Lagrange’s Multipliers (NLPP with 3 Variables and 1 Equality Constraints) Problem 2

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Ekeeda

Ekeeda

Күн бұрын

Пікірлер: 11
@coder_chandan
@coder_chandan Жыл бұрын
Sir your smile is awesome ❤ and teaching style is wow 😊
@mumbaikachallenge5526
@mumbaikachallenge5526 2 жыл бұрын
Sir you are amazing ❤️
@Ekeeda
@Ekeeda 2 жыл бұрын
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@raghulvallarasu6872
@raghulvallarasu6872 8 ай бұрын
Thank you sir 😍
@xavierthexavier
@xavierthexavier Ай бұрын
sir i think the 4th derivation was supposed to be done with lambda not L except that perfect explaintaion thank you
@abhishekak8597
@abhishekak8597 8 ай бұрын
Thankyou sir 🙏 You teach excellent manner 💯💯🫡
@oshot5373
@oshot5373 Жыл бұрын
Sir if delta 4 and delta 3 is positive it's minima? Or If delta 3 is negative and delta 4 is positive so it's maxima? So please Reply this comment
@flip-flops-vesit
@flip-flops-vesit Жыл бұрын
If delta 4 and delta 3, both are negative, it is minima. If delta 3 is positive and delta 4 is negative, it is maxima (alternate signs of principle minors).
@marcfernandes7283
@marcfernandes7283 Жыл бұрын
6 divided by -3 is -2, but u wrote lambda is 2
@atharvamane3045
@atharvamane3045 8 ай бұрын
Wrong value of Partial differentiate of L wrt to lambda is wrong x1 + x2 + x3 = --10
@abhishekak8597
@abhishekak8597 8 ай бұрын
Bro partial differentiation Karen ke bad -x1-x2-x3+10=0 aaya then minus se multiply Kiya so x1+x2+x3-10=0 Then minus ten shift right side x1+x2+x3=10
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