2*x + 1 = 9*(3*x - 1), x > 1/3 10 = 25*x x = 2/5 = 0.4
@oahuhawaii21412 ай бұрын
Dude, you failed math at 03:00. In general, log(a) - log(b) ≠ log(a)/log(b) . Discard that line, and continue with log(a) - log(b) = log(a/b) . This is the 2nd video in which you failed miserably.
@adgf1xАй бұрын
=>2x+1/(3x-1)=9=>27x-9=2x+1=>25x=10=>x=10/25=0.4 ans
@BenjaminYai6 ай бұрын
Why does the positive sign changes to negative
@CatherineZulu-bd3rp Жыл бұрын
What is this topic??
@PhocasNamasengesho3 ай бұрын
Correction examination for 2024
@adgf1xАй бұрын
why repeat same line?
@abioyebolanle79119 ай бұрын
Pls sir slove loga 27+ logb 4 = 5
@GraceNyarobi3 ай бұрын
Ans 5
@oahuhawaii21412 ай бұрын
Using the base conversion rule, we have: log(27)/log(a) + log(4)/log(b) = 5; a, b > 0; a, b ≠ 1 log(3³)/log(a) + log(2²)/log(b) = 5 3*log(3)/log(a) + 2*log(2)/log(b) = 5 There's an infinite number of solutions. An obvious integer solution is a = 3, b = 2. But I can find many others, such as: a = 1/3, b = ⁴√2 a = √3, b = 1/4; a = 27, b = √2; b = 4, a = ⁴√27; ... If a = b, we have log(27*4) = log(a⁵), or a = b = ⁵√108 .