There is a problem with this. When you are solving an equation, you must not just divide both sides by an expression involving x, because by doing so, you lose solutions. What he should have done is move everything to one side and factorise to give x^2(x^2-1)(x^4+x^2-8)=0 which gives potential solutions as x=0, 1, -1 aswell as as his solutions. We then exclude 0,1 -1 as solutions as when we substitute them into the original expression we get 0/0 which is undefined.. So we end up with just his solution, but his method would lose about half the marks.
@ramesankd1604Ай бұрын
Okey
@ДмитрийЗенков-х7о22 күн бұрын
А как же х в степени 8 должно иметь 8 корней?
@ДмитрийЗенков-х7о22 күн бұрын
В заставке одно уравнение, а по факту решается другое 😂
@AmédéeGerestАй бұрын
Ah you announced another fraction in the beginning :: But it is easier with x^4 - x^2 😉