Active, saturation, & cutoff state of NPN transistor | Class 12 (India) | Physics | Khan Academy

[@KhanAcademyIndiaEnglish]

Hey, here's a dedicated CBSE course on our website where you can practice all the concepts related to this video and more. And oh, it's always free. www.khanacademy.org/science/in-in-class-12th-physics-india/in-in-semiconductors

[@nerd3350]

I have a question here when the critical state of transistor us achieved Vce is 0 then .... wouldn't that be a forward bias between collector and base so there should be a net flow of electrons and it is that part of the curve which is not parallel to voltage axis

[@VndNvwYvvSvv]

What does "fie wold" mean?

[@bookspa_4942]

you guyes are gem

[@mahmutkoroglu7072]

This is by far the most understandable and usefull electronic tutorial I have ever watched. You are blessed with an amazing teaching skill.

[@RoseDeWittWish]

same to me

[@tanjiro3285]

Yup bro

[@piyushyadu6663]

Yup. He makes the best simply understandable concepts.

[@grjesus9979]

I'm studying telecommunications engineering and no words to say. This is perfect. Easy to understand, just what i need. Thank you for your good job.

[@12akul]

I've been trying to understand the basic concepts of transistor for years and this has definitely helped alot. Thank you🙂

[@RoseDeWittWish]

same to me!

[@eventhorizon7267]

Same

[@samsamm777]

This whole transistor series of lessons was superb! I think i finally grasped a decent understanding now!

[@KennehGebra-cf9ds]

To answer your question. You: I hope this makes sense ? Me: it makes more than sense.

[@aabhasdhaubanja1184]

The application of the cutoff mode and saturation mode is a switch. I finally understand, Thank you!

[@Cosmos0000]

your entire series on semiconductors has been invaluable to me in understanding the basics. Thank you!

[@BharathinfinityHegde]

It would be great if someone could clear my doubt - We increased Ib, so Ic increased but Vce decreased. And so we are trying to find till what we can increase Ib to, so that amplification still happens....but according to what you said in the last video, after Vce decreases below 0.7V, the base-collector gets forward biased and for amplification process to happen we must be in the right side of the output characteristics graph. So for the active state shouldn't 0.7

[@KhanAcademyIndiaEnglish]

You are absolutely right. I oversimplified it.

[@BharathinfinityHegde]

@@KhanAcademyIndiaEnglish Thanks a lot for clearing that! And these videos are great. I tried multiple resources but never understood this chapter properly, until i found these.

[@srivatsaa.r.9936]

SIR / KHAN ACADEMI Just now i watched yr video on TRANSISTORS (NPN)--CUTOFF, SATURATION AND AMPLIFICATION REGION. Liked yr video AND U TAUGHT VERY WELL. U EXPLAINED CLEARLY AND I UNDERSTOOD WITHOUT A DOUBT. YR WRITINGS VISIBILITY, EXPLANATION SOUND ALL EXCELLENT. THANKS VATSA

[@obrigadoamigo]

I watched 3 videos on the subject before this. Superbly done!

[@md.rokunuzzaman862]

very helpful sir, I had watched a lot of video on youtube about saturation of transistor but I did not understand the saturation of transistor clearly.many many thanks for understanding this lesson easily.

[@jakenbaked87]

This definitely helped explain the saturation region a lot. The saturation and cutoff regions can be used for oscillators -- in coupled transformers positive feedback to the base using an coupled inductor is the basis for ring choke flyback transformers

[@deepakpaliwal3564]

Without a single flaw you explained this very well

[@whiskyguzzler982]

Some Eureka moments for me in this video. Thanks.

[@niranjan7457]

Sir, at 07:47, the Output Voltage has become 0 Volts This means that the Input voltage is greater than the output voltage So the reverse biasing has stopped and Forward bias has started, right?(As the P type is now connected to a more positive than N type). Which means the transistor ceases to amplify

[@justinsantos5751]

I agree. I guess there should be no current but why is there still I_c?

[@Hino_55]

Finally understood the concept! Thanks Sir Mahesh! :)

[@moumagarai451]

I loved the colour factor you used,it made it easier to understand..thnks :)

[@DearMajesty]

One of the best videos on this I have seen. I'd just like to note that many courses like to use V_ce = 0.2 V for sat and that V_be = 0.6 V for anyone watching. Thanks!

