Lec 16: Dependency preserving decomposition in DBMS | with example | DBMS Tutorials for beginners

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Jenny's Lectures CS IT

Jenny's Lectures CS IT

Күн бұрын

Пікірлер: 132
@koraykara6270
@koraykara6270 4 жыл бұрын
Candidate keys are AE,DE,CE and BE. Prime attributes are A,B,C,D,E So, the relation is 3 NF but not BCNF.
@novicecoder5753
@novicecoder5753 3 жыл бұрын
Same answer brother
@ujithadharshana7397
@ujithadharshana7397 3 жыл бұрын
All keys are prime attributes, so we can blindly say this relation is in 3rd nf
@drumilakhenia4747
@drumilakhenia4747 3 жыл бұрын
@@ujithadharshana7397 but we must check for BCNF , if All keys are prime attributes
@kumarvaibhav7203
@kumarvaibhav7203 3 жыл бұрын
Yeah it should be 3NF.
@adityabikramarandhara9477
@adityabikramarandhara9477 2 жыл бұрын
Same answer
@eddiechen6389
@eddiechen6389 4 жыл бұрын
very detailed and well explained, thats what i call a high quality stuff
@soumyamitra7831
@soumyamitra7831 4 жыл бұрын
The Candidate keys are AE, then BE, then CE, then DE. So, all the attributes in the relation are prime attributes. Hence, it can be said that the relation is in 3NF. We have to check only for BCNF. None of the Functional Dependencies have super keys at its Left Hand Side, so, clearly the relation is not in BCNF. Hence, the highest Normal Form of this relation R(A,B,C,D,E) is 3NF.
@shivampatel8850
@shivampatel8850 2 жыл бұрын
I really appreciate your hardworking towards us , you explained it in very well and convenient manner even I never found such a great video as well as teacher on KZbin and even in my college.
@singanapallibhanu3844
@singanapallibhanu3844 2 жыл бұрын
Thank you Madam...Because of your classes I have cleared my dbms exam
@vijaychoudhary8864
@vijaychoudhary8864 4 жыл бұрын
Very good way of teaching. Keep posting your knowledgable videos as they are helping us a lot. Thanks
@balasubramaniantk4863
@balasubramaniantk4863 4 жыл бұрын
Love your lectures, like lots of your fans, you are my Secret potion of power, Really makes the lectures more easy❤️Thank you sooo much
@nabeelnajeeb8
@nabeelnajeeb8 3 жыл бұрын
simp
@abhishriram9211
@abhishriram9211 4 жыл бұрын
Thank you Soo much for ur lecture's mam ...... 😊Really you are genius mam 👍 .... Aap jaisi lecturer mere clg hona chahiye tha mam
@khushbookumari-so8dt
@khushbookumari-so8dt 4 жыл бұрын
Candidate key are AE, DE, CE, BE and prime attribute are A, B, C, D, E. If all attribute of a relation are in prime attribute then it would be in 3NF. so the highest normal form is 3NF.
@yuzo9331
@yuzo9331 4 жыл бұрын
Your so smart madame I like your lectures and thanks a lot because your videos are very helpful to me👋
@SAURAVVISHNUGITTE
@SAURAVVISHNUGITTE 8 ай бұрын
This time u taught better than Gate Smasher! , he did not cover decomposition neatly .
@shobhitkumarpatkar5468
@shobhitkumarpatkar5468 3 жыл бұрын
Ma'am you teach so naturally that I feels like I am sitting in front of you to learn DBMS.
@reshmateenu
@reshmateenu 4 жыл бұрын
Thank u so much❤️...Really catching the clear ideas behind every topic
@BaskarMCA-ig3ec
@BaskarMCA-ig3ec 3 жыл бұрын
For the Relation R(A, B, C, D, E) and Functional Dependencies are FD = {A->B, B->C, C->D, D->A} the highest normal form in 3NF , and the prime attributes are {A, E, D, C, B}
@adityabikramarandhara9477
@adityabikramarandhara9477 2 жыл бұрын
Same answer
@ALLT-kz5zz
@ALLT-kz5zz 9 ай бұрын
yes
@lakshaykapoor4830
@lakshaykapoor4830 4 жыл бұрын
mam your teaching skills are very good.
@shubhambansal1495
@shubhambansal1495 4 жыл бұрын
Mam you teach very well. So, please apply for data structures in nit delhi.
