17 - Calculating Vector Components in Physics, Part 1 (Component form of a Vector)

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For my reference :) 17:14 two dimensional needs 2 numbers Same goes for 3D needs 3 numbers

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A car travels at 20km due north and 35km in the direction 60° west of north.find the magnitude and direction of the car's resultant vector

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[@ernestschoenmakers8181]

There's a mistake, if you say vector d = 10 m then that's wrong, a vector is not a number. So vector d should be 10 m*r(hat) where r(hat) = i(hat)*cos(theta) + j(hat)*sin(theta).

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[@phoenix13574]

Thank you for this video but at 25:11 you comment on how we should be thinking in our minds that SINE will chop for the vertical component and COSINE will chop for the horizontal component. I found this is not true for triangles like yours that are rotated 90 degrees and therefore the COSINE and SINE values are opposite. Instead wouldn't it be best to associate it with the following below? Your scenario will not always be true otherwise. Depending on the orientation of the triangle the Opposite Side and Adjacent Side values can either be Dₓ or Dᵧ. |D|cos(

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[@kojo1114]

might be confusing for some if you write out fx +fy= f as if the vectors were parallel and equal so they would just add the numbers out

[@sheritriacottman5089]

What are the steps when you aren’t dealing with a right triangle? The resultant vector in the problem I’m working through isn’t oriented head to tail and the angle isn’t starting straight from the x-axis. I’m like two seconds away from withdrawing from my physics course.

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the vector means a direction right but , why do we need two numbers to calculate a single direction ?

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Stupid question - if in 2D case alpha +beta = 90deg, how is in 3D case? is alpha+beta+gamma = 180deg always?

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