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@NhanNguyen-wu3zp Жыл бұрын
With 2^x=a>0 we have a^3+a^2+a=39 a(a^2+a+1)=3x13 . Check a={3,13}, we have a=3 is one of result. let take (a^3+a^2+a-39)÷(a-3). We have (a-3)(a^2+4a+13)=0 with a>0. 😊😊😊 Then the only result is 2^x=3
@amelgrisssa442211 ай бұрын
il faut mentionner dès le début dans quel ensemble sera la solution.puis vos solutions l'une dans l'ensemble des réels et l'autre dans l'ensemble des imaginaires ce qui n'est pas possible . Désolé.
@stevenjeng123711 ай бұрын
You push students out of math. It is not a good way. 2^x(2^2x+2^x+1)=39 So, 2^x=1 or 3, but 2^x could not 1, so 2^x=3. Take log both side X(log2)=log3 X=(log3)/(log2)
@Fredscorpion28 ай бұрын
t= -12t+13t t= 1000t-999t t= 2t-t t= -7t+t t= -0t+t Why -12t+13t???????????? Why?????? Why not 100t-99t? Why not-15t+16t? Why not 28t-27t??????????? Why 12 and 13????????? Why??????
@hectorsegundoserichevalenc87878 ай бұрын
Muy mala solución Yo lo hice en dos minutos, tanta complicación de usted en este ejercicio matemático 😡😡😡
@mohammadhosseinian59868 ай бұрын
the main problem is how we find out t=3? just by guessing? that is not the way you solve math problems
@musicsubicandcebu1774 Жыл бұрын
2ˣ(1 +2ˣ +2²ˣ) = 3*13 Or RRT applied to t³ + t² + t - 39
@hectorsegundoserichevalenc87878 ай бұрын
Así lo hice Yo ❤
@rajasengannann6311 ай бұрын
By taking log on bothsides 2^X=3 gives X=log 3 to the base 2
@hanswust6972 Жыл бұрын
I loved the last trick: *log a [n] ÷ log b [n] = log a [b]* *Thanks for the class!*
@deadman777010 ай бұрын
that's no a trick that's just one of the formulas of logarithms.
@kevinsolari274411 ай бұрын
Having got to t³+t²+t-39=0 it doesn't take much to see that t=3 is a solution so we must have (t-3)(t² + ?t + 13)=0 Then ewustd coefficients to find?
@YusufEpik-o5r9 ай бұрын
Müthiş
@miracbarsapaydn650 Жыл бұрын
There is no need to go on for so long, the correct answer is log(2)[3]
@is7728 Жыл бұрын
He's just checking the value of x
@peterwallman6269 Жыл бұрын
@@is7728 x is log(2)[3] 🤦♀
@josephmullat25378 ай бұрын
log 2 of 3
@kaushikbasu9707 Жыл бұрын
log3 / log2.
@kaushikbasu9707 Жыл бұрын
log3 / log2
@viktarkrylov560411 ай бұрын
t=2^x >0, по теореме Безу t=3 -корень уравнения t^3+t^2+t-39=0 далее по схеме Горнера находим t^3+t^2+t-39=(t-3)(t^2+4t+13)=0, x=ln3/ln2