Sir I don't understand your second step like how would you multiply 2log3(x-1) into it simplest isn't (x-1) the argument of log3 so how is it possible to do so??? please help i'm confused
@NdumbaChimwaka4 ай бұрын
I don't understand sir
@oahuhawaii21414 ай бұрын
He screwed up at 03:37.
@michaelchris-ub6pj2 ай бұрын
Great job
@NshutiEric-q8c Жыл бұрын
Great job 👏👏
@oahuhawaii21414 ай бұрын
He screwed up at 03:37.
@GreyGift-to2gf Жыл бұрын
Genius
@oahuhawaii21414 ай бұрын
He screwed up at 03:37.
@jagadiswarchakraborty2955 ай бұрын
Well done
@oahuhawaii21414 ай бұрын
He screwed up at 03:37.
@nyanyokkon Жыл бұрын
Very great
@oahuhawaii21414 ай бұрын
He screwed up at 03:37.
@PatrickKantnmoya Жыл бұрын
Very interesting
@oahuhawaii21414 ай бұрын
He screwed up at 03:37.
@SimoniKessy4 ай бұрын
Good luck you did it 🫱🫱🧠
@AkbarkhanZawndon9 күн бұрын
Hello how are you dear teacher I have a problem in math
@AkbarkhanZawndon9 күн бұрын
I'm from Afghanistan
@olayinkabalogun2435 ай бұрын
Sir i also don,t also unferstand the second step like how would multiply 21(x-1) into it simplest isn' t ( x-1) the argument of log3 so how is it possible to do so because i did not understand 🙏make me understand sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
@oahuhawaii21414 ай бұрын
He screwed up at 03:37.
@mahlatse10121 күн бұрын
Yeah what he did is not true rather you take the 2 up to be an exponent then use the product rule, it will then create a cubic polynomial, that is what I think but this thing of multiplying with 2 is not true
@sam-y3s7rАй бұрын
Tangent
@GiftNakombe-uw5tqАй бұрын
Sir help me with this. Log(x+2)=Log(x-4) + Log 3 It says solve the equation.😊
@meshackokuomose2067Ай бұрын
Log(x+2)-log(x-4)=log3 Log(x+2)/(x-4)base 10=log3 base 10 Base 10 cancel out, Left with x+2/x-4 = 3 Cross multiply 3(x-4) = x+2 2x=14 x=7