@swapniltayade1006
@swapniltayade1006 4 жыл бұрын
Mam You teach very well👌👏😍
@piyushkurve457
@piyushkurve457 3 жыл бұрын
How did she wrote/derived the F.D from the table? Can anyone plz tell me in which video she had explained about this because i'm continuous at watching her video from the very first video of this topic. I'm talking about 2:51
@farmygaming9609
@farmygaming9609 2 жыл бұрын
candidate keys are AE,DE,CE,BE and prime attributes are A,E,D,C,B . and highest normal forms is 3NF.
@pankajmohansahu958
@pankajmohansahu958 2 жыл бұрын
Thanks Mam for explaining such a Tough concept in a well Simplified & Clear manner.
@priyankamanna4550
@priyankamanna4550 3 жыл бұрын
Detailed explanation of the topic🔥🔥😀
@srinivasukurapati8778
@srinivasukurapati8778 3 жыл бұрын
Thanks mam😌, your the best
@eagle_shadow6665
@eagle_shadow6665 2 жыл бұрын
Thank you mam for making this video,you are the best 👌😊
@dinkarmehta1445
@dinkarmehta1445 3 жыл бұрын
Really very very helpful lectures
@udayabhi185
@udayabhi185 3 жыл бұрын
Thanku mam . Mam answer is 3NF
@dineshchanwariya9956
@dineshchanwariya9956 Ай бұрын
Very good video for cheching preserv fd thanku mam
@manikanthpalled2274
@manikanthpalled2274 3 жыл бұрын
Excellent teaching mam...!!
@henimehta4927
@henimehta4927 2 жыл бұрын
Awesome explanation mam!!
@priyankapaul7077
@priyankapaul7077 2 жыл бұрын
Ck--》 AE,CE,BE,DE AND PRIME ATTRIBUTES ARE A,B,C,D,E AND THE HIGHEST NORMAL FORM IS 3NF.✅
@heithemdhib4709
@heithemdhib4709 3 жыл бұрын
Thank you for carrying us the 4CHIF!
@peppi44
@peppi44 3 жыл бұрын
ois oke heisem?
@heithemdhib4709
@heithemdhib4709 3 жыл бұрын
@@peppi44 Fühl mich gecarried
@Bickysahoo-vo5ru
@Bickysahoo-vo5ru 6 ай бұрын
i dont have an words to appreciate you🥰🥰🥰🥰
@ShivamKendre-fc3su
@ShivamKendre-fc3su 3 жыл бұрын
Great explanation
@rishikumarvirenkumarmehta9635
@rishikumarvirenkumarmehta9635 3 жыл бұрын
Thank you Ma'am 😊
@momentswithjireh3921
@momentswithjireh3921 2 жыл бұрын
Great lectures mam! I read in a text that a decomposition is dependency preserving if we can compute all FDs without joining R1 and R2, but here it is not possible, we cannot compute D --> A without joining R1 and R2.
@collinseromosele8938
@collinseromosele8938 2 жыл бұрын
the second one is also not Dependency Preserving. Good notice
@AbdulBasit-2003
@AbdulBasit-2003 2 жыл бұрын
Your vedios are excellent with full concept but it is a humble request to make short length vedios as it is quite difficult to watch whole content in exam days
@maitridharmajumder9635
@maitridharmajumder9635 3 жыл бұрын
Ck-AE,BE,CE,DE It is in 3NF
@alrabbi6194
@alrabbi6194 3 жыл бұрын
The Relation is in 1NF.
@anshuraj6455
@anshuraj6455 4 жыл бұрын
You are the best...
@mohsinimam2048
@mohsinimam2048 2 жыл бұрын
Thank you.
@anishjoshi1999
@anishjoshi1999 2 жыл бұрын
Thank you mam
@shivalikagupta3433
@shivalikagupta3433 4 жыл бұрын
Highest normal form is 3NF, because NPA is null , and condition for transitive dependency is NPA->NPA . For 3NF it should not be in transitive dependency.
@productivityaccount8274
@productivityaccount8274 Жыл бұрын
Nice now I can cross check my ans
@mathsview11
@mathsview11 4 жыл бұрын
Thank u ma'am
@milonpaul720
@milonpaul720 3 жыл бұрын
The highest NF is 3NF in the relation .
