Carbon13 NMR - Two worked examples

[@emcha6235]

So glad I found this right before my exam. Spent the whole year trying to learn this. Took you like 10 minutes! 👌🏻 Love these videos!

[@MaChemGuy]

Thanks! Glad you like them :) GOOD LUCK!!

[@margaretsekinobe2428]

Thank you I have always dreaded teaching this section I will teach this tonight with confidence! Thank u!

[@leoniemcauleyshean4161]

Thank you very much for this playlist. I am doing A Level chemistry and I was struggling to understand spectroscopy in lessons but after watching these videos I was able to get an A in an assessment point! These videos were really helpful at explaining the Chemistry. I find the topic a lot more engaging and interesting now.

[@MaChemGuy]

Leonie McAuley Shean That's great to hear. Thanks for getting in touch, it means a lot. Well done on your A and good luck for the summer exams. :)

[@erfanm1425]

Great video Sir !!!

[@mashaaln8764]

@machemguy Please respond need your help!! 5:35 should there not be two peaks at 120ppm? You have two different carbon environments that possess a C=C bond (orange and green). I know you've done the orange carbon environments as C-O but would you not include them in C=C (120ppm) as well?

[@MaChemGuy]

Environment classed as C-O due to greater impact on electron density around nucleus due to higher electronegative O atom

[@connorstokes8284]

Love the videos, they really do help. Are you going to do videos based on singlets, doublets, triplets, etc on C-13 NMR as well as videos based on H-1 NRM?

[@hannahbee9992]

Could I ask why at 3:59 that little orange group differs from the green ones?

[@MaChemGuy]

Hannah Bee The green ones are 2 C's away from the OH group. The orange one is 3 C's away so different. Make sense?

[@hannahbee9992]

I think so. Thank you for getting back to me so quickly

[@uhidk18]

Why does the phenol have 4 environment how is the last one different

[@MaChemGuy]

How many do you think it has?

[@uhidk18]

@@MaChemGuy Nevermind I understand it now, it gets so confusing sometimes. I'm sitting for the Edexcel international A level and chemistry unit 5 is absolute nightmare.

[@sea5205]

Great video, thanks a lot!

[@shona3180]

I don't' understand the aromatic carbon environments, how did you get 4 and 2?

[@WiShInGdRaGoN1324]

I found that it helps to draw out the structures and observe the internal planes of symmetry. The left phenol molecule has 1, whereas the right hydroquinone molecule has 2

[@chemistrylearner2096]

amazing explanation

[@gilong1311]

Hello, was wondering if you could help me understand C NMR more. I am looking at a Carbon NMR spectrum that have peaks with the labels: s,d,t,q? I assume they stand for singlet, doublet etc. but how would those labels help me determine the carbon bonding?

[@mintyasmr3052]

Hey sir, you know at 4:40, why are all 4 carbons in the same environment. ( the one where you put 4 green dots ). I thought if they are in the same row in a benzene they’re in the same environment, so I got 3 peaks instead of 2 peaks. 😅😅

[@MaChemGuy]

The presence of the lower OH group introduces another line of symmetry making the 4 C atoms equivalent

[@sabinahasanova7198]

Genius!

[@fkazi123]

For your C-OH peaks in the benzene rings, wouldn't they the furthest downfield because they are also in the benzene ring. This is referring to your last worked example

[@MaChemGuy]

Probably but remember that this is only A level and as such the exam board use a much simplified data sheet. You have to go on the values given on that

[@markusgermann7433]

Yes they are they are aromatic as well.

[@smugcat723]

do you happen to have a copy of that paper?

[@TheAyad64]

Sorry sir, I think you located the the peaks in an incorrect positions, the chemical shifts as follows: 1. the C-o at 155 ppm 2. the blue carbons at 115.48 ppm 3. the green carbons at 129.79 ppm and the orange carbon at 121 ppm, so the C-OH has the larger chemical shift. Thank you

[@MichlBro]

[@leebautistor938]

how can i find that paper?

[@zannatul23]

sir, are u required to draw the spectrrum?