Fischer to Haworth shortcut for Glucose and Fructose

[@ursamajor5744]

Is it because D-glucose’s hydroxyl groups are in equatorial position, so it is more stable in that conformation?

[@Leah4sciMCAT]

Exactly 💯

[@kroliia3116]

What happens to the purple “H” that’s attached to the red “O” that attacks?

[@Leah4sciMCAT]

Good question! The red "O" becomes deprotonated in solution and loses that purple "H". It is no longer a part of the structure when glucose is drawn as a Haworth projection.