[@Yusuf-dx4hw]

This is the most understandable explanation I have ever seen in BJT topics

[@musthafaaltaf505]

Typical Khan academy style. You nailed it my man.

[@hiteshmourya1719]

Sir you are the best teacher who teaches about the transistor working

[@MuksEmmaN]

This channel deserves way more views You a legend sir

[@shaikrafiq9498]

Ur amazing sir .. so happy to have u as my mentor🙏🙏🙏❤

[@bitanbasak8274]

Very very thanks sir.I struggled a lot to understand transistors but after this I realised it's quite easy. Your teaching style is awesome sir. Respect u!!🙇🙇

[@stevenlee1637]

This is so good omg

[@alexp6869]

Excellent! Crystal clear presentation, idea by idea. Best transistor modes vid I've seen so far :)

[@vaibhavpatel8553]

This vedio is great 👍 . I clear my confusion regarding modes of operation for transistor after watching it .

[@purushottamdahiphale3696]

Toughest topic I have ever studied in physics

[@vedsengupta]

Thank you so much, understanding electronics has never been easier. A very lucid tutorial!

[@datchentai3047]

This is a very excellent explanation. It really contributed to my overall understanding of how the NPN transistor works and the accompanying technical vocabulary. Thank you very much!

[@hieuphamvietminh4655]

Thanks so much for your absolutely helpful lecture sir.

[@tozinikki]

Just what I needed clarity on 🎉❤

[@RVcollections19]

This is very good.and at last he teased digital switches which is very interesting.

[@coloradowilderness3139]

I have read Boylestad + Floyd but failed to understand in short time. Your single 13 min is enough to understand Operation of Mode. Thanks

[@Abhisar_Gupta]

Absolutely amazing explanation sir.. ❤❤

[@conteudocv685]

I learned in 12 minutes what I didn't learn in 1 hour at university. Thankful

[@mark-qi6di]

Wish I had seen this video much earlier... Thank you, super clear explanation.

[@nimeshraijada5844]

Simplified explanation. Very Good 👍

[@danielsims5771]

You are the best. I do not have any questions after watching your tutorial. Thanks a lot

[@akshithraj9584]

his voice is really great and the way he speaks makes me to listen and stick on to the video till the end !! great sir keep doing videos on many different topics in electronics subject

[@YLprime]

by far the more useful video i came across.

[@sandeeppinninti3087]

Really thank you soo much I want to understand this from many years but now with this video it's very clear

[@tanjiro3285]

Awesome man, hats off to youtube Algo.

[@bsand1746]

Thank you sir for your effort, please continue if you wish🙇‍♂️👍

[@jeffreychavey4161]

just like Khan math --> well done. thank you

[@shaikrafik6300]

Sir ur subscribers are incresing

[@nazmunnahar9572]

Amazing, thank you khan

[@Sagar_the-rise-of_king]

your video is so good from 1st video to end video,,,,yyou are a legend;;;

[@settings4593]

This has to be appreciated. I can't thank anymore.

[@ayushmandutta3204]

Mahesh shenoy sir you are simply great!

[@krunoslavmikus3496]

Great lesson, very good teacher.

[@zahidfaheem3233]

Best explanation! Thank you!

[@pcbekri340]

i mean there can't be a better explanation than this one most of the videos that i've saw are way too complicated and not comprehensive at all unlike this one thank you from the heart man

[@niranjan7457]

Sir another doubt... At 11:10, you have said that for the transistor to work as an amplifier, the Input Current has to be within a rang. But in the 3rd case, even though the Input current is greater than 30 microamperes (outside the range), the output current is 3 milliamperes (still almost 100 times the Input current). So doesn't it continue to be an amplifier Because the condition for an amplifier is that the Output current must be much greater than the Input current, and the condition is still satisfied). Kindly clarify this sir

[@furiousarpan7473]

Yeah but you're not getting an amplified current as you're supplying more current from base region..

[@MauxX]

Simply... Thanks

[@totscastle3772]

Thanks a lot !!, Very well explained!!. I think this is the easiest explanation I have found on the Internet.

[@suhailbhat1996]

In saturation we say Transistor acts as closed switch. That is collector current = emitter current. But wouldn't emitter current be equal to base current + collector current according to KCL. why we assume it directly equal to collector current alone?

