Mechanical Engineering: Particle Equilibrium (18 of 19) Determining Angles & Tension in 3-Dimension

[@malachite072]

Are you Dutch? It looked like you wanted to say 5 and 80 lol 7:25 awesome video btw

[@MichelvanBiezen]

I was born and raised in Belgium and speak Flemish. (My dutch is a bit rusty).

[@malachite072]

@@MichelvanBiezen Oh ok cool. Similar story here, I was born in Belgium but grew up in America.

[@リアキエロン]

Thanks! This helps a lot...

[@elprimo4727]

What is L?

[@MichelvanBiezen]

L is the length of the cable on the left. (The equation shows how to calculate its length).

[@ptyptypty3]

Hi Michel..... Happy SUMMER to you.... I'm enjoying your latest videos... thank you for all of them... These videos on Mechanical Engineering are Astounding. As usual you've taken complex concepts and revealed them to be Easy to understand when PRESENTED in the Right way.... that's your style.. In regards to this Video Lecture... I was wondering if the Tension in the Other TWO CABLES could be derived simply from the Values you've determined for the 10,000 Newton Cable?... I'm wondering if using the concepts of Equilibrium would apply, that is.. using sum of X forces equaling ZERO, sum of Y forces equaling Zero, etc.... By the way, I've either read about Direction Cosines or Saw videos on them... and Never have I gotten such a complete picture of them before. Your videos continue to achieve at the highest level... Thanks again.....

[@MichelvanBiezen]

Philip Y Hi Philip. Good to hear from you and thanks for the kind words. Yes, the basic principles of the sum of the forces in the three directions can be used to find the tensions in the other cables. (I skipped the other cables because I wanted to keep the video short enough) I am definitely having fun with mechanical engineering. Too bad I don't have more time.......

[@josericardoxavier_]

you have to find the sum of all forces in each direction (X, y and z) and then you will get a system of equations ( including the weight of the tower) from wich you can find the other variables by a variety of methods

[@kestergascoyne6924]

Wow. This is so cool.

[@KAMusical]

May Jesus Christ bless you Mr van biezen, YOU deserve the blessings cos you're always ready to deliver.to God's people, may your wisdom increase every time you do that, and may the grace of God be with you all your life.

[@MichelvanBiezen]

Thank you.

[@aktersalma279]

Thq u sir

[@leob6094]

Hi, I like your video, you explain it very well, but there is an issue. I noticed that you made a little mistake, the Z component of the Total Force is negative, and the "Theta Z" angle is not 76.2° , is 103.8177°, if you use the formula: Cos^2 θx + Cos^2 θy + Cos^2 θz = 1, and you clear θz, in order to find it, taking into consideration that Fz

[@adem8353]

Leo B I think also as you thought

[@rohityadavade5528]

I know it has been 5 years, but you got it correct. The angle he got was wrt -Z axis

[@karimkhan1312]

THIS IS EXTRA ORDINARY

[@doganerdoganer6460]

it was difficult