Conductor with charge inside a cavity | Electrostatic potential & capacitance | Khan Academy

Consider a charge q, inside a cavity of a spherical conductor. Let's explore how the induced charges get redistributed in electrostatic conditions.
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Created by Mahesh Shenoy

[@PadmavathiVedavalli]

He has covered all the advanced topics with such an impeccable quality of teaching

[@FabGamer]

Thank u so much I was tired searching about it since long and finally got this exact thing

[@piyushrajput513]

Me also bhai

[@boopeshkumar9752]

The charge distribution on the outer surface doesn't depend on the charge distribution on inner surface so outer charge distribution must be uniform

[@bhartikumari4167]

Thank you….I was searching this for a long…I always used to get confused and even no one has explained this concept….finally the concepts are clear!!

[@yash1152]

really nice video in that it covered it from basics - i had only memorised it, but thanks for going in details without all the jargons and hype that other coaching institutes create

[@Raven_hustles]

Had tears (of happiness) finally I got it sir. I love how you raise questions and tell us to think about it. ❤ Amazing teaching 👏🏻 stay blessed

[@SamiulIslam-z3d]

Such a nice explanation, I couldn't even understand a single thing by reading my text book for the 5th time....Now everything is clear.

[@suhai8830]

Physics always leaves me speechless 💯

[@jays6430]

Much precise, detailed and well explained than most of the videos out there on the same topic. your videos clear doubts instantly! keep em coming.

[@gurleenkang6337]

Why I didn't know this channel before?? The video is so clear and easy to understand!!! Thank you very much

[@bosslovely27]

You are one of the greatest teacher

[@preritsharma329]

Fricking hell.. this is JEE Advanced level content right there, cleared all my doubts which i had on this topic! TYSM! Tho i may have a doubt, is it possible to calculate the electric field's *value* inside the cavity? I think not, but i am not sure

[@badpineapple9120]

E=0 inside the cavity. Sir said in the video By taking gaussian surface as any spherical surface inside the solid sphere, electrostatic force inside gaussian surface is zero. Thus electric field =0. Refer 3:20 for more info

[@preritsharma329]

@@badpineapple9120 i am not saying inside the conductor, but the empty part between the charge and conductor

[@abhirupkundu2778]

the field inside the cavity originates due to the positive charge, which means at any point the field is Kq/r^2 inside the cavity until you enter the conductor

[@abhirupkundu2778]

@@badpineapple9120 you got it mixed up

[@abhirupkundu2778]

the field inside a cavity is due to the positive point charge only, which is equal to Kq/r^2 at a distance r from the charge as long as you are outside the metal shell

[@Mr.D-r2r]

outstanding work, talking as a physics teacher

[@jcamargo2005]

This result is remarkable. I remember seeing this in Physics class but as usual throwing out all the amazement.

[@AtsukoPrice]

How'd he get the cursor to have two fingers pointed out :0

[@AtulyaRai-gm2hc]

Wow extremely clear explanation. The only video i found that covers this topic in depth.

[@avnishpathak1510]

Also positive charges are immobile in a solid conductor

[@padmavathivedavalli2639]

Thank you sir

[@PrabhjotSingh_24]

sir please organize your videos, it's a humble request

[@yash1152]

head over to the site mentioned in the descriptions - there, the videos are verry well organised

[@Rohan-e7t]

In this video there’s a minute error, the electric field in the bulk of the sphere is not canceled by the opposing field from the +Q charge on the outer surface. According to the shell theorem, the electric field at every point inside the sphere due to the charge on the outer surface is zero. The electric field inside the bulk of the conductor is neutralized because the induced negative charges on the inner surface cause the field lines originating from the +Q charge inside the cavity to terminate on the inner surface.

[@PW_Rockstar]

LOVE FROM UGANDA KI KALIGHATI 😌🔥

[@Ultimatemaster_026]

Best explanation

[@vedamurthyc2123]

I am grateful to you sir❤

[@irwanahmed001]

you're a lifesaver thank you

[@anilsurjewala3606]

I fell in love with your video every time

[@physicsnotesa.k.s5369]

[@dvsalim09]

What if the sphere is grounded, would it have the same results? Please answer as soon as possible, Ty

[@Jahnavi120]

Your explanation is very helpful...thankyou so much🤗

[@chalkaholicasmr6823]

Explanation can be to the point and not take longer time

[@AnkitPal-p9c]

Mazza aaya!

