Mesh Analysis Example-Everything Part 1

[@joeten4817]

its great that you cover the harder and more complicated examples unlike other youtubers. thanks heaps!

[@Wolverine8141]

You are the best teacher I have encountered online

[@revoltemusic1448]

Mr. Morrell if you come to Bulgaria don't hesitate to write to me I have some beers to give you because of the help !!! (: Thank you very much.

[@SmoothChino]

can I come for beer

[@jrassa04]

Thanks. You have helped me quite a bit this semester. I will be sure and put you in my acknowledgements on the last page of my final.

[@KyleP133]

Thank you for taking the time to put this online.

[@ProXyFullBack]

I loved the humorous depression in your tone of voice

[@essamgouda1609]

adjust the video speed to 1.5x if you don't want to sleep while studying.

[@yanks477]

life saver

[@alyaa7273]

I just did

[@ayazmir2931]

thanks dude....u just saved my semester

[@auroracoco7650]

thank u

[@joevasquez7766]

At 9:25, how do we know that the current through the 30 ohm resistor is I3 - I1 instead of I1 - I3?

[@nandemonai__]

Sir, I've noticed something wrong in your last equation. It must be i1(-40-20) + 40i4 = 80, am I right?

[@harshitkumar9708]

Yes you are

[@vmsikrsnah]

I had the same doubt too

[@navineshjeyavirancaunder5757]

Yah I also have the same doubt sir.

[@satyamverma05]

Yes you are right

[@mydadsamilf]

good lookin dawg helpin me ace me circuit analysis midterm ~ good examples

[@ronaldjorgensen6839]

GREAT DARYL THANKS FOR YOUR TIME UNTIL YOUR BETTER PAID

[@Aphroditeandtea]

Sr there is an error in your supermesh simplification. Shouldnt it be I1(-5-30?? And the part where vc=-50I1 and substituted in I1(.4x-50)-40??

[@shreniksparrow552]

These professors are Evil. E.V.I.L. Professors 😛😜 Thanks tons for the help! Amazing job you are doing here!

[@leonardo84]

this method is so complicated, it's very easy to make a mistake and screw up the whole analysis. And i didnt understood why did you change the voltage sign over the resistors, took me a while to catch up... I know it makes no difference if you do this in a entire mesh since the sum is always zero, but i find easier to keep the minus sign on resistor, just because we are adding up "drops". Thanks fou you video!

[@somendutta182]

Love from Bangladesh....great job

[@avinashchowdhury2533]

In 7:28 sec how do know VB=i1-i4, why we can't write i4-i1

[@DarrylMorrell]

Thanks for catching this. I have added an annotation to correct it.

[@thejdhingra]

at 11:47, shouldn't it be i1 = (-5-30)?

[@DarrylMorrell]

If the source between Mesh 2 and Mesh 3 were a voltage source, we would just add or subtract its voltage when going around the two meshes. If it were an independent current source, the analysis would be the same as in the video except that the difference I3 - I2 would be the value of the current source and not .01VB

[@mariakas13]

what confuses me is that there are 2 different signs at each both ends of the resistor

[@ilanpo45]

At 13:54 it should be -40 ohms, thanks for the videos.

[@1415J]

Is it possible to perform nodal analysis of this circuit.What would be the current of the 50 ohm top resistor which will flow into or out of the first node from left?

[@coleblezzy9755]

at 13:30 shouldnt Vc = positive 50 ohms? why is it negative if we are going from positive to negative?

[@BlaKKoutGT]

Going from positive to negative is a DROP across the resistor, making it negative.

[@NJLStudios1]

my favorite remarks: 0:11 11:24 11:33 (ROASTED OUR INCOMPETENT ASSES)

[@bernardcheong683]

for your Vc i thought the polarity is alreadygiven - to + , but why you can change it ?

[@saaketh]

At 13:55 in the equation at the bottom, it says 40(i4-i1), but at 7:18 it says Vb = 40(i1-i4). Can you please explain this? Thanks!

[@mariakas13]

could u explain why at 12:50 u get Vc= -50 rather than +50? How do u determine the sign? I thought if u have the voltage raise u get minus sign, and if you use the clockwise direction on the 1st mesh u get a voltage drop...

[@joshuaabraham9297]

Same doubt

[@BicycleFunk]

I sub A is the same as a mesh current, I sub 1? I thought there were different currents between every node, so wouldn't I sub A just be a part of I sub 1? Thanks

[@saaketh]

Also, if in the place of the 5Ia dependent source, if there had been a current source, how would I write the supermesh equation? Thanks again!

