Math Olympiad:Which is Greater? Can You Solve It?

Math Olympiad:Which is Greater? Can You Solve It?‎‪@AyaansMath‬
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Math Olympiad : A Nice Algebra Olympiad Problem ‎@AyaansMath #olympiad #algebra #math #matholympiad #mathematics#olympiadalgebra #olympiadmathproblems #olympiadmathematicscompetition #olympiadmathematics #olympiad_maths #olympiad
Math Olympiad : A Nice Algebra Olympiad Problem @AyaansMath
Math Olympiad:A Nice Olympiad Algebra Problem@AyaansMath
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Math Olympiad :A Unique Algebra Problem ‎@AyaansMath
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Math olympiad:Solving Pair of Equations@AyaansMath
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Math Olympiad:A Nice Olympiad Algebra Problem@AyaansMath
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Dive into the intriguing world of Math Olympiad with @AyaansMath In this video, we tackle a captivating Olympiad Algebra problem, unraveling its intricacies step by step. From elegant equations to clever solutions, join us on a journey of mathematical discovery. Explore techniques, strategies, and insights crucial for mastering algebraic challenges in Olympiad competitions. Whether you're a budding mathematician or an Olympiad enthusiast, this video offers valuable insights to sharpen your problem-solving skills. Don't miss out on this enriching mathematical experience! Subscribe to AyaansMath for more Olympiad math adventures.
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[@backgammonmaster]

Dear teacher ,@ 3:10 it is very clear that a is smaller than b . Because BOTH numerators are the same that is 3 but the denominator of a is manifestly greater than b. therefore a is smaller than b. No more actions is needed. Thank you.

[@umisora2707]

This proof sux. There is a more elegant one: Given that x^2 - y^2 = (x+y)*(x-y), 1 = 21 - 20 = [sqrt (21) + sqrt (20)]*[sqrt (21) - sqrt (20)], using same logic we get 1=[sqrt (18) + sqrt (17)]*[sqrt (18) - sqrt (17)]. Rewrite this into: [sqrt (21) + sqrt (20)]*[sqrt (21) - sqrt (20)] =[sqrt (18) + sqrt (17)]*[sqrt (18) - sqrt (17)], or a*b = c*d. Since a>c obviously, b must be less than d.

[@AyaansMath]

thank u superb