Interpreting M+ Peaks in Mass Spectrometry

[@DSnowaws]

These are probably the best Mass Spec explanations I’ve ever heard in my life

[@Sophia-sp7eb]

this is the first time I understood any concept in o.chem 100%. thank you sir.

[@victoriableecker8226]

2 minutes into the video I learned more than I did in lecture. Thank you so much

[@SandyLucy11]

Thank you, sir. Your explanation was splendid and cleared a lot of my misconception. Thank you!~

[@rimshakhan9684]

thank you sooo much sir. your videos helped me a lot to get these spectroscopic techniques. i must say that u did an excellent job to help students like me :P stay blessed. may you get the best reward for doing these videos :)

[@Knowbee]

Fantastic compliment! Too kind. Made my day!

[@lexibexitextinexi]

DUDE DESERVES A MEDAL FOR BEING SO CLEAR

[@khodaniganeli8489]

i thought ill never understand mass spectroscopy but i was wrong, thank you Sir!!

[@MuhammadNaeem-mm8hk]

Thanks for the kind video sir. You have made my way of solving the spectroscopic problems very interesting. May you live long sir. ❤

[@Ajtraytray]

Your explanations are simply amazing. God bless you

[@swadhinchetia2792]

Teacher should be like you. Great job. Hoping for more videos. Love from India

[@brenna760]

This is an amazing video and I needed it for my final tomorrow so thank you so much!!!!!

[@urwabajwa3502]

Life savour kind of videos🥺❤

[@shammahndzalama9731]

This has literally helped me to understand this much better ... thank you so much sir God enrochly bless you

[@user-tg1en3gk7k]

Perfect explanation, THANKS ALOT!!

[@charlesrobert1217]

Excellent teaching

[@towhidsmail]

Thank you very much for your well organized and easy explanations. It made my study easy.

[@Knowbee]

You're welcome!

[@shehanai123]

Jijo2

[@aso1569]

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[@BilalAhmad-sr5uw]

Sir you gave a lot of knowledge.thankss

[@shushayhagos3190]

No words , it is great

[@romulus2225]

great video and example sample analysis

[@rajeshkumarbehera9834]

sir it is my luck that i found your video which helped me very much.thank you

[@SonuNigamUnofficial]

you are the best teacher I HAVE ever come through in my whole Chemistry Studying life... Your are blessed with the ability of teaching tough things like Fairytales ...wow stay healthy and spread knowledge .. you are my favourite ... where to get the links to have chat with you sir .... and lastly What is your name ?? thank u so much

[@kavitadumaga1973]

Thanks sir.... It help me a lot.. Plzz prepare some more videos on organometallic chemistry

[@amandawramage5865]

I'm confused as to why pentane is displayed on the graph? I thought only ions were displayed? Pentane does not appear to have an electron removed. Can someone please explain??

[@Junior-hq3hy]

I may be incorrect but the way it works aswell is such that sometimes the whole molecule just becomes an ion due to the way an electron hits the molecule (by just knocking off an electron whilst simultaneously not changing the molecule structure) that’s what they call the parent/molecular ion (in this case pentane)

[@Theperfectblabla]

Thank you! This helped so much!

[@zahoorahmad-rt1hl]

Due to the presence of different isotopes of an element in a compound, the parents ions responded differently. How about the daughters ions? As the individual parent ion will generate different daughter ions of different m/z values.

[@tuck295q]

I think you might mixed up methyl butane MS with pentane from the previous video. The MS looks more like methyl butane one or am I wrong?

[@shammahndzalama9731]

Sir if it happens that we dont have m+1 how can we determine the molecular formula?

[@krishna795]

This is smooth. Thank you

[@ayeshasiddiqua2607]

Plz explain what will be the relative intensity of m m+2 m+4 peaks for 2Cl if present instead of Br

[@ayeshaasif20asif73]

Amazing explanation

[@akeedasharma4249]

I have a doubt. I agree that relative intensities of molecular ion peak involving both Br isotopes should be same. The doubt is that why this m+2 peak. Is there for molecular ion peak and for other peaks such as base peak. Why don't we have M+2 base peak of same intensity Pl. Answer

[@fenfentang2263]

can anyone tell me that why secondary has more relative abundance than primary?

[@joanazanchetti228]

because its more stable

[@thomasmuntzer1004]

But is there not a Chance that there are molekus that have 81br and 13C? So they weigh 125? By the way thank you very much!

[@skylersorkin6129]

thank you thank you thank you thank you

[@wgdanmourad]

you are the best

[@sammadsaeed3373]

Life saviour!!

[@dhaneeshapb3154]

Thank you sir...

[@songohan393]

thank you a lot

[@nazlikianersi727]

it was usefull

[@abrahamrivera5660]

very helpful!

[@goodluckgoody1366]

THANK YOU VERY MUCH SIR

[@Carvel]

THANK YOU!

[@shyamdedaniya2056]

literally great explanation than useless university PhD Professor

[@mohammadhamza8942]

thank youu legend

[@s.k.sameer2219]

Where 0.055 value come plz someone help me????

[@girlish911]

were trying to see how tall the M+1 peak is compared to the M Peak, so we mark our M peak as being 100% (it is 100% of its own height) we took the height of the M+1 peak (by viewing the vertical axis in this spectroscopy -in this case, we cant see it) and we divided it by the height of the M peak. That number is where the 0.055 is where that number comes from

[@koningA]

5 carbons = 5 x 0.011 = 0.055 (Natural abundance of C-13 is 0.011 % ). Because the chance on 2 C-13 is negligible (0.0001%) this peak wasn't shown.

[@dimitrisgkiousas8928]

super!!

[@chemistrysmystery8467]

Thank you sir

[@y_y1776]

why isnt the M+1 ion due to hydrogen isotopes? how exactly do you guys know m+1 peak is due to carbon isotopes?

[@kuashaahmed7513]

I need answer to this too.

[@s.k.sameer2219]

Why value pridict0.055......

[@comedydiary5988]

It's a given value for each isotope...

[@gildebertvonhaargert5327]

THANK YOU

[@benjaminhogan3157]

BRAVO!!!!!

[@mukesh2400]

super

[@mohammada4523]

What the fuck this is amazing, thank you so so so so so so so so so so so fucking much

[@rameshbanothu1058]

Tnq sir

[@kondwanimwafulilwa5521]

👏👏

[@drbalvindertalwar4749]

👍

[@uzmabatool3437]

Brilliant explanation

[@tusharmandge2899]

Thank you sir