[@AnkitPal-p9c]

Literally terrific explanation

[@hersheysgupta]

great video! We need more educators like you

[@jlpsinde]

Amazing video! Thanks from Portugal

[@PW_Rockstar]

Really 😶😶😶

[@md_altaf_wasim]

Thanks

[@jothibaskarn887]

Sir excellent sir, organize your videos sir

[@ryanthegooch5952]

THANK YOU!

[@chandrikakhooha1173]

Superb

[@RitumbaraSaxena]

I am so much confused about this topic but thank u so much for solving my doubt🤩

[@naduninelumika3337]

Thanks it helped a lot

[@precisionmedicine9091]

Really got a charge out of the lecture, you have great energy.

[@factsss7]

Outstanding amazing mind blowing sir

[@AwaisKhalid-y9r]

but what if the charge is placed at the centre then the negative charges would be uniform right??

[@ChronicleBlaster]

Thanks a lot

[@brighttips8203]

thnks sir

[@princeverma673]

will there be any charge induced on the outer surface of the cavity?

[@ranjeevramprasad6672]

Mahn ur just too gud pls continue this good work

[@brendawilliams8062]

Thankyou

[@nutanpanpalia4170]

Thankyouu

[@albertomontecarlo6231]

Hi. I like your videos. I’m following a electromagnetism and I think that this problem (which is the Faraday ice pail) explain together different properties. As a person that is learning I don’t feel that your explanation when you say that the “outside word” is disconnected from the inside because you can imagine a Gaussian surface and so there is no flux through is the best explanation.. don’t get me wrong you can explain with Gauss law but I would try to give a different explanation without Gaus law of why outside there is not other option than uniformely distribution charge..

[@sulochanasaroj8639]

Nice explanation

[@sunakshi_m]

Thnku sooo much sir nd hatts of to your commendable teachingg

[@srisaisubramanyamdavanam9912]

hush finally my doubt is solved

[@pedrokogawa8191]

Hi, does that means I have a field equal to the resonance field outside of the room (faraday cage) but more scattered ?

[@darkrai2065]

Sir will you cover capacitor and capacitance also.?

[@jayasimhankrishnamurthy2245]

How the positive charges are supposed to gather around the conductor if there's no electric field in-between them or they're disconnected from the inner postive charge? Can someone clarify this?

[@ranujena784]

In case of neutral dielectric sphere wht happen??

[@milanrai3607]

So what is the field inside the cavity?

[@JeevaNandhan-x2o]

Why

[@JeevaNandhan-x2o]

​@@yajumbagang1596 for any point inside the sphere conductor electric field is exist, then how it would be zero?

[@tarandeepsinghkhurana2874]

Sir i have a doubt, let's say the cavity is of an irregular shape then the charge distribution on the surface of cavity will depend upon the position of point charge inside the cavity or on the local radius of curvature of the cavity ?

[@navkhr352]

Depends on the position of charge inside the cavity otherwise electric field won't be zero Centre of charge of non uniformly induced charges (-q ) on surface of cavity will lie on the charge (+q) inside the cavity (off centre here) so that E=O inside the material of the conductor

[@saksham21990]

Simply awesome. Please create more such videos on difficult concepts.

[@nishok3502]

Thank u providing us quality education bro

[@plonksmag2686]

The electric field inside the conductor should be zero but doesnt the field lines between the charge q and induced negative charge indicate an electric field??

[@samramzi4639]

A spherical conducting shell, centered at the origin, has inner radius a and outer radius b. Its net charge is zero. Inside the shell, on the x-axis at at x = a/2 there is a point charge q. Which will be the direction and magnitude of the electric force acting on the point charge?

[@alongwithsangita]

Is the charge on outer surface same as in centre or Different?

[@navkhr352]

It has to be same

[@yashchandra633]

How to find potential at centre?

[@seshareddy1235]

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[@kaydenbreak-wo4xj]

Such a Nice voice😂😊

[@Subramanyam-go2wv]

Explanation is everything good....but while listening into another English accent feeling difficult to hear....

[@NOTHING_In_]

It's probably the laziest video you ever made

[@malharpatil157]

Avoid that cheap accent 🙏

[@Noah-jz3gt]

thanks a lot

[@ritankarmondal0411]

Thanks a lot