@junaidahamad3725
@junaidahamad3725 3 жыл бұрын
ma'am please also teach ER diagram with example that topic is very important for interview.
@adharsh7703
@adharsh7703 3 жыл бұрын
should we need to understand all deeper concepts in DBMS??
@khanaurangzeb1789
@khanaurangzeb1789 4 жыл бұрын
Mam how would u divide this realtion
@arbazzaman5090
@arbazzaman5090 4 жыл бұрын
Respect from pakistan
@sarathmaheshk
@sarathmaheshk 9 ай бұрын
luv u vadhinA
@sanchitdeepsingh9663
@sanchitdeepsingh9663 7 ай бұрын
thanks mam
@utube_int2075
@utube_int2075 Жыл бұрын
THanks a lot for the lecture. Suppose I have a dataset that has more than 20 columns. How can I decompose the dataset?
@sowbhagyanagayasamy1782
@sowbhagyanagayasamy1782 3 жыл бұрын
Thank you !
@sureshtech2696
@sureshtech2696 2 жыл бұрын
ck DE,CE,BE,AE .All attribute is prime attribute then direcktly we say this is in 3NF no need to check
@sinirajesh14
@sinirajesh14 4 жыл бұрын
Thanks from kerala🥰
@tiliksew_mulugeta
@tiliksew_mulugeta 4 жыл бұрын
i'from ETHIOPIA...i'm here not to attend this lecture,but because of missing u my love jenny.......lov u forever
@shumayalasabbag2052
@shumayalasabbag2052 9 ай бұрын
Ma'am how did you write F.D.(BC->A ) ....i couldn't understand , Can you plz tell me in which video you explained about this.
@dhwaniupadhyay4727
@dhwaniupadhyay4727 4 жыл бұрын
Mam what is the answer of this question: R(ABCDEG) F:{AB->C , AC->B ,AD->E,B->D,BC->A,E->G} R1(ABC) R2(ABDE) R3(EG) Dependency is preserved or not?
@AmarKumar-vo2bv
@AmarKumar-vo2bv 3 жыл бұрын
yes preserved bro
@shyamsundar-vh9me
@shyamsundar-vh9me 2 жыл бұрын
Yes 👍
@bhargavkartik7476
@bhargavkartik7476 4 жыл бұрын
The highest normal form of R is 3NF.
@govindchavan7689
@govindchavan7689 2 жыл бұрын
Given example answer is Candidate key : AE BE CE DE ITS NOT IN BCNF ITS IN 3NF , 2NF , 1NF HIGEST FORM IS 3NF
@prathmeshsharma7628
@prathmeshsharma7628 4 жыл бұрын
Please make videos on Linux os
@saakib6513
@saakib6513 4 жыл бұрын
Have you ever thought about home tutions??
@worlddream3704
@worlddream3704 3 жыл бұрын
What is that previous video that mam told in this video to derive dependency from given relation.I didn't find that video
@piyushkurve457
@piyushkurve457 3 жыл бұрын
Did you? Bcoz i'm still at search. Plz share it.
@popeyetech9634
@popeyetech9634 2 жыл бұрын
Just checkout the ibutton
@Sgoose105
@Sgoose105 3 жыл бұрын
pretty and teach so well
@arpitmangal4038
@arpitmangal4038 4 жыл бұрын
mam plz make more video on DBMS
@BooHeeee
@BooHeeee 6 ай бұрын
this lady is CRAZY
@anuska8513
@anuska8513 5 ай бұрын
Hello ma'am I have one doubt..Tomorrow have my exam, please solve my doubt. Ma'am for R1 why we are not take (AC) clouser..!?? But at R2 we take (CD) (DE) (CE) clouser... But R1 we only take (AB) clouser and (BC) clouser... If I take (AC) clouser then any problem..!??
@deepankargolait5121
@deepankargolait5121 4 жыл бұрын
Mam please make videos on 4nf 5nf
@sparrow_harsh
@sparrow_harsh 2 жыл бұрын
at 4:52 why didn't you take BC->A and AC->B in functional dependency
@sensen9235
@sensen9235 6 ай бұрын
dude ur outfits are fire
@Santoo2207
@Santoo2207 4 жыл бұрын
It is in 3NF
@kdineshkumar7763
@kdineshkumar7763 Жыл бұрын
Mam why you can't find the AC+ closure
@rohitahuja999
@rohitahuja999 2 жыл бұрын
highets normal form is 3NF.
