Limits of Logarithmic Functions | Calculus

[@TheOrganicChemistryTutor]

Limits - Free Formula Sheet: bit.ly/3T3dD2X Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Math & Science Videos: www.patreon.com/mathsciencetutor/collections Next Video: kzbin.info/www/bejne/bHKXoZWpjch8bpY

[@gaetanoradin694]

I am a retiree, I studied calculus more than 50 years ago, now your lessons serve me as mental gymnastics, bravo

[@goktrenks]

I love your calculus videos,thanks for the work you do

[@georgesadler7830]

MR. Organic Chemistry Tutor, thank you for another excellent video on finding the Limits of Logarithmic/Transcendental Functions using L'hopitals rule.

[@dddddddddd8178]

You should teach teachers how to teach I've finished the limits of function in one day by watching you 🤯 it's unreal

[@Tivnanmath]

A different approach is to recognize this as the definition of a derivative at a point. Then you can deduce that if f(x) = ln(x), then f'(x) = 1/x. So f'(e) = 1/e.

[@budtastic1224]

Nice observation! I always miss seeing stuff like that

[@ruiz_is_sleeping]

thanks for the brilliant idea! i didn't think of that.

[@bezzyahmadi9056]

Thank you so much for your outstanding explanation, really appreciate your works!

[@benma5154]

thank god for organic chemistry tutor.

[@nbdahmd8452]

Thanks for the explanation

[@OlySamRock]

what should I do when the function isnt a fraction? how would i find the limit of square root of x times ln(x)?

[@jimmytorres4181]

You’re a nice person

[@听音乐-o9j]

Wonderful videos which help me so much.

[@anshikamandal2554]

Thank you sir

[@demr5251]

Is it possible to do it without using L'hopital's rule?

[@CRYPTOYT-rf2gj]

Yes

[@kunaalagarwal1924]

isn’t the thumbnail just the alternate definition of the derivative, meaning if you differentiate ln(x) and then plug in e for x?

[@Jose-qy3zr]

Yes

[@odujana1679]

I know this is abit late but please can you do a video solving: lim. ln(2x²+x)-ln(x²-1) X->+♾️

[@antonio-ry9tc]

cool just when i needed this

[@maekkkaaa_]

Hello sir it's 2am here in ph I would like to ask how you calculated it? The minus e in denominator i just dk how to type it in my calculator huhu

[@allmight801]

make video about failur of l'hopital's rule

[@thelastrunamv8488]

rade brate kako si ti meni?

[@allmight801]

@@thelastrunamv8488 fino vala ti? stvarno nisam nikada ocekivao da jos neko sa balkana prati ovaj kananl

[@samiulislamdurjoy]

G 196

[@zulkiflishamsudin7178]

You just like understand me, i was fever exam, hehehewh.. Tq

[@drippybizzle4969]

2nd view , love from 🇮🇳

[@safwaan1240]

y cant u juist up ur voice but i rate ur teaching syll

[@NotJaddy]

turn up the volume...

[@Sully_one]

i have a chemistry question anyone can help?!

[@hydrogendioxide483]

Ask it maybe I could help.

[@Sully_one]

@@hydrogendioxide483 if we have 100ml HBR 0.8M with 25ml Ba(OH)2 0.5M PH=? i can't understand how should i find the answer when i dont have ka, poh,kb or anything else if u can explaint it that would be cool

[@hydrogendioxide483]

Since HBr is a strong acid and Ba(OH)2 is a strong base they both dissociate fully in water and you wouldnt need to know Ka in order to solve the problem.that means that 100 ml HBr 0.8M will result in (0.8×0.1)mole proton and 25ml Ba(OH)2 0.5M will result in (0.025×0.5×2)mole hydroxide which reacts with some of the protons and produces water so the Ph will be -log(the remaining amount of protons) and the remaining amount of protons equals to the concentration of protons produced during HBr dissociation minus the concentration of hydroxide ions resulting from the base dissociation. Hope that could help u

[@Sully_one]

@@hydrogendioxide483 i think i got it but i donno if i do the math right or not can you say what is the final answer that u got?

[@hydrogendioxide483]

The answer is: PH=-LOG((0.8×0.1-2×0.5×0.025)÷0.125)=0.35

[@plassgon9752]

wtf so cool