Projections onto subspaces | Linear Algebra | Khan Academy

[@ojussinghal2501]

Amazing that these will always remain relevant.

[@celinakward2897]

Usually, I like Strang's lectures better than Sal's for Linear Algebra, they just seem to paint a better picture in my head. But for this particular lecture, Strang's was a bit all over the place (in my personal opinion, anyway) so yeah, Sal's lectures are very good in the sense that they tend to follow one direction the entire time. That can get a little boring at times, though, but I guess it's what you get with online lecturing.

[@forpublicstuff728]

Just came here from Strang's lecture (PROJECTIONS ONTO SUBSPACES) - got to admit that it is somewhat messy=)

[@musicarroll]

At 17:00 and following you might want say that the v in the top half (for a line) is not the same v as in the bottom half (for a general subspace). Using v in both places might confuse novices.

[@SomethingSoOriginal]

Thank you very much for this, certainly helping with exam revision.

[@zenfascist]

According to the Khan academy web site, Sal studied math in MIT so he was probably taught linear algebra by Strang (Though I might be wrong..) I like to watch both the Strang and Sal videos, they somehow seem to complement each other. Sal goes through practical examples which help to clarify the perhaps bit more abstract lectures of Strang

[@DJstripe1]

you are my saviour. thank you

[@fashionvella730]

i think the reason Proj X on V = v and proj X on Orth.. Compl.. of V = w is because X is the resultant of the v vector and w vector and as we know they are orthogonal compilement of each other means all vectors which spans V and all vectors which spans Orth.. Compl.. of V are perpendicular to each other means there linear combination will always have a shadow either on V or Orth.. Compl.. of V

[@hearthacker5565]

If V is the column space of matrix A of order 3×2 with ist colum 1 1 1 and 2nd column as -1 2 -1 . Then the orthogonal projection of colmn vctr (0 1 0) on V is. Sir plz help to solve this?

[@basmaal-ghali9174]

Brilliant

[@NotmyYTchannel]

Thank yoU!

[@ojussinghal2501]

11 years down the line, I want to thank him again!

[@TheVikas88]

Sir, i need to project a circular aperture on the some 3d figure. Circular aperture can rotate in 3d space and my "3d figure" is stationary. How to do?

[@mustafaeminkorkmaz]

10 dislikes = math teachers

[@empirewhite]

16:17 wrong.... (9/13)*3 =27/13 ....no minus

[@mrpuncher100]

nice try but that's not a minus it's part of the brackets

[@dankoch5357]

@@mrpuncher100 phew bro I was tripping. came to the comments for clarification and you gave it, bless.