[@carultch]

Playing devil's advocate: Trigonometry doesn't have exponents, and you can have lines intersecting trig functions that have 2 solutions.

[@greentomato9829]

Integrated graphing calculator goes crazy on these questions 💀💀💀

[@j_jayden0719]

Can you use them during no calculator portion?

[@greentomato9829]

@@j_jayden0719No but these questions come up on the calculation portion

[@bruhmoment3169]

You dont need calculator to draw this graph its one of the easiest graphs to draw

[@J77H]

DESMOS

[@CalculusIsFun1]

Two straight lines which are not parallel can only intersect at a maximum of 1 point. It cannot be infinitely many or two, and the equations do not have same slope with a vertical phase shift (no solution) so it must be one solution. Takes like 1 second.

[@CindyBazzar]

You could just put both equations into the desmos calculator and see how many times they intersect, if they intersect once: one solution, if they dont intersect: no solution, if the lines are on top of each other (same line): then infinitely many solutions

[@crosh3301]

Just make them slope intercept form and imagine it in your head. Like a rough shape you know

[@mortuusponduus7879]

Dude why are there so many dumb tricks and trinkets you got to solve SAT problems these days, just recognize their linear and not parallel and move on,

[@krunalpatel9811]

Only solution is x=0 and y=8. Put x=0 so y=8 in first equation and 2x8=16 since x=0. The only one solution is possible by just looking at equations.

[@roshangaul45]

Bro its a linear equation no way it has more than 1 solution. If its a quadratic equation it will have 2 solutions

[@abhinavsood2670]

You are wrong. Two parallel lines have no solutions and 2 overlapping lines have infinite solutions.

[@AnanyaSaxena-t9v]

Bro is this American math? We literally have a formula for this in our books provided by the school. First of all, general formula for all linear euqations: ax+by+c=0 If u have 2 Equations, take 1 as: a1x + b1y -c1=0 and the other as: a2x + b2y -c2 = 0 Now, just take coefficients of x, y and take c: a1/a2, b1/b2, c1/c2 If a1/a2=b1/b2=c1/c2, the lines are collinear (have infinite solutions) If a1/a2 = b1/b2 ≠ c1/c2, the lines are parallel (have no solution) If a1/a2 ≠ c1/c2, the lines are intersecting (have 1 solution)

[@raghavpopli5805]

Cramer’s rule in 2D basically

[@itztigerbtw5766]

Bro it can be solved in less than 15 seconds. Multiply the first equation by 2 and then you would realize its different slope so its one solution.

[@pjhgerlach]

Never learn tricks. Try to understand what's going on. Rewrite both as y=....

[@himanshukataria6300]

JEE aspirants dont even need a pen to solve these SAT questions

[@rajharssh]

it's obvious. our education system is much advanced (academically) compared to them, we learn much more and much deeper at the age they do these simple questions, BUT they have a better overall development. (sports, music etc)

[@TuringTested01]

@@rajharssh and they are gay as well so thats a bonus

[@rajharssh]

@@TuringTested01 lmao

[@jassimarsingh6505]

Yeah but you guys are robots, 0 life

[@oswaldhiren0610]

wait till u find out about english section😂

[@adw1z]

This is stupid, just solve the equation instead of teaching some obscure rule that bears no relevance of intuition whatsoever u can clearly see the lines are not parallel so there has to be 1 solution exactly OR, solving: 2y + 6x = 2y - 6x (= 16) ==> x = 0 ==> y = 8

[@cherry-tq7yc]

there is so fucking way you get asked this shit in american how doesn’t everything get full marks 😭

[@Triloche]

Bro this is 10th grade easiest maths in india

[@orlando5789]

Wouldn't it be easier to multiply the first equation by 2 and add them? You'll get 4y + 6x - 6y = 32, so 4y=32, y=8, x is 0

[@Neymar-cd6zg]

What if The x portion and number portion are matching

[@unlait3163]

I'm starting to see why americans struggle at math so much... Why complicate such an easy problem...

[@guessWHOOO111]

y+3x = 8 2y-6x = 16 Multiply first equation by 2 to get 2y+6x = 16, subtract both equations to get 12x = 0. Solve to get x = 0 Plug in 0 to y+3x=8, y=8.

[@brominete9]

I mean... You could just punch it in ur gdc. Or just look at the equations. They are straight lines. So ofc only one intercetion

[@mattb5634]

Been taking linear algebra so Gaussian elimination was my first bet this neat

[@diablominero]

Or you could solve the system of equations and not waste brain space on this "matching rule" nonsense?

