Fischer to Haworth shortcut for Glucose and Fructose

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Leah4sci MCAT

Күн бұрын

Пікірлер: 48

@fatts96 4 ай бұрын

amazing explanation, u saved me once again!

@Leah4sciMCAT 4 ай бұрын

I'm so happy to hear that!

@ManitJain-i1g 20 күн бұрын

I am preparing for my engineering exams(JEE) and quite helpful !! love from India

@Leah4sciMCAT 19 күн бұрын

I'm glad it's helping you! Best of luck with your exams!

@anirudhsreeram3157 17 күн бұрын

When is ur test bro 🥶

@ManitJain-i1g 15 күн бұрын

29 january

@Leah4sciMCAT 12 күн бұрын

SO close! Rooting for you!

@SucpwBcosbsv 4 ай бұрын

In min 0:52 It isn’t enough to put the last chiral carbon’s alcohol on the left for L-glucose (and other sugars), you have to change all the alcohols to their respective opposite side. If not then you will get a different sugar (an epimer in 2,3,4 of L-glucose, not L-glucose) Same problem for fructose

@Leah4sciMCAT 4 ай бұрын

Oh my goodness you are right. I don't know how I didn't know this for over a decade teaching this. Thank you so much for pointing it out. Mind blown 🤯

@maximilliansaar5512 3 ай бұрын

Perfekt erklärt! Vielen Dank

@Leah4sciMCAT 3 ай бұрын

You're very welcome!

@soumyajitpaul6135 Ай бұрын

I am from India, Thank u sm ❤ for this amazing explanation, I will ace my class 12 board exam

@Leah4sciMCAT Ай бұрын

You're welcome, glad to hear it helped! All the best for your board exams!

@GaverMote 2 ай бұрын

iam from iraq this is in ❤University of Kufa. I searched very hard to find someone talking about this topic. Thank you very much. I feel that I understand the topic a little

@Leah4sciMCAT Ай бұрын

I'm glad I was able to fill that gap for you!

@aysanrasti1058 Ай бұрын

thank you soooo much😍

@Leah4sciMCAT Ай бұрын

You're welcome 😊

@ShikahAlmuharif 5 ай бұрын

This really helps me thank u sm ❤

@Leah4sciMCAT 5 ай бұрын

You're so welcome!

@yaminaboub-jo2lb Ай бұрын

Thank you

@Leah4sciMCAT Ай бұрын

You're welcome

@Leah4sciMCAT Ай бұрын

You're very welcome!

@ursamajor5744 9 ай бұрын

Is it because D-glucose’s hydroxyl groups are in equatorial position, so it is more stable in that conformation?

@Leah4sciMCAT 9 ай бұрын

Exactly 💯

@miladabdolahzadeh8473 2 ай бұрын

I have a question, I'm studying veterinary biochemistry and my professor drew the haworth projection with the first carbon on on the left part of the pyran and the c6 down , is he wrong or this is another way of showing it?

@Leah4sciMCAT Ай бұрын

Molecules can rotate in space. This means that while convention has us drawing it one way, the molecule can also be drawn flipped or upside down. So long as the stereochemistry and connectivity doesn't change, the structure is still correct

@timecode37 2 ай бұрын

Could it be that the first skeletal formula for D-Glucose isn't quite right? My Fischer projection ends up with all the hydroxyl groups on the right side. If you compare it with the picture on wikipedia, the skeletal structures for D-Glucose don't match. When doing the projection starting from the skeletal structure from wikipedia, the fischer projection matches the one in the video. Can someone tell me what i'm doing wrong?

@Leah4sciMCAT Ай бұрын

Yup, I've been teaching this for well over a decade and only JUST learned that I've know and taught this wrong all along!! I will be redoing this video 🤦🤦🤦

@sarahsadatt 10 күн бұрын

Hi, your videos have helped me out so much over the past year! In my lecture, we were taking a look at naming the structure of sucrose and my professor said it is alpha-D-glucose(1-->2)Beta-D-fructose. She said we would need to figure it out on our own but why would the linkage be from 1 to 2 rather than 1 to 5? The way I've become accustomed to numbering is doing it in the clockwise direction. Thanks so much!

@mistyor3754 4 ай бұрын

Hiii teacher , I’m a bit curious about where does the blue OH comes from ?

@Leah4sciMCAT 3 ай бұрын

Great question! The blue oxygen is the aldehyde oxygen in the Fischer projection of glucose. It has been converted into an alcohol group in the Haworth.

@kroliia3116 6 ай бұрын

What happens to the purple “H” that’s attached to the red “O” that attacks?

@Leah4sciMCAT 6 ай бұрын

Good question! The red "O" becomes deprotonated in solution and loses that purple "H". It is no longer a part of the structure when glucose is drawn as a Haworth projection.