Lec 12 Beams III

[@thinkgrow4296]

Thank You sir .. for this great effort.... I was very much comfortable with the the first sign convention from the beginning but after understanding that you are going to follow the second one from now onwards I decided to follow that....

[@surajkakati1140]

Sir, At time stamp 47:31 How come we can know that M+delta(M) and V+delta(V) is as per the direction shown in the example the cut out section of lenght delta(x) If in the above section the direction of M+delta(M) and V+delta(V) is reversed we cannot arrive at the outcome equation Please explain the logic behind the consideration of the direction Regards

[@himanshuyadav4967]

This is also my doubt.. Explain it.

[@MehulMehta-pm1mr]

27:04 problem 1 38:15 problem 2 43:23 Interelation between loading, shear and bending Moment

[@janakamohotti]

Great lecture ❤️

[@AmarSingh-kk3kx]

Sir please do not miss the middle steps and directly right the answers because sometimes getting confused.

[@Inquisite1031]

I don't mean to sound like an asshole, but if u cant do such simple calculations, u need to revise highschool physics textbooks, if they have to repeat highschool level physics/mathematics every time we will never finish the course lol.

[@सागरबड़थ्वाल]

great sir

[@shreytiwari5392]

Okay🙃

[@SAWmoon3111]

Link for lecture 9

[@melvindavis3629]

kzbin.info/www/bejne/m5eQZnuqo6eomLc&feature=emb_logo

[@bhagyeshmadas456]

kzbin.info/www/bejne/m5eQZnuqo6eomLcsi=t16SL7P5QWknsPFR

[@rohanmishra2735]

kzbin.info/www/bejne/m5eQZnuqo6eomLcsi=mlcKFH1ugQRKE5Er

[@guesswho-og2wv]

A conceptual question if someone may answer : How can something called "force per unit length" be a continuous function as shown. Meaning what this function essentially means is for every value of x ; which are essentially discrete points on the x - axis ; there exists a value y, called force per unit length? How is force "per unit length" defined for a point ? I believe it can't be defined for discrete points? Has anyone got an explanation? Please do share 🙏

[@Inquisite1031]

it simply means at distance x from the origin there is a force y, and who said the function representing force on a beam is always continuous ? it can be discontinuous, it can even be discontinuous and not be defined for all values of x.