[@dd-6497]

I'm not convinced by this as your rule ignores the x coefficient. Surely the important thing is how x relates to y (the gradient). Since it's 2 straight lines if the ratio of x to y is the same in both equations they have the same gradient and so are parallel with no intersections. In this case they don't have the same gradient so there is one intersection. Alternatively rearrange into the form y = mx + c to check if the gradients are the same. Your answer is right but your method doesn't work.

[@dawnsclim4382]

Here's what I did: y + 3x = 8 2(y + 3x) = 16 2y + 6x = 16 2y + 6x = 2y - 6x 6x = 0 So y = 8. x = 0. Answer is 1.

[@SATMathVideos-wk7dx]

way too much thinking. If two lines on a plane have different slopes the answer is always 1. Done.

[@ELSAMRAS1]

Or just see the slopes of the lines and to the slopes are not the same. Sooooo there’s 1 solution.

[@whitefeather8387]

As someone who is from asia i cry when i see these questions are for entrance exams😢😂😅

[@hank1519]

He's wrong. It has 1 solution because the ratios of the x and y terms coefficients do not match!

[@dicksonudoka6504]

Option E?? 😭😭😭😂 Sat questions are starting to get mean 😂😂

[@Amadare-cj1gv]

Brainrot solution. Doesn’t give any understanding to a student

[@smashliek5086]

I''ll just use Desmos

[@carultch]

How the hell is Desmos allowed on the SAT?

[@Suekru3]

I just took linear algebra so my brain just ran through it in matrix form.

[@theonerealtemp]

or just plot it on desmos and see how many places the two lines intersect..

[@dr.tetraminflakes3187]

one half and neg one half is 0 not one half

[@orange_turtle3412]

Or just put it in desmos and save yourself the brainpower

[@pravarmaurya2490]

This question was written directly in the class 9 NCERT.

[@adisb07]

It is literally in 10th standard linear equations in 2 variables

[@MRulli427]

Just graph it in your calculator or Desmos, hella easy

[@thatguy720]

The x only has an exponent of one. The degree of the function is the number of solutions it has.

[@armgrease]

Just use substitution by elimination. Multiply the top equation by 2, cancel out the x'es, and the add the two equations together. You'd get 4y = 32, so y = 8. Plug that back into any equation and x would make the equation true, making it one solution. This is standard teachings on ninth grade algebra 1 so anybody taking the Sat's should know it.

[@Krebzonide]

You forgot to multiply the 8 by 2

[@armgrease]

​@@KrebzonideWhat? Where do I have to do that?

[@Krebzonide]

@@armgrease When you multiply the top equation by 2 the 8 on the right side becomes 16. Add the two equations together and you get 16+16 = 32. I assume you missed the multiplication and did 8+16 = 24.

[@armgrease]

​@Krebzonide Oh your right, sorry, I'll edit my comment.

[@reyaan7]

One solution 😮 if someone getting it hard than just draw line n see

[@atharvaplayssoccer]

or just use your resources and use desmos......

[@AnkitMishra-34]

Indian 10 th grader maths problem lol😅

[@dread2159]

That's SAT questions. A kid can do that

[@erenshaw]

fundamental theorem of algebra says one

[@irene7041]

is i quit actually an option in SAT LOL!!

[@AditAgrawal-n3k]

bro this is 9-10 class problem in India

[@foot-gaming2137]

bro I did it in Desmos in 2seconds

[@notanigga829]

That's not something it is taught to everyone in class 10

[@_0O7RONALDO]

This is something I learnt in 10th class

[@helloo_oo_]

what is SLAP sir in graph question

[@chukwuemekanwokoye8759]

What if you have none matching?

[@bemore2886]

Ok now i know for future video quiz

[@Sani_m453]

Students learn it in 8th grade 😅

[@runup454]

Just use the fucking desmos

[@adamgoudreau7069]

Or just use the desmos on the digital sat

[@theavgguy3555]

just use desmost lil bro

[@roopeshramagiri7751]

For linear equations , we will be having only 1 solution for each variable.

[@justarandomstudentman6355]

Or just shove it into desmos💀

[@YaswanthSai-yl1np]

Bro thats 9th grade math in india😅😅

[@TARUNV-bo5nu]

. just desmos that thing bruhh

[@prateeshsingh5222]

Just use desmos😂

[@optimizegaming8475]

This is class 10th question

[@kimberlylaguna4272]

Just use seamos for these

[@DalM-xb4kf]

F