M20 1 Simplifying Rational Expressions Lesson

[@RobSteel117]

at 34:18 I was struggling trying to simplify the (2r^2+1) in the numerator. I always work the problems before you explain them. I couldn't factor it and gave up. I was thinking that any 2nd order binomial should be something I could simplify. Apparently that is a false assumption? then I realized that would only be if the entire binomial was square, or was a difference of squares.

[@valeriem63]

In question "h)" at 42:45 when taking out what's common in the denominator it would be 7x^2(3x^2+2x) not 7x^2(3x^2+2). If im not mistaken the real answer would be x^2-5/3x^2+2x , x ≠ 0, √ -⅔. the √ -⅔ is not a real number though.

[@JeremyKlassenThePiMan]

Argh!!!! You are correct. Good catch!!! I hate when that happens!

[@shouta8853]

For h) in the simplifying rational expressions examples wouldn’t you factor out 7x^3 instead of x^2 since the lowest degree is x^3 in the denominator? And that the NPVs would be 0 and -2/3? And the coefficient for the denominator be just 7x?

[@agaggleofgeeese]

yep, he made a boo-boo