Is it because D-glucose’s hydroxyl groups are in equatorial position, so it is more stable in that conformation?
@Leah4sciMCAT3 ай бұрын
Exactly 💯
@kroliia3116Ай бұрын
What happens to the purple “H” that’s attached to the red “O” that attacks?
@Leah4sciMCAT29 күн бұрын
Good question! The red "O" becomes deprotonated in solution and loses that purple "H". It is no longer a part of the structure when glucose is drawn as a Haworth projection.