@engineering5584
@engineering5584 Жыл бұрын
3NF
@SHASHANKRUSTAGII
@SHASHANKRUSTAGII 4 жыл бұрын
Smile❤️
@StevenSteel7
@StevenSteel7 Жыл бұрын
Watch lecture 4 is anyone is confused in deriving functional dep from tables
@KrishnaPandit1999
@KrishnaPandit1999 3 жыл бұрын
3nf is the answer.
@explorer3401
@explorer3401 10 ай бұрын
What are those numbers?
@madhupadayeswanth1865
@madhupadayeswanth1865 Жыл бұрын
3rd nf
@ahsanalikhan5704
@ahsanalikhan5704 4 жыл бұрын
Tabah deya g
@tanushrees1340
@tanushrees1340 4 жыл бұрын
First 😌🤭
@nayanakb3654
@nayanakb3654 3 жыл бұрын
AE, DE, CE, BE ARE CK SO HIGHEST NORMAL FORM IS 3NF
@mylavarapulokesh6472
@mylavarapulokesh6472 4 жыл бұрын
3rd normal form
@dhonisingh4094
@dhonisingh4094 3 жыл бұрын
SQL database video
@FINANCIALYOGI
@FINANCIALYOGI 4 жыл бұрын
R(ABCDE). FD(A-B,B-C,C-D,D-A). CK(as E not determined by any of attributes, AE,BE,CE,DE are CK. All attribute are Prime, therefore in 2NF. As all attributes are Primary, the RHS of SK-PA is PA for deciding 3NF, so R is in 3NF. BCNF requires SK-PA or NPA but none FD HV SK as determinants, not in BCNF. HNF is 3NF. Jesus bless U.
@virendrapatel775
@virendrapatel775 4 жыл бұрын
💛💛💛💛💛
@ravikiran8135
@ravikiran8135 3 жыл бұрын
Mam cutie 💓
@tejassharma3212
@tejassharma3212 2 жыл бұрын
It is 3nf
@sagarchaurasiya1324
@sagarchaurasiya1324 4 жыл бұрын
H.N.F.=>3NF
@bharatletstalk
@bharatletstalk 2 жыл бұрын
😘
@vasilijchenkov8856
@vasilijchenkov8856 3 жыл бұрын
I love you
@abdussamad0347
@abdussamad0347 3 жыл бұрын
Amazing video but you looks like Jerry from Tom and Jerry
@crazydheeru2095
@crazydheeru2095 2 жыл бұрын
nice to listen the class mam mam are u got married
@Rohit_kuhar
@Rohit_kuhar 4 жыл бұрын
Khatri + lamba ? Omg you are married 😣😣😣😣
@saibalam7852
@saibalam7852 3 жыл бұрын
3nf
@vivekpaliwal1876
@vivekpaliwal1876 4 жыл бұрын
mam lgta hai aaj ap nahaaye nhi... ya fir winters me glow kam ho gaya?
@ahsanalikhan5704
@ahsanalikhan5704 4 жыл бұрын
Sedkay
@raghavshukla344
@raghavshukla344 4 жыл бұрын
SPECIAL PLACE IN HELL RESERVED FOR THOSE WHO HAVE DISLIKED THIS VIDEO😡🤬
@sasi.s.sinthu8957
@sasi.s.sinthu8957 4 жыл бұрын
P.A(A,E,C,D,B)... no N.P.A..and the C.K (AE,DE,CE and BE) this relation in a 3rd NF bcoz, if no any N.P.A then definitely that relation it's in a 3rd NF and that left side of FD's not contained any S.K so BCNF is not possible.
@rajneshrana6571
@rajneshrana6571 4 жыл бұрын
😍😍😍😍😍😘😘😘😘😘😘😘😘😘
@4subhashom
@4subhashom 4 жыл бұрын
CK:AE,BE,CE,DE ; Highest NF: BCNF, Please reply
@subhashsandhar2018
@subhashsandhar2018 4 жыл бұрын
No it isn't BCNF bcoz A,B,C,D are not super keys (i.e) they can't determine E.
@nikhilsindiri8497
@nikhilsindiri8497 3 жыл бұрын
Don't promote white hat jr
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