Lecture 14 : Shallow Foundation - Bearing Capacity IV

  Рет қаралды 28,451

IIT Kharagpur July 2018

IIT Kharagpur July 2018

Күн бұрын

Пікірлер: 10
@doghummkad...
@doghummkad... 4 жыл бұрын
Wow... really helps for GATE
@nickveretin4766
@nickveretin4766 3 жыл бұрын
The video sound is pretty good, beyond my imagination
@millupower2875
@millupower2875 3 жыл бұрын
Some segments in the video are stamped not adjacent to each other
@abduljabbarkhan9107
@abduljabbarkhan9107 4 жыл бұрын
When phi =0, cot(phi) in the equation of Nc becomes infinity. Why the value of Nc = 5.7 then?
@aboli_r_shinde
@aboli_r_shinde 4 жыл бұрын
Cozzz....for pure clay Nc = 5.7 (See in Table of phi and factor's of bearing capacity)
@abduljabbarkhan9107
@abduljabbarkhan9107 4 жыл бұрын
@@aboli_r_shinde For normally consolidated pure clay in CD and CU conditions c = 0, not phi.
@abduljabbarkhan9107
@abduljabbarkhan9107 4 жыл бұрын
@@aboli_r_shinde Clay soil does not have phi =0 always. Fora example, a normally consolidated clay will have c = 0 (not phi) under CU and CD conditions. So, if phi is not equal to zero, Nc won't be equal to 5.7 either.
@aboli_r_shinde
@aboli_r_shinde 4 жыл бұрын
@@abduljabbarkhan9107 ok👍🙏
@ashutosharya1161
@ashutosharya1161 3 жыл бұрын
@@abduljabbarkhan9107 for clay phi is always zero as it is perfectly cohesive soil while silty soil is c- phi soil .
@behpeak6837
@behpeak6837 3 жыл бұрын
Some segments in the video are stamped not adjacent to each other
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