Lead Lag

[@msudandevkota6797]

Awesome explanation. Maths is not hard if you have a good teacher.

[@filip2365]

finally,no skipping,thank you

[@flaneurable]

That didn't sound like Sal but the chalks were familiar.

[@sohailjanjua123]

Hi, I like your lecture.Thanks

[@dalenassar9152]

What happens when you want to talk about LEAD and LAG greater than (or less than) 360 deg?

[@sultanafahimaazhatunnisa5066]

great explanation!

[@1dgaf_]

BushStudies everywhere BTS armys 😂❤️

[@tensoinboba]

Hey army 💜💜💜😂

[@UwU-dx5hu]

thank you so much

[@chittychittis3357]

Thank you

[@moghalsalwar6803]

Thank You Sir.

[@sanghyeonban9989]

Great video!

[@nucleus7896]

Finally, I understand!!!!!

[@serajsersawi5786]

but when we add the graph shifts to the left !!

[@serajsersawi5786]

I mean the function shifts

[@ultimatemayu8017]

think of it this way, we gave sin a ' 'head start' ' of pi/2 in the equation cos (theta)=sin (theta + pi/2) and even after the head start sin does the same thing as cos does which mean sin is slower so it ' 'lags' ' cos

[@dalenassar9152]

Would cos (theta -300) be LAGGING cos(theta) by 300 deg.? Are there any conditions where LEADING COS can NOT be converted to LAGGING COS and vise-versa? Thanks for the great video!!!

[@katsuxrlj]

cos(θ-300°) and cos(θ)? the θ in your statement is the 300. Maybe you meant cos(wt-300°) and cos(wt). If this the case, the waveform was delayed by 300° (kinda looks like it shifted to the right) from the cos(wt).

[@NamaSaya-wg9gn]

How about cos to -sin?

[@nikhilvadapalli126]

-sin leads cos by 90 degrees

[@curtpiazza1688]

😊🎉

[@sharyarsharyar8787]

Name Khan lectures English ma hai

[@UwU-dx5hu]

@@global1903 hahahha

[@brd8764]

Lag, ta,

[@ahmedsaber2914]

Please ..make this videos with translation into Arabic

[@apocalypticbean]

thank you