Binnet's 2nd integral formula

  Рет қаралды 5,488

Maths 505

Maths 505

Күн бұрын

THAT monster integral: • An absolute MONSTER of...
Cot(z) series:
• That's right, an infin...
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Пікірлер: 34
@nightmareintegral5593
@nightmareintegral5593 Ай бұрын
Flammable math was first with this integral. He had so much passion then. Now he almost gone 😢.
@maths_505
@maths_505 Ай бұрын
@@nightmareintegral5593 why am I not surprised that flammy solved this before me 😂 jokes aside it's probably down to work and priorities.
@yoav613
@yoav613 Ай бұрын
@@maths_505 yes,in that time i think he was a student,now he is a teacher and doing other stuff..
@ShanBojack
@ShanBojack 18 күн бұрын
I also miss papa flammy, haven't been following his channel. What happened to him?
@leroyzack265
@leroyzack265 Ай бұрын
Bro you literally breath integration. For me you're the person that has mastered it the most.
@CM63_France
@CM63_France Ай бұрын
Hi, "terribly sorry about that" : 2:06 , 2:40 , 4:06 , 5:51 , 6:36 , 8:07 , 8:57 , 12:45 , 15:24 , "ok, cool" : 2:16 , 2:53 , 3:23 , 5:14 , 6:10 .
@JXS63J
@JXS63J Ай бұрын
THe "terribly sorry.." is too distracting. Learn to write. Really!
@ShanBojack
@ShanBojack 18 күн бұрын
Bro only has one job
@aravindchallenger3116
@aravindchallenger3116 Ай бұрын
Yo bro U setted and built uped the previous integral im such a way that this integral solution development feels like a climax plot of a movie 😂
@smallyberbigelbe7571
@smallyberbigelbe7571 Ай бұрын
Thank you for reminding me of math I once knew. Still just as beautiful as the day I learned it.
@leroyzack265
@leroyzack265 Ай бұрын
I really enjoyed the wild ride and I'm happy for learning new things.
@MrWael1970
@MrWael1970 Ай бұрын
Fruitful result. Thank you
@IsomorphicToIntingersAdjoin_i
@IsomorphicToIntingersAdjoin_i Ай бұрын
Beautiful result , i hope for more videos .
@MrFtriana
@MrFtriana Ай бұрын
The result reminds me of the Stirling formula, an asymptotic series expansion for the Gamma function
@lokeshraybarman7007
@lokeshraybarman7007 Ай бұрын
Beautiful explanation ❤❤❤ can you pls take up more ramanujan like integrals and explain ❤❤❤❤
@yoav613
@yoav613 Ай бұрын
Nice!! This looks like the binet's formula for log gamma,cool way to derive it😊💯💯💯
@maths_505
@maths_505 Ай бұрын
Yeah this was fun
@yoav613
@yoav613 Ай бұрын
@@maths_505 yes!
@Mario_Altare
@Mario_Altare Ай бұрын
Waiting for/looking forward to Binnet's 1st integral formula 🙂
@Aplicapitagoras
@Aplicapitagoras Ай бұрын
The power of the laplace transform😵‍💫
@MrFtriana
@MrFtriana Ай бұрын
Laplace transforms are very powerful, yet sometimes looks like are very underappreciated.
@AliAujla92
@AliAujla92 Ай бұрын
Wow! This integral is pretty hard.
@maths_505
@maths_505 Ай бұрын
How's it going my friend?
@aliaujla-2ujt
@aliaujla-2ujt Ай бұрын
Watching my broo math505 only, and it's going well, hard, and okay, cool😂😂
@aliaujla-2ujt
@aliaujla-2ujt Ай бұрын
​@Ebru659, if you want to solve it by yourself, there is a book named "Table of Integrals, Series and Products" by Losif M. Ryžik. The book has answers to every integral where you have to find the solutions by yourself. Otherwise, @michealpenn @blackpenredpen @mathsflammable @drpeyam are very amazing. But believe me this channel is way ahead than any other calculus channel!
@maths_505
@maths_505 Ай бұрын
@@Ebru659 math stack exchange and anywhere else you can find them on the internet.
@МуратВахитов-п8ф
@МуратВахитов-п8ф Ай бұрын
Why is 15:50 true?
@giuseppemalaguti435
@giuseppemalaguti435 Ай бұрын
I=(1/2π)Σ((-1)^n/(2πz)^2n)Γ(2n+1)ξ(2n+1)...mah
@ShanBojack
@ShanBojack 18 күн бұрын
I don't understand what you say in the intro of the videos can you write it here 'my _______ folks'?
@maths_505
@maths_505 18 күн бұрын
@@ShanBojack mae govannen
@cdkw2
@cdkw2 Ай бұрын
pretty!
@aadi.-.
@aadi.-. Ай бұрын
great to see you here too haha
@mau9639
@mau9639 Ай бұрын
Hai
@maths_505
@maths_505 Ай бұрын
Bit more than that😂
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