Maths 2 Quiz 1 PYQ | Previous Year Paper Solution quiz 1 Maths 2 | M2 PYQ Quiz 1 solution

[@afadingbreath8627]

😍👌

[@chandralekab.s3810]

16:23 only z depends so isnt it 2 dimensions

[@priyanshushankar2016]

I think it must be that x and y depends on z so independent vector is z so the dimension is 1

[@roadtoiit4940]

@@priyanshushankar2016 wse to doth are depended to each other. I don't get the solutions to this type of questions

[@AARONJACOBTHOMAS]

how did you get the intersection of W1 and W2 as {x , 0 , x} and union of W1 and W2 as {x , y , x-2y}??

[@sahilkochar5121]

In question 5, Det(A) is (a/2 )* (a/2) - (-a/2)* (a/2) which equals a²/2

[@Myowncampus]

I don't what u saying but it should be a^2/4 not by 2

[@Chad-be3jm]

In q5 you found the determinant of A = -2 (should have been 2)

[@chandralekab.s3810]

then is 2nd option crt

[@xytan3502]

Thnku

[@priyankachahal-c4g]

In question 3 why can't the (1,1) is the zero vector because see according to given addition and subtraction if we take (1,1) + (1,2) = (1,2) so v + 0 = v

[@Myowncampus]

That will be 0,0 not 1,2

[@Chad-be3jm]

yeah this is exactly what i was thinking

[@Chad-be3jm]

In question 3 why can't the (1,1) is the zero vector because see according to given addition and subtraction if we take (1,1) + (1,2) = (1,2) so v + 0 = v ?

[@xytan3502]

I added a cmnt but smjh aa gya meko

[@Myowncampus]

X^2 = -Y^2, square term can't be negative. So I can't be independent. As for x^2 + y^2 to be zero, both needed, think x=0 and y =0, x solely 0 can make equation zero. I hope you got it Btw i appreciate you for asking this question, i tried to answer most of the question but this question left there

[@Myowncampus]

Yeah i read that comment and was replying that

[@xytan3502]

Yeh I got it by myself so deleted.. Thnku bro🫶🫶

[@xytan3502]

@@Myowncampus Pls upload the pdf (with annotations) of both classes.. pls

[@Myowncampus]

@@xytan3502 check discription, i have provided link for both