Lec 19: Practice Problem on Lossless Join Decomposition | DBMS Tutorials

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Jenny's Lectures CS IT

Jenny's Lectures CS IT

Күн бұрын

Пікірлер: 66
@chandrashekarr1977
@chandrashekarr1977 5 жыл бұрын
Kudos... For the first time am seeing a lecture in English from North India.. thank you
@bense_tony
@bense_tony 4 жыл бұрын
Just in case if you are confused @20:27. Simple trick said by mam earlier is... C+ = {A,B,C} It has all the attributes of R1(A,B,C) which means, C is a super key. Also, C is a single attribute. So, it is a candidate key, since no proper subsets of C[which are just empty sets] is a super key.
@gulcesafiye9579
@gulcesafiye9579 3 жыл бұрын
You are litterally perfect . I have been struggling to understand this topic ,I have found this playlist and now everything is crystal clear . You are amazing
@ebrimajobe6535
@ebrimajobe6535 4 жыл бұрын
you deserve some credit ma'am. Everything i learned from you is more than explicit. Thanks!!
@rithviksenthil7152
@rithviksenthil7152 2 жыл бұрын
At 14:47 we cannot say AB is a candidate key. A candidate key is a mimimal superkey. So A would be the candidate key. AB is a superkey.
@deepakdobhal4388
@deepakdobhal4388 4 жыл бұрын
The common attribute of both the sub relations must be a super key of either R1 or R2 or both. if someone confuses in SK or CK. Every CK is super key but not all SK is CK. Mam is saying all time CK so plz consider it as SK. bcz in 4th sub-relation AB is not CK. it's SK.
@souravsengupta627
@souravsengupta627 5 жыл бұрын
Plz make a video related to foreign key and primary key and the way of joining the tables.... ASAP.
@impatientoptimist5632
@impatientoptimist5632 5 жыл бұрын
Toppee because of your bloopers 😆😆bcoz i started following you after your blooper😆😆
@nickmorgan2822
@nickmorgan2822 6 ай бұрын
Beautifully explained. thank you. also I love your coat😉
@ganeshrams4246
@ganeshrams4246 3 жыл бұрын
Thank you so much mam,all your videos are very clear and it helps me to prepare gate/net exam very easily, u have saved my time .thanks a lot
@p.bayapureddy6117
@p.bayapureddy6117 5 жыл бұрын
I am in love with your eyebrows
@nishantraj3869
@nishantraj3869 4 жыл бұрын
Love lapati chhod do bro... Sikhlo kuchh , Your perfection will make you glow . Jarurat nhi padegi tumko kisi ko love this that ya wahh krne ki.... After all bro.. pasand to hmm v krte but kya kare she is my online teacher .
@snehasaha2310
@snehasaha2310 7 ай бұрын
you're savior 😇
@Russia_wala_Putin
@Russia_wala_Putin 5 жыл бұрын
Bhai main commerce se hu pr pdh k a6a lg rha hai 😍😍😍
@anshuraj6455
@anshuraj6455 4 жыл бұрын
You are great mam... 📲📲📲📲
@elyasaf755
@elyasaf755 4 жыл бұрын
Very clear. Thank you!
@Attitudeandsigma
@Attitudeandsigma Жыл бұрын
Mam please continue your Valuable videos for gate please mam
@M_Rimi
@M_Rimi 4 жыл бұрын
Thank you mam 😊 you are great 😘
@pavankumar8673
@pavankumar8673 4 жыл бұрын
The definition shouldn't be for candidate key because at 15:27 we have abc and you termed ab as candidate key ,but since a is a superkey, this is not valid. Instead you should change the terms you use, mam
@pavankumar8673
@pavankumar8673 4 жыл бұрын
Instead of candiate key, just term that common attribute must be superkey
@rukaiyadalroti2886
@rukaiyadalroti2886 Жыл бұрын
At 13.55 your are deriving b can derive CDE in which due to at value of b at 1 having different value it can't be derive but if we take 3 in common from (6,3,6)than it can became similar soo can we do it that after removing common divider make it similar or not....?
@RishiRaj-zs4fh
@RishiRaj-zs4fh 4 жыл бұрын
Why aren't you making more videos on other computer science topics as well or on DBMS. At least with your help, we can really increase our knowledge in DBMS.
@Mayurishihz11
@Mayurishihz11 5 жыл бұрын
Thanks for this video
@FINANCIALYOGI
@FINANCIALYOGI 4 жыл бұрын
Is it ok to discard a tuple from a relation formed after decomposing R? Won't it be loss of record. Kindly explain. Thanks.
@pranilthakare
@pranilthakare 2 жыл бұрын
interesting ma'am thank u
@anishjoshi1999
@anishjoshi1999 3 жыл бұрын
love from nepal
@velagabhavyasri6720
@velagabhavyasri6720 7 ай бұрын
Pls do on 4nf, 5nf and Multivalued dependency mam
@rajsarkar
@rajsarkar Жыл бұрын
Why should we remove the second 1 3? . I done it with it and its forming Lossy join where as while i removed it it created lossless join.
@SureshBabu-og4ys
@SureshBabu-og4ys 2 жыл бұрын
