another way to eliminate complexity is: x^4 - 2x^2 +1 - 2x^3 + 2x - 0 ( x^2 - 1 )^2 - 2x ( x^2 - 1 ) = 0 ( x^2 - 1 ). ( x^2 - 2x - 1 ) = 0 x^2 - 1 = 0 ==> x = ± 1 or ( x^2 - 2x - 1 ) = 0 x = 1 ± √2
@DaneBrookeАй бұрын
I watched a vid; when it ended it made several suggestions, I chose this one. On the suggestion-screen was a slightly different problem than you are solving here. I think you should update the suggestion screen to make it match.