[@Burpeekanksss]

i loved your tutoring

[@drussell7419]

Overall this was a great problem and solved elegantly. I do have one issue. I'm not comfortabel with the *seemingly" random switching of voltage across resistors. In some instances you obay the polarity of the resisitors, in other cases you switch them to suit you needs. For example, you swithced polarity at the the 50 ohm resistor to be +, then - then + again. you dis the same thin thru the 20 ohm resistor. I f I try to do the same thing during a test, it would screw me up keeping track

[@markethunter888]

why do you switch the polarity at the devices? Thanks

[@syedmuntazirmehdi574]

Its the way to find current Plz upload the probelem to solve for particular voltage

[@oscarr4570]

When he goes around Vc why is it negative, every time he goes around other resistors or voltage sources he always takes the first sign that appears as he is going through that loop.? why does he change it for Vc?? PLss heaalp

[@shivpalpatine]

+Oscar R A comment below by "Jimmy R" answered the question. he said " i1 is traveling clockwise around mesh 1, and when mesh current 1 enters the resistor, Vc is the opposite polarity of the voltage drop that would be seen from I1 dropping across the resistor. Therefor, the voltage drop is (-I1)*50 Ohms. It's all about the polarity of the voltage drop with respect to the direction he defined of the mesh current"

[@ibrahimelkhayyat7982]

I never got how do we choose the positive and negative terminals of the resistors. Can somebody tell me how?

[@eivindstraume1429]

what program are you using?

[@guillaume6373]

Amazing, thank you

[@manjunathsastry7540]

dude, while writing supermesh eqn., how can u plug in 5A directly into KVL?! u need to multiply it with resistance of the current source ...

[@GODANIALazuha]

i think it is voltagr dependant source, that why they can directly plug into the kvl

[@БекзатГабидуллин]

Thank you my broo!!!

[@spandannautiyal4230]

sir in step 2 you wrote 40 ohms(I1-I4) but why didn't you take the 30 ohm resistor on mesh 3 into consideration?? please any user who can help me??

[@jimmyr6265]

+Spandan Nautiyal Step 2 was determining the current flowing through the dependent current source, which can be defined by (I2-I3). Since this current source is only dependent on Vb, we only have to worry about this voltage. Looking at where Vb is defined, we see it's only the voltage drop across a resistor, which from Ohm's law is just the current flowing through the resistor times its resistance. Looking at the mesh currents, we see that the only currents flowing through this resistor are I1 and I4, flowing in opposite directions, so those are the only ones we need to use to determine the Vb voltage drop.

[@spandannautiyal4230]

+Jimmy R thank you so much... very helpful..

[@RozArialind]

why is the Vc = -50 ohms? I can see where... but why did it become negative?

[@jimmyr6265]

+Rozalind Aria I 1 is traveling clockwise around mesh 1, and when mesh current 1 enters the resistor, Vc is the opposite polarity of the voltage drop that would be seen from I1 dropping across the resistor. Therefor, the voltage drop is (-I1)*50 Ohms. It's all about the polarity of the voltage drop with respect to the direction he defined of the mesh current

[@shivpalpatine]

+Jimmy R thanks

[@fakruddinpathan4261]

I want to ask a question

[@pemsilsaring5307]

sir why i3-i2=.1Vb. why not 0.1vb=i2-i3, Iam having confusion on this, some1 pls explain

[@zynthos9]

Are you Sal from Kahn Academy?

[@1001godknows]

on the first equation.. why is it I1-I3 ? not I3-I1? please answer asap .

[@heidischultz1404]

+Vincent Fernandez From the perspective of the I1 loop, I1 is always positive. I3 is going through the 30 ohm resistor in the opposite direction, so it is negative.

[@1001godknows]

thanks . :)

[@anigam91]

HI THERE QUICK QUESTION; AT 6:28 IS IT EQUALLY VALID TO SAY: I_2 - I_3 = .01V_B IF NOT, CAN YOU PLEASE EXPLAIN WHY AND HOW YOU KNEW TO DO IT THIS WAY, THANK YOU!

[@StannyMrKee]

That's the same question i have here😢...tell me if you find a solution please

[@olaayman1900]

thank you

[@LajuJ]

How is I3-I2=0.01Vb? Isn't it meant to be I3+0.01Vb=I2? Please if anyone can respond asap that'll be really helpful

[@SHeeDeED]

all i wanted to know what is Vc = to and i got. thanx

[@amarjeetsingh5414]

bahut aacha

[@vault587]

I guess my professor is an evil professor.

[@mannerlykracker]

this could have been a 2 minute video

[@FrancescoMarrato]

on 2X speed and u still speak slow

[@bignnake_family]

what does he mean "every mesh current shows up"? kzbin.info/www/bejne/rqXRd3yjja6lgbM

[@shivpalpatine]

+chinonso nnake He is talking about he Blue equation. He is saying that the blue equation relates every mesh current (i1, i2, i3, i4) all into one equation. He is saying it is rare for one equation to include all the mesh currents into 1 equation because professors try to make your life as hard as possible. If you notice, all the other equations he derives relate max of 3 mesh currents.

[@shinycharizards]

Why do you sound depressed? :(