Consider the relation R(P, Q, S, T, X, Y, Z, W) with the following functional dependencies. PQ → X; P → YX; Q → Y; Y → ZW Consider the decomposition of the relation R into the constituent relations according to the following two decomposition schemes. D1 : R = [(P, Q, S, T); (P, T, X); (Q, Y); (Y, Z, W)] D2 : R = [(P, Q, S); (T, X); (Q, Y); (Y, Z, W)] Which one of the following options is correct?
@yaswanthb9733
@yaswanthb9733 3 ай бұрын
@@SureshBabu-og4ys first one
@kailashuv3028
@kailashuv3028 4 жыл бұрын
Didi ,can you please make a video about "lpp simplex" method to attain optimal solution....
@shyamprakashm6325
@shyamprakashm6325 4 жыл бұрын
Yes dude each book and videos teach different manner and different solution has arrived😥😥😣😣😣
@Aakash-p7x
@Aakash-p7x Ай бұрын
Take Note : If Common attribute is CK of any one then it's lossless❤
@ahmadabbas1836
@ahmadabbas1836 5 жыл бұрын
I love your eyes looking like carrer post graduate institute of medical science
@SaurabhjiEngineer
@SaurabhjiEngineer 2 жыл бұрын
How AB can be ck,since A subdomain is a superkey? In 4th number ,16 min
@gurjotsingh5924
@gurjotsingh5924 5 жыл бұрын
please add videos on network models and constraints in dbms.
@axelbelkacemi7697
@axelbelkacemi7697 4 жыл бұрын
I think there's a contradiction in the 4th decomposition : you said if A has distinct values then definitely AB determines C, so AB is CK . but A has different values means that it's SK (subset of AB is SK) what means that AB is not CK ... I'm confused , does it mean that its not lossless decomposition?
@kirajan7333
@kirajan7333 4 жыл бұрын
Mam was not talking about CK or SK, she was saying that if A has distinct values then AB combination also distinct values and there is no common rows of AB in table because A is like primary key with no duplicate values so AB will derive C
@deepakdobhal4388
@deepakdobhal4388 4 жыл бұрын
AB is SK so still its lossless decomposition. The common attribute must be a SK.
@arslanamjad2385
@arslanamjad2385 5 жыл бұрын
Make some lectures in urdu mam Some people have poor english like me Reply please about my opinion mam Arslan from pakistan
@nishantraj3869
@nishantraj3869 4 жыл бұрын
Hindi sikhna hai to bolo ... Hmm bataenge
@MegaNivetha
@MegaNivetha 5 жыл бұрын
Madam how to find functional dependency then describe about how to find normalisation.madam please take some questions from gate or net exam and teach it clearly madam
@shashikalaraju5769
@shashikalaraju5769 3 жыл бұрын
Please tell me what's that matrix you've written under Relation. What does it mean?
@shashikalaraju5769
@shashikalaraju5769 3 жыл бұрын
Oh...that's the table. Okay
@Mandeepsingh-jo5cf
@Mandeepsingh-jo5cf 3 жыл бұрын
Thanks mam.
@himavarshareddy4153
@himavarshareddy4153 4 жыл бұрын
Mam can u please make a video on multivalued dependencies
@SHIVAMGUPTA-kl5gk
@SHIVAMGUPTA-kl5gk 5 жыл бұрын
nice explanation mam,but upload more video very soon please
@shubhamchavan7828
@shubhamchavan7828 3 жыл бұрын
make a series on SQL
@nubmidnight8543
@nubmidnight8543 5 жыл бұрын
Mam please make videos on C language ... Please mam
@SaravaniJawahar
@SaravaniJawahar 9 ай бұрын
yes mam
@chetanraj7974
@chetanraj7974 4 жыл бұрын
Hii mam , would you like to have dinner ? Final year student at IIT Kanpur
@shekhar5599
@shekhar5599 4 жыл бұрын
Jantey ho mam...mai yahi soch rha itney padhe likhey larki se sadi karne k liye . . . Kitna padhna parega.... and kash bachpan me mai English movie bina MUTE kiye dekhta to aaj mai puri class me sirf apko dekhta nhi balki sunta v....
@devimadhumitha018
@devimadhumitha018 Жыл бұрын
🎉
@NaveenKumar-os8dv
@NaveenKumar-os8dv 4 ай бұрын
15:32. This is wrong. You must not use this method. We don't do that for checking lossless join if R is divided into 3 or more relations. This is so wrong! I am telling guys. It works only if R is divided in 2 relations R1 and R2. For 3 or more relations, you should use "Chase Algorithm" to check for lossless join. Do some research on your own as well. Don't call any teacher god and praise them. Wrong concept was used here. Shocking that everyone is praising the wrong concept.
@bonsugodfred801
@bonsugodfred801 5 ай бұрын
lecture 20 is missing
@Aakash-p7x
@Aakash-p7x Ай бұрын
No it's just shuffled wrongly
@ritvikdabas2436
@ritvikdabas2436 5 жыл бұрын
Mam plss guide me for dsssb tgt cs plss🙏
@amitjajoo9510
@amitjajoo9510 4 жыл бұрын
Ma'am upload more video
@deepakkumarsaroj5374
@deepakkumarsaroj5374 5 жыл бұрын
I am NEET aspirant but I don't know why I am here during my chemistry class 😎😎शायद ठरक 😜😜
@ahmadabbas1836
@ahmadabbas1836 5 жыл бұрын
Mam ka no. Hai 7392810252
@puspendudebnath2533
@puspendudebnath2533 4 жыл бұрын
uffffff Those eyes 🙈
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