[@cecilgeorge3849]

Excellent Explanation Congrats

[@garysewell5465]

Simply put, great video, thank you.

[@hashansameera2763]

woooow,, thank you sir @LK

[@shivaashish5901]

Amazing lectures!! Really pretty detailed information in a very understandable manner.What could we want more than this in physics👌😀

[@naasifn]

I guess saturation, & cutoff can be used as a NOT gate.

[@thomasvarghese4085]

Great Guess. Close..ie a switch

[@richardwhalen1859]

Great presentation. Thanks

[@ashitaserrao6676]

Its an awesome vedio pertaining to electronics ..... please put up more such vedios for students from electronics engineering background...i understood it well thanks!!.

[@carlitobrigante9740]

absolutely amazing job

[@akshitkhubber329]

Very useful video👍👍👍

[@sabarishks6089]

Best explanation.you are a great physics teacher.

[@saruulnasanjargal8590]

Wow thank you so much! Great explanation, I couldn't find such great explanation anywhere! You're great!

[@SAJAN_ECE]

This is the best explanation in this topic.

[@coloradowilderness3139]

Tough thinks make easier . Great.

[@madhumatinarule4489]

Excellent 🙌👌

[@punjdeya4363]

Very well explained sir

[@vidyadharabhyankar316]

Congratulations for creating this superb piece of video. I have gone thru number of other videos but no match

[@lkprasad100]

Thank you soon much for providing Crystal clear explanation 😊 finally understood the concept!!

[@priyap6242]

U explain in a very simple way .thanku so much Sir

[@pradyumnam7451]

Thank u khan academy 😀

[@mth32871]

Excellent explanation. Thank you!

[@mileslegend]

Thank you very much ..so clear brief and conscise

[@cardo9904]

If the output voltage is connected to a load, and base voltage is zero, will the 1k resistor will have a voltage drop? Or the Vce will get the full 3v? Thanks

[@sushmitahalder4736]

Wow 😍

[@coloradowilderness3139]

Very cleaver !

[@charuprabha4534]

Best teacher 😀💙

[@wagsman9999]

Very nice explanation!

[@entertainingasap1856]

Because of saturation and cutoff transistor can be used in binary operations .. like citoff means 0 and saturation means 1

[@KeerthiVarsith]

thank you so much

[@ankitasarkar2627]

thanks so much for such a nice explanation!!

[@vaibhavpatil-mj5zj]

Yes sir explanation is from very basic

[@sivanagaraju3665]

Your not a ordinary man

[@shawnstanley2390]

Best explanation

[@miryasadanandam5661]

Thank youuuuuu sirrrr

[@GauravGupta-pb8mk]

Thank you sir

[@bidhanthapa9076]

thankyou 3000

[@CHANDANSINGH-br5rr]

Here Vce can never be equal to or less than 0.7 volt as base collecter will become forward biased...sir u too Vce=0v minm...can't understand...plzzz help

[@KhanAcademyIndiaEnglish]

The value of Vce depends on choice of resistor and supply voltage. You are absolutely right that when Vce goes below 0.7 volt the base collector gets forward biased. This is actually where the saturation region begins. In saturation region both b-c and b-e are forward biased

[@sukritdass9897]

@@KhanAcademyIndiaEnglish Sir how can the transistor b-e (be) forward biased when when input voltage is less than 0.7 volt please explain .

[@adarshbhat8165]

@@KhanAcademyIndiaEnglish Sir if the base collector juntion becomes forward biased how will the electrons move from the base to the collector ??? How can their be a collector current even when at saturation both the b-e and b-c juntion are forward biased

[@justinsantos5751]

@@KhanAcademyIndiaEnglish How is the I_C max when b-c is forward biased? Shouldn't there be no current in the collector pin?

[@SaurabhKumar-ey2dv]

@@KhanAcademyIndiaEnglish so it means that amplification can done only in active region.

[@sarimansari9701]

11:58 I guess we can use 'cut_off' & 'saturation' to apply digital logic i.e. 1 or 0 ???

[@d.albuquerque]

excellent video !!

[@RixtronixLAB]

Nice video, thank you for sharing :)

[@darkrai2065]

God level teaching

[@T-She-Go]

You are amazing. Thank you so much 😭

[@rashmithau5043]

amazing sir.